• Stainless Steel Vertical Multi-stage Centrifugal Pump System 1
Stainless Steel Vertical Multi-stage Centrifugal Pump

Stainless Steel Vertical Multi-stage Centrifugal Pump

Ref Price:
get latest price
Loading Port:
China Main Port
Payment Terms:
TT OR LC
Min Order Qty:
-
Supply Capability:
-

Add to My Favorites

Follow us:


OKorder Service Pledge

Quality Product, Order Online Tracking, Timely Delivery

OKorder Financial Service

Credit Rating, Credit Services, Credit Purchasing

Application: SMV. SMVN is a kind of non-self-priming vertical multiple-step centrifugal pump. The whole pump is composed of an motor, motor base, pump casing and feet etc. The inlet port and outlet port of the pump are at the same line. All pumps are equipped with free maintenance mechanical seals.

--------------------------------------------------------------------------------

Feature:  

--------------------------------------------------------------------------------

OPERATING CONDITIONS
1. Delivery liquid: rarefied, non-inflammable and non-explosive liquid with no solid grain or fiber. Liquid shall not cause any chemical or mechanical damage to pump materials. When the density or viscosity of the delivered liquid is greater than that of water, it is necessary to adopt an electrical motor of correspondingly big power. Whether the pump is applicable for a special liquid or not depends on many factors such as chloride content, PH value, temperature and ingredients of liquid.
2. Liquid temperature: -15oC~103oC
3. Ambient temperature: maximum 40��. When an ambient temperature is over 40oC or the elevation above sea level is over 1000 meters, the cooling effect of the electrical motor will not be good due to the low density of air, and the rated output power of an electrical pump will decrease correspondingly. Therefore, it is necessary to select an electrical motor with higher power.
4. Minimum inlet pressure: the inlet pressure shall be computed in case of following conditions.
High temperature of liquid, flow rate is significantly greater than the rated value, suction lift required for liquid is very big, inlet pipeline is too long; inlet conditions are bad.
5.Motor:squirrel cage induction motors,F Class insulation and in accordance with IP 54.50Hz standard voltage:3Ø/380V.


Q: And would a water pump off any 302/5.0 fit the 1985 F-150 302/5.0 whether it was from a Mustang ,or Crown Victoria
they should, the best way is cross reference the part go auto zone page check the part numbers see if they match
Q: My water pump is losing pressure slowly even though no water is being used. Your help is appreciated. Thank you.
If the motor sounds louder than normal. Youll need to check the impeller in the pump. Make sure the shaft seal on the pump is not leaking. You either have a leak, restriction in the system or a bad impeller or failing pump motor.
Q: Ok, so if i have an 80 watt solar panel and want to run a 12v dc fan and water pump ONLY when the sun is out or enough light to power them, will i need something like a voltage regulator? I would like to have the panels charge deep cycle 12 v batteries at the same time or when the fan and pump is not running. For instance, i have the panels out and my fan and pump on allowing them to run only on solar as well as charge the batteries. What diagram would i use? I would probably get a charge control for the batteries but more importantly what would i need to regulate the power from the panels? Inverter?
You may have to do some math. The 80 watt panel is only 80 watts at peak sun on a 75°F day at the equator. Chances are you will have something less than 80 watts to work with. But you can add up all the hours of partial sun to get an equivalant number of peak sun hours. An example would be a few hours in the morning and evening at partial power and a couple of hours at solar noon at nearly full power may give you 5 peak sun hours worth of light. 5 psh x 80 w/ps = 400 wh Your supply may have 400 watt hours worth of power per day. You state that the fan is 12v dc but what is the wattage? It could be a little 12v dc fan out of a computer or it could be a huge 12v dc fan out of an RV. What is the power requirements of the water pump? Is it a little 12v dc one for a foot tall decorative fountain or an industial 3 phase pump for a well? To charge the battery you need a voltage 120% higher than the battery voltage. 12v x120%=14.4 v To add up your loads convert them all the use to dc watt hours per day Here is an example to give you an idea of how to play with your numbers: Fan 12vdc x 1.5 A = 18 watts, use this for 5 hours your load would be 18w x 5hr = 90 watt hours Pump 120 vac x 2.5 amps = 300 watts (The AC will need to come from an inverter. The inverter has a certain amount of loss. How good it does the job of converting dc to ac is know as it's efficency. Lets use 90% to be safe) 300 watts / 0.90 = 333.4 watts, use this for 1/2 hour per day 333.4w x 0.5hr = 166.7 watt hours The 90 watt hours + the 167 watt hours = 257 watt hours per day. This would leave about 140 watt hours to put into the battery. Yes it would be best to use a charge controller to protect the battery from overcharging if the pump and fan are off, or from draining the battery too much if the fan or pump stays on.
Q: Hi, I'm looking for an affordable pump that can be used to circulate heated water (60 C) through a 12pipe with a diameter about the size of a pencil. Is there a pump out there to match this application? I've come across some small fountain pumps, but they need to be submerged in the 60 C water bath and I'm not sure about the temperature tolerances of it. The model I'm currently looking at is a quot;TotalPond130gph fountain pump model. Thanks
Sounds like you're in quite a predicament there.
Q: A pump, the flow rate of 30T/H per hour, lift 30 meters, should be allocated more power motor?
Depends on how big your water pump is. How long is the pipe length?
Q: Why is the water pump usually used multi-stage pumps, while the circulating pump is usually a single-stage pump?
Pump selection is based on flow, lift, power to determine, the actual situation is different, the choice of pump specifications and models are different, the key to your needs to choose.
Q: Went to bring my car in to get all my belts replaced (minus the timing belt) My car was working fine, nothing was wrong with it. I pick up my car and get it home when I turn to get into the drive way there's this horrible squeal. I bring it back to Pep Boys and they tell me my water pump is broke. Now I don't know anything about cars, but is there a belt that they replaced that does something to the water pump? Please if you know about cars let me know. Thanks
not there fault . just bad timing
Q: My car randomly decided to dump fluids the other day. Now, the engine overheats after 5 minutes of driving it and the check engine light comes on. I put more coolant in it and noticed it began to drip underneath the car. I'm hoping it's a leak but being my car is 10 years old and I've never replaced either the water pump or the head gasket I figure it's about due time unfortunately. About how much would this cost me to have done at the garage?
Rather than guess at what is wrong you should have it tested and confirm what is wrong, then worry about how much it will cost. The two things you worry about are only part of what the problem could be by your description. Could be a hose, clamp, radiator, thermostat, cap, gasket, pipe.....
Q: House has bad mains pressure, so previous owner installed a quot;Holding Tankwhich stores water from the mains, before pumping it into the house for the internal tanks.However, after some recent plumbing work when the mains was turned off, it's running a little weird. The pump seems to be constantly running, although at a very low level, and some times when the taps/fawcets are opened, they seems to be nothing for up to 30 seconds (only air), and then the water rushes out. Same thing for toilet/WC cisterns..Any advice/pointers appreciated.CheersJM
If you are using a standard well pump, then there should be a check valve in the pipe between the holding tank and the pump. In a well it will be a foot valve, but may also have been a simple check valve. The work on your mains may have introduced dirt into the valve and prevents if from sealing and maintaining the pressure in the system when the pump stops. Someone also suggested that the pressure tank (not the holding tank) associated with the pump has become water logged. If that is the case then a small volume of water coming out of the pressure tank will cause a large enough pressure change to keep the pump working. Last possibility, there has to be a sensor that determines that the level of the water in the holding tank is low and will turn on the mains supply and when the level gets high enough that the mains supply is turned off. This can be a pressure switch or a mercury switch similar to one with a sump pump, etc. So my suggestions are: Check to make sure that the holding tank is clean and there is no sediment in it. Check to make sure that the holding tank fills when the water level drops, (it appears to stop when it is full). If you do this next procedure, make sure that you know how to prime your pump. I would also turn off the hot water tank. If it is a foot valve, remove the foot valve by removing the clamp and then back wash it to clean out the dirt. If it is an in-line check valve then remove the pipe. between the pump and the holding tank and invert it, and run water through it to clean out any sediment, then replace the pipe. Drain the pressure tank, and if you can pump some air into it. Then make sure that everything is connected, prime the pump and turn it on. Make sure that everything is working, then at each tap, especially the hot water taps, turn them on and leave running until the water flows smoothly. When all of the air is out of the system then turn on the hot water tank.
Q: Help?Water is to be pumped to the top of a skyscraper. If the pump can create a gauge pressure (pressure above atmospheric pressure) of 8.50E+5 Pa, what is the height of the tallest building that it can service? DATA: g=9.8 m/s^2
IF the pump can produce a static pressure of 8.5e+5 Pa, then it can support a column of water, h h = P/(rho*g) = 8.5e+5/(1000*9.8) = 86.7 m h = 87m Now, the water will have no velocity, so you can't use it effectively, but that's not what the problem asks!

Send your message to us

This is not what you are looking for? Post Buying Request

Similar products

Hot products


Hot Searches

Related keywords