Oil Pump AY Series

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General Description
Type AY Serious Oil pump is a new product designed on the base of old type Y oil pump which is suitable for renewing equipment with the aim of saving energy. It is used for petroleum refinery, petrochemical, chemical industry and other petroleum, liquefied petroleum gas and other mediums which are inflammable, explosive, toxic, high temperature and high pressure without solid particles.
Performance range
Capacity：2.3～600m3/h
Head：30～603m
Temperature：t=-45℃～+420℃

Instruction of pump type
For example：
1：250AYS80
250—Suction nozzle diameter (mm)
A:First reform
Y: Centrifugal oil pump
S:First stage impeller is double-suction
80: Head of single stage (m)
2：80AY100X2B
80:Suction nozzle diameter (mm)
A:First reform
Y: Centrifugal oil pump
100:Head of single stage (m)
2: Stage number
B:Impeller cutting code
Construction：
The construction of oil pump type AY is divided into eight kind single-stage and single-suction overhung, double-stage and single-suction overhung, single-stage and double-suction overhung, single-stage and double-suction with two ends supporting, double-stage and double-suction with two ends supporting, single-stage and double-suction with two ends supporting，multi-stage and ring section.
The single and double stage pump casing is installed horizontally with supported on the center line. The suction and discharge nozzle flanges are cast together on the pump casing and vertical upwards. The stuffing boxes and pump cover are cast together which can be installed with soft packing seal and mechanical seals such as balancing bellow and series. The water-cooled chamber jacket, which can be selected ,is installed outside of shaft sealing chamber the water cooled chamber will be installed only when required by customers or when the medium is water with temperature more the 66℃ and hydrocarbon compound with temperature more than 120℃.
A journal ball bearing and thrust bearing arranged back-to-back are installed on the bearing housing. The bearings are lubricated by flinger with thin oil. Cooling fins are cast outside of bearing housing which can be cooled by air(temperature is less than 120℃). The bearing housing also can be cooled by water(temperature is 120℃ to 420℃)
The pumps are driven directly by driver through the membrane coupling. View from motor end, the rotating direction is anticlockwise.

Q:Is it normal for my sump pump hole to be empty. No water in there.. ??: I wish my hubby were home to answer- but I think it HAS to remain in the water. It will burn the pump up if it is dry. A sump pump is meant to be submersed... all the time. You may need a new pump now anyway. You might be burning it up. hope that helps!

Q:How do I change the water pump in my 1998 ford mustang manual v6?: If you don't already know how to do it, then take it to a shop to have it done by the professionals. If you insist on trying it yourself, buy a Chilton's manual for your car, do some online research (with pictures), and buckle down. You will need to loosen the belts, remove the belts, remove the water pump, replace it, and reinstall everything. You will need to make sure that the belt is routed the correct way, or BOOM! You might also want to replace the timing belt while you're in there. It makes sense to replace it if you already are removing it, and the timing belt is something you can't afford to have go bad on you.

Q:Why can't vertical water pump use spring shock absorber?: Building water supply and drainage and heating engineering construction quality acceptance specification (GB50242-2002) on the 4.4 water supply equipment installation 4.4.6 regulations. Because the spring damper is not conducive to the stability of the vertical pump running, therefore, the vertical water pump damping device should not use spring shock absorber.

Q:How long would it take before I would see water coming out of the exhaust bellow? I let it run for about 5 seconds or so and shut it of fearing it would burn up. Did this a few times and finally gave up. Pump wasn't hot and impeller was still good. Wondering if I just didn't let it run long enough?: i've always gone by the 30 second rule. even a NEW or emptied for winter motor that must completely fill, 30 seconds should be long enough. if it hasnt begun pumping by that point, i turn it off and give it some time to cool while i double check everything. then i might give it a full 45 seconds. but it wont overheat in less then a couple of minutes. and if its not pumping with the hose hooked up, the impeller is probably bad already anyways. however, if you do even get it near warm, its already hotter then you think it is where the heat is produced, the cylinders, and where you have tight clearances on fast moving parts, the cylinders and pistons. and if it gets too hot, major damage is quickly done. BTW, service period on a merc impeller is always 100 hours or 3 years. or NOW, before the motor is damaged, if unsure of when it was last done. when the impeller is less then $50 (and about an hour labor, if paying for it) and a new motor is THOUSANDS, you cant replace it too often. dennis, you have NO clue. i suggest getting one before you ruin the motor in your own boat. and in the meantime, keep your bad advice to yourself.

Q:What are the new regulations in the design of main and auxiliary water bin and water pump room in coal mine?: The main water bin must have a main bin and an auxiliary warehouse. When a sump is cleaned, another water tank can be used normally.When the normal water inflow is below 1000m3/h, the effective capacity of the main water tank should be able to accommodate the normal discharge of 8h.The effective capacity of the main water bin can be calculated by pressing type in the mine where the normal water inflow is greater than 1000m3/h:V = 2 (Q+3000)Effective capacity of V-- main water bin in type m3;Q-- mine hourly normal water inflow, m3.However, the total effective capacity of the main water storage tanks shall not be less than the normal water inflow of 4h.The effective capacity of the water tank in the mining area shall be able to accommodate the normal water inflow in the 4H mining area.There is a big difference between the maximum water inflow and the normal water inflow in the mine. The drainage capacity and the water storage capacity should be specially designed.The water inlet chamber should be set up. A sedimentation tank shall be provided for the filling of water sand, hydraulic coal mining and other gushing water with a large amount of impurities. The water storage capacity of short positions must often remain above 50% of total capacity.

Q:I need to fit a booster pump to increase pressure from a gravity fed vented solar water heater (uses vacuum tubes).The problem is that the temperature of the water from the solar panel can be very high - in fact it could boil under some circumstances. It's safe because the system is vented.As the quot;solarwater feeds existing water heaters in the house, diluting the hot with some cold prior to the pump with an automatic mixer valve is not really an attractive option as we want to gather as much hot water as possible.Can anyone tell me where to get a booster pump that can operate at up to 100 Deg C, delivering 2 bar pressure and about 25 liters per minute. Thanks.: Well, you have to have a mixer valve if your temps are over 140F If I understand you correctly, you could put your mixer valve on the gravity fed hot water and then the output of the mixer valve goes to the inlet of a pump that can handle 140F. Then you don't need a mixer on the hot water tank in the house. And finding a pump that can handle that temp will be a lot easier. Also, storing high temp water is very inefficient. The higher the delta Temp is from the water to the ambient surroundings, then the lower the efficiency. You could save just as much energy in the water by increasing your water tank size and lowering your temp. For instance a 100 gallons of water close to boiling has the same stored energy as 150 gallons of 140F water. And you don't need a mixer at that point and you don't need a special pump either. I'm assuming you are using storage on the roof with a thermosyphon? Can you add more water storage next to that one?

Q:I installed a new water pump on a Cherokee straight-6 engine, the upper radiator hose is not heating up and the engine is starting to make a funny noise. The thermostat is new and was working fine before. The coolant reservoir is full and no more coolant will drain to radiator / engine. Anyone know why waterpump is not circulating coolant?: You okorder

Q:does anyone know the proper way to take the lower gearcase off and install a new water pump kit. it is a 1986.: This is a simple repair but I'd recommend that you get a service manual, ether a factory manual or one of the generic Seloc manuals. The key things to do are mark the trim tab so you can put it back in the same position after repairs. Drain the oil. Removing the bolt that is in the hole at the back end of the upper housing, as well as all the obvious Nuts. both above and under the cavitation plate. Put the drive in forward gear, which takes the tension off the shift shaft. Once all the nuts and bolt are loose. Jiggle the drive and it will separate from the upper housing. You now have access to the water pump housing. Remove the housing and pull it up and off the d. Shaft. Inspect fully and account for missing impeller blades. When you re assemble Lube the impeller and put the drive key in place and put the impeller in place. Slide the housing down to the impeller. You can use ether th drive shaft or the propeller to turn the drive shaft in a clockwise direction as you apply pressure on the housing, It should slide down over the impeller. Reassemble in reverse order. Slide the drive shaft up into the upper housing turning the D. shaft using the prop to turn the shaft. Watch the water tube slip into the guide tube. Once it's in place put a couple nuts on then check the gear shift to make sure it goes F-N-R. Bolt up and fill with oil. Good Luck!

Q:How much would it be in labor and parts to change a water pump and on a 2000 Dodge Durango 5.9 4 wd with 109k.miles? Should I change the timing chain? If you can please give me a estimated Thank You!I getting tired of old Vechiles LOL: The cheapo water pump from oreillys is $46, the higher end one is around $70. As far as labor, Mitchell OnDemand calls for 2 hours flag rate time to change it out. You'll probably be looking at at least 1 gallon of antifreeze as well for what will be lost changing it out, and I would recommend changing the thermostat when you change the water pump. The 5.9 uses a timing chain, which I wouldnt recommend replacing, seeing as the vehicle has that low of miles on it. I'm not sure how much labor costs in your area, but the shop I work at charges $75 per flag rate hour. So if we were to do it, taxes and everything it would be right around $250. If you live in a big city, you'll probably be expecting to pay around $100 a hour for labor at a reputable shop. Good luck and hope this helps.

Q:Water is pumped out of a holding tank at a rate of 6-6e^(-.09t) liters/minute, where t is in minutes since the pump is started. If the holding tank contains 1000 liters of water when the pump is started, how much water does it hold one hour later??Round your answer to one decimal place.: Let V(t) be the volume of water (in Liters) in the tank after t minutes. We are given that V(0) = 1000, and we wish to find V(60). We are also given the rate of change of the volume: V'(t) = -[6 - 6e^(-0.09t)]. Note that a negative sign needs to be placed because the rate represents water leaving the tank, i.e., being pumped out of the tank. By the Fundamental Theorem of Calculus, Integral (0 to 60) V'(t) dt = V(60) - V(0), so that V(60) = V(0) + Integral (0 to 60) V'(t) dt V(60) = V(0) + Integral (0 to 60) -[6 - 6e^(-0.09t)] dt V(60) = V(0) + Integral (0 to 60) [-6 + 6e^(-0.09t)] dt V(60) = V(0) + [-6t + (6/-0.09)e^(-0.09t)] (Evaluated at t = 60 - Evaluated at t = 0] V(60) = V(0) + [-6(60) + (6/-0.09)e^(-0.09(60))] - [-6(0) + (6/-0.09)e^(-0.09(0))] V(60) = 1000 + [-360 - (200/3)e^(-5.4)] - [0 - (200/3)] V(60) = 1000 - 360 + 200/3[1 - e^(-5.4)] V(60) = 640 + 200/3[1 - e^(-5.4)] V(60) = approx. 706.4 Therefore, approximately 706.4 L of water occupy the holding tank 1 hour after the pump is started.

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