High Quality Electro Galvanized Wire

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Packaging & Delivery

Packaging Detail:	Spool, Reel, Coil,
Delivery Detail:	2~5weeks

Specifications

1) Bright and smooth surface
2) Different coil weight available
3) Small tolerance on wire diameter
4)ISO approved

Product Description

Electro Galvanized Wire

1)Application:	This kind of industrial wire is mainly used in construction, making of wire nails and wire ropes, express way fencing, binding of flowers and wire mesh weaving.
2) Material:	Carbon steel wire, mild steel wire
4) Surface:	Electro Galvanization
5)Diameter:	0.28mm~4.00mm
Tensile strength	320-500MPA
6) Technical Info:	Surface: hot-dipped zinc coated Tensile strength:340-500 N/mm2 for all sizes Elongation: Min. 10% for all sizes
7) Packing:	2kg~500kg, in small coils, big coils and on spool or drums
9) All can be produced according to customers’ actual requirement.

Q:I have an old house with old wiring. I have no colors to go by.: It should have continuity (low ohms) when tested against the general mass of earth.

Q:I have a Hunter 5 minute fan. I have four wires coming from my ceiling. Red, Black, White, and Bare Copper. The Fan has a Green Wire, Black Wire, White WIre,and a Black/White striped Wire. The Ceiling Plate also has green wire. I know to connect the black to black, red to black/white striped, white to white. But for the green and copper wires, do I connect the copper wire from the ceiling to the green wire in the ceiling plate and also to the green wire from the fan?: You are correct. With Romex? type house wiring the bare copper lead is the ground wire and should be connected with both of the green wires.

Q:Are two wires of the same material but different in thickness and length? Are their young's modulus of elasticity the same?: The elastic modulus is the inherent property of the material and, once the material is determined, the modulus of elasticity has been determined, irrespective of shape

Q:Or can stranded wire of the same gauge be subsitituted for solid wire without any consequences? The reason I ask is because its for a massive 4kJ capacitor discharge circuit, and I need all the energy delivered to the power coils im using, cant afford to have much leakage inductance.: You question about Inductance seems illogical. I can't imagine how a straight wire will affect a sudden discharge of current unless the wire is coiled (inductor) or have a shield attached to ground(capacitor). I believe the difference between the two wires are their direct current resistance which is very negligible if the wires are just a few feet long. The Capacitor that will discharge current directly to a coil is a 'tank circuit' and is a type of oscillator. Most likely, The inductance you will experience is caused by the power coil itself that feeds it back to the capacitor and vise versa. If that is true, I recommend a reverse shunt diode across the coil and a series diode between the capacitor and the coil.

Q:I bought a new light that holds two light bulbs for my bathroom and quickly took off the old light. I then noticed that wall had three wires coming from it, a black, red, and white. The light however has four wires coming from it, 2 whites and 2 blacks. How do i wire this properly so both light bulbs can be turned on and off simultaneously?: I'm going to assume that you are in the U.S.A. (if not, then disregard the rest of my answer). On the new fixture, twist the ends of the black wires together and twist the ends of the white wires together. Connect the white fixture wires to the white wire in the wall (I hope it is in an electrical box). Connect the Black fixture wires to either the Black or Red wall wire. To determine which one, you will need to know which one is controlled by the switch on the wall. You could just pick one and see if it works. If it does not, then try the other wire. Do not use the cheap crappy wirenut connectors that usually come with these fixtures. Go to the hardware store and buy a pack of tan wirenuts (red will work if necessary.)

Q:A wire is 1.5 m long and has a diameter of 1.5 mm. The stretch modulus of the wire is 6.2 x 10^10 N/m^2. If a force of 400 N is applied to end of the wire then the increase in length of the wire is???please help, thanks: The stretching of wire by longitudinal force: If F force applied across the crosectional area A of wire of radius r and lenght L then the wire elaogates in the dirextion of force Stress P = F / A A = pi* r^2 = (1.5/2)*10^-3 = 7.5 *10^-4 m^2 strain produced = dL / L = increase in length / original L Young's modulus or elastic (stretch) modulus for the maretial, within elastic limits, Y = stress/strain strain = stress / Y dL = F * L / A * Y = F * L / pi (r^2) * Y dL = 400* 1.5 / 3.14 (7.5 *10^-4)^2 * 6.2*10^10) meter dL = 0.005479 * meter dL = 5.479 millimeters increase in length

Q:If you hang a pot-plant with mass of 8kg from two lengths of wire attached to a horizontal beam 100cm apart. The wire on the left has a length of 50cm and the wire on the right has a length of 75cm.What is the tension in both wires?: The tension in both wires.? If you hang a pot-plant with mass of 8kg from two lengths of wire attached to a horizontal beam 100cm apart. The wire on the left has a length of 50cm and the wire on the right has a length of 75cm. What is the tension in both wires? In the triangle ABC, AB(c) = 100 cm, BC (a) = 50 cm and AC (b) = 75 cm 2s = a+b+c = 225 cm s = 112.5 s-a = 112.5 - 50 = 62.5 s-b = 112.5 - 75 = 37.5 s-c = 112.5 - 100 = 12.5 tan A/2 = √ {(s-b)*(s-c) / [s*(s-a)] = √ {37.5*12.5) / [112.5*62.5] A = 28.95? tan B/2 = √ {(s-c)*(s-a) / [s*(s-b)] = √ {12.5*62.5) / [112.5*37.5] B = 46.57? C = 180-28.95-46.57 =104.48? --------------------------------------... 46.57? is the angle between horizontal and 50 cm wire. 28.95 is he angle between horizontal and 100 cm P is the tension in the 50 cm wire and Q is the tension in the 75 cm wire Equating the horizontal components of the tensions P cos 46.57? = Q cos 28.95 ? P = Q cos 28.95 ?/ cos 46.57? P = 1.27 Q-------------------1 Equating the sum of the vertical components of the tensions to the weight of the pot P sin 46.57? + Q sin 28.95 = 8*9.8 N 0.73P + 0.48 Q = 78.4N 0.73(1.27 Q) + 0.48 Q = 78.4N Q = 55.72 N and P = 70.76 N ============================= Or use Lamis theorm Angle between P and Q = 104.48? Angle between P and the pot = 90 + 46.57? Angle between Q and the pot = 90 + 28.95 By Lamis theorm P/ cos 46.57? = 78.4/ sin 104.48? P = 55.67 N and Q = (78.4/ sin 104.48? ) cos28.95 = 70.85N ====================================

Q:I just removed a Australian light switch that I've never seen before that controlled a bathroom ceiling fan and the bathroom light. (both buttons on a single panel switch)I have a black wire coming from the switch box that has 2 other black wires splitting out from the connection point, one of each going to the fan and the light. And a single black wire going to the ceiling fan and a red wire to the light.I'm just putting in your everyday off/on switch one for each the fan and the light. any help? what are the positive and negative wires?: If you are putting in two single pole switches, one for light and one for fan then each switch has two lugs. Take the two black wires that split from one connection point and tie one to one lug of a switch and tie the other black to one lug of the second switch. This will leave you with one remaining lug on each switch. Then tie the remaining black to the first switch and the red to the other switch.

Q:1989 Honda Accord LxWhat is the wiring Diagram for the Stock stereo wiring harness?Just pulled out the old Stereo wanna put my deck in there now but i dont know the cars harness colorss.: Check out a Chilton's manual for that car.It may be at your local library to view, not sure that they will let you check that out if they have it.Hopefully they have a color copying machine so that you could photo copy the schematic and take that with you.

Q:I am installing a Pioneer head unit in a 1997 Nissan Pathfinder. All the wires from the harness to the deck are connected according to color. I was able to connect all of the wires except for the stock orange/black wire coming out of Nissan's harness. I am assuming this wire has something to do with the illumination. The pioneer does not have an orange/black wire to connect it to. The deck will not turn on at all if the orange/black wire is:- not connected to anything- connected to the red power wire- connected to the yellow power wireThe deck will turn on if the orange/black wire is:- connected to the black ground wire- connected to the remote wireHowever when the headlights are turned on the head unit cuts off and will not turn back on until the headlights are shut off again. In other words, the deck will work fine until the headlight switch is turned to the on position. Does anyone know a solution to this problem?Thanks, Dan: they are there merely in the adventure that your automobile has a characteristic to dim upload-ons. you dont want them connect them everywhere in maximum circumstances, thy are in basic terms a luxury in the adventure that your automobile has that characteristic.

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