Electro Galvanized Wire With Good Quality

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Loading Port:: Tianjin

Payment Terms:: TT OR LC

Min Order Qty:: 5 m.t.

Supply Capability:: 100 m.t./month

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Specifications

1.The lowest price
2.Have machine to produce
3.Materials test report
4.As customer's require
Silvery and soft binding wire

Galvanized metal wire

Material: low carbon steel

Surface treatment: galvanized

Gauge	SWG	BWG	Metric systems
8#	4.06	4.19	4.0
9#	3.66	3.76
10#	3.25	3.40	3.50
11#	2.95	3.05	3.00
12#	2.64	2.77	2.80
13#	2.34	2.41	2.50
14#	2.03	2.11
15#	1.83	1.83	1.80
16#	1.63	1.65	1.65
17#	1.42	1.47	1.40
18#	1.22	1.25	1.20
19#	1.02	1.07	1.00
20#	0.91	0.89	0.90
21#	0.81	0.813	0.80
22#	0.71	0.711	0.70

Q: Two wires are placed parallel to each other. What would be the effect of passinga) upward current through both wiresb) an upward current throgh one wire and a downward current through the other.Explain.: a) When the currents through both the wires are in the same direction, the magnetic field due to each midway between them, by right-hand thumb rule, will be in opposite directions. This will result in attraction between the wires. b) When the currents through both the wires are in the opposite directions, the magnetic field due to each midway between them, by right-hand thumb rule, will be in the same direction. This will result in respulsion between the wires.

Q: I want to connect a fan with light and pull chain only to a box that has the old wiring black and white to the new wiring black,white and green.Is this possible and how do I do it.: Black to black, white to white, the ground goes to the metal box. Only use a light weight fan, less than 6 lbs. KT wiring should be replaced ASAP. The insulation on the old wiring deteriorates over the years with heat and become a fire hazard. Most insurance companies want that type of wiring removed.

Q: how do i wire a dual 2 ohm sub to an amp at 2 ohm: You can't. Dual 2 ohm subs can only be wired at 1 ohm or 4 ohm. To run an amp at a 2 ohm load you need a dual 4 ohm sub. You can get a second dual 2 ohm sub to match and then they can be wired together at a 2 ohm load.

Q: can anyone please tell me what does hook-up wire mean and how does it differ from other kinds of wires such as light duty and heavy duty?Also,which one should I use for breadboards?: Hookup wire is a term usually reserved for wire sizes smaller than 16 AWG, usually single strand conductor. It is generally used in applications where current-carrying capacity is not of prime importance. Breadboarding is one of these applications, but usually uses 22AWG or smaller wire.

Q: A wire has a resistance of 21.0 ohms. It is melted down, and from the same volume of metal a new wire is made that is three times longer than the original wire. What is the resistance of the new wire?: The resistance of the new wire is (in terms of its length, area resistivity); R2 = pL2/A2 And the resistance of the original wire is; R1 = pL1/A1 The ratio is;(resistivity will cancel because its the same for both situations) R2/R1 = L2A1/L1A2 given L2 = 3L1 R2/R1 = 3A1/A2 To find the new cross-sectional area ,require the volumes to be equal; L2A2 = L1A1 3L1A2 = L1A1 A2 = (1/3)A1 Sub this into the R2/R1 equation to get; R2/R1 = 9 R2 = 9R1 = (9)(21) = 189 ohms

Q: Its a 3 wire chandelier, 2 are attached like a regular electric cord and the third is separate. all are the same color. the ceiling has 2 wires. one tan/white and the other is red. I am comfortable with doing the connections but unsure what wires to connect: One of the chandelier wires will go to the red and the other to the white wire--it does not matter which one goes to which. The third wire is likely bare (or green) and is a ground wire. Connect this wire to the ceiling box and to the third wire in the ceiling if there is one.

Q: My house is currently wired using Cat-5 lines. If I were to replace the Cat-5 wiring with Cat-6 wiring, would I see an increase in my DSL speed?: you have to have speical equipment to use cat-6, so no if you did that it would still be the same as using cat-6

Q: True or False?Branch wiring from a 200A - 3 phase 4 wire panelboard.WIRE #PHASES 1 --- PHASE A 2 --- PHASE B 3 --- PHASE C 4 --- NEUTRAL - WHITE WIRE 5 --- PHASE A 6 --- PHASE B 7 --- PHASE C 8 --- NEUTRAL 9 --- GROUNDTOTAL OF 9 WIRES GOING TO SIX (6) 20A 120V CIRCUITS: That's true. 9 wires may go to 6 circuits. Each circuit has one phase so 1,2,3,5,6,7 are the six phases going to six circuits. For two pair of three phases (pair one 1,2,3)(pair two 5,6,7) there are two neutral wires and one common earth wire. that is total nine wires. there is nothing wrong in it.

Q: Say you have a 5 cm current wire carrying 10 A going from left to right. Directly 1 c.m below the left end of this wire is a long wire that is perpendicular to the first wire and goes out of the page. What is the net force on the 5 cm wire?I've tried using F=ILB with the I of the first wire and the B of the second wire.: I didn't read the question so I was carefully working out the force. The wire is perpendicular to the first wire, so using the right hand rule you discover that the field it creates is PARALLEL to the first wire at this left end. The magnetic force is caused by the component which is PERPENDICULAR to the wire which is in fact zero. So there is no magnetic force at this point. As you move along the wire you get a diminishing amount of magnetism caused by the wire which is going out of the page but that field has a component which is DOWN the page. Therefore that part of the wire experiences a force which is into the page. ( take your right hand, put the thumb along the wire pointing to the right, the fingers point down the page, the palm points into the page which is then the direction of the force) I would be surprised if you were required to work out the magnitude of the force in this context. You can't use F= ILB because both the magnitude and the direction of the field varies at different points along the wire. If the perpendicular wire had been directly below the middle of the other wire there would have been no net force. If you were of a level where working out the force was appropriate you would need to set up the formula for B at various points along the wire, taking the vertical component only and integrate this over the range from 0 to 5 cm. Not a trivial mathematical task.

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