High Quality Electro Galvanized Iron Wire

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Silvery and soft binding wire

Galvanized metal wire

Material: low carbon steel

Surface treatment: galvanized

Q: I have a new light fixture I am trying to install. The electrical box has two sets of black and white wires coming in. Both of the black wires are connected together while the white wires from either set were used to connect the old fixture. How should I wire in the new fixture. The switch for this light has only one set of black and white wires connected to the light switch.: Possibly the box was wired using 2-conductor romex as a switch leg. That means one of the blacks is the power into the fixture box. It connects to the other black that goes to the switch. From the switch, the white is used to feed power back to the fixture. Hence you have one white that is neutral and one that is energized. This is not your fault but is 100% wrong, against code and is dangerous for someone like you that is trying to figure out what was done. Switch legs are accomplished using three conductors; one red, one black and one white. Use a current tester and see if you have one white that is hot and one that is neutral. If so, use a black magic marker and color the hot white one black. Do the same where it attaches to the switch.

Q: How can I repair an enamel coated headphone wire? In other words, how can an enamel coated wire be reconnected; i.e. how is the enamel coating stripped off, and what can I use to recoat it so that it won't short?: Strip off the coating to expose bare metal where you would to slice (reconnect) new wires. Twist them or soldier them together. The wires will not short unless they come in contact with electricity-conducting materials, including human flesh. Hardware stores sells paint just for wires, but you don't have to go such extremes. Just put some tape it or cover it with any other non-conductive materials.

Q: where does the expression 'down to the wire', come from?: I found this online: The wire is used in a four-legged footrace-- at least I've only ever heard the word tape used for races involving bipeds. That and ribbon. The wire in question is an actual wire, and it's used in the Sport of Kings, horseracing. A tape or ribbon would be too stretchy to instantaneously trip the shutter on the finishing-line camera when it was crossed. A horse has no problem busting through a single strand of wire.

Q: I'm trying to fix a light fixture for a friend. Her father-in-law gummed it up. At the fixture, there are 3 white wires soldered to a single wire. There are 3 black individual wires and one red wire. There are three switches that control the light.If I hook one of the black and the 3 white to the light, the light stays on constantly. If I hook either of the two other black individually, nothing comes on period.I'm pretty much at a loss. Any advice would be greatly appreciated.: Can you post a picture?

Q: What are the advantages and disadvantages of a bank wire transfer ?: Wire transfers on average will run you $15 for domestic and $30 for international. Both representatives from two different banks will process the electronic transfer. Advantage - No physical cash is exchanged. The money will be at another institution the same day. Disadvantage - Fee

Q: Two wires, 2.44 m apart, both carry current 2.2 A toward the bottom of the screen. The right wire is extremely long, and the left wire is 0.36 m long. What is the magnetic force on the left wire?: Magnetic force, F = BIL --------(1) where B is the magnetic flux density of the magnetic field caused by the right wire, acting perpendicularly to the left wire in Tesla I is the current in the left wire in Amperes L is the length of the left wire in metres To find B (due to the right wire), you have to use the formula B = (?0)(I)/(2πr) -----(2) where the I in this case is the current in the right wire, r is the distance between the two wires, and ?0 is the permeability of free space, numerically defined as ?0 = 4π×10?7 using eqn (2) so B (due to right wire) = (?0x2.2)/(2πx2.44) = 1.8x10^-7 T using eqn (1) and the value of B calculated above F = (1.8x10^-7 x 2.2 x 0.36) = 1.43x10-7 N

Q: I need the designations for the wires so I can splice in an amp.: Speaker wires: left front: (+) tan (-) gray right front: (+) lt. green (-) dk. green left rear: (+) brown (-) yellow right rear: (+) dk. blue (-) lt. blue Accessory power at radio for amp turn-on: yellow (only in 2003 and older; should be located next to orange constant power wire)

Q: What is the difference between carbon fiber and wire heating?: Carbon fiber heat is not transmitted through the medium, but far infrared light radiation to the human body, the heat transfer directly to the human body tissues and organs

Q: I have an old house with old wiring. I have no colors to go by.: consider a rewire , sounds overdue .

Q: This is the typical Physics problem with the wire and boom connected to a wall with a mass hanging on the end of the wire.Does the tension in the wire increase or decrease when the wire is connected higher on the wall (meaning the angle between the wire and the boom increases).: Assuming the boom is free to pivot at the wall, and a massless wire, the tension in the wire decreases as the attachment point is moved further up the wall away from the boom. There is a constant vertical force (the weight of the boom and the mass attached to its end) that is a constant component of the tension in the wire. The tension must increase to maintain this constant upward force as the wire approaches the pivot point, because the vertical component of tension is the tension multiplied by the sine of the angle between the wire and the boom. As the angle approaches zero, the tension required to support the boom approaches infinity. Conversely, as you move the end of the wire higher up on the wall, the tension decreases, approaching the combined weight of the boom and the suspended mass as the wire approaches being parallel with the wall. So imagine a sign attached to the side of a skyscraper at street level supported by a wire extending to the top of the building. There will be almost no horizontal component to the tension in the wire and the vertical component will just be the sum of the weight of the wire, the boom, and the attached mass.

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