• High Quality Electro Galvanized Iron Wire System 1
High Quality Electro Galvanized Iron Wire

High Quality Electro Galvanized Iron Wire

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Loading Port:
Tianjin
Payment Terms:
TT OR LC
Min Order Qty:
5
Supply Capability:
100 /month

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Quick Details

Place of Origin:

China (Mainland)

Anti rust:

shinning

Model Number:

YJT--001

Surface Treatment:

Galvanized

Galvanized Technique:

Electro Galvanized

Type:

Loop Tie Wire

Function:

Binding Wire

Wire Gauge:

0.4mm----4.0mm



Packaging & Delivery

Packaging Detail:1.inside with plastic and out with hession or woven bag 2.with pallet 3.as customer request
Delivery Detail:depend on amount

Specifications

eletro galvanized wire
1.wire diameter:0.4mm----4.0mm
2.roll weight:0.25kg/roll-----500kg/roll
3.shinning,anti-rust

Galvanized Wire
Wire GaugeSWG(mm)BWG(mm)Metric(mm)
84.054.194.00
93.663.764.00
103.253.403.50
112.953.053.00
122.642.772.80
132.342.412.50
142.032.112.50
151.831.831.80
161.631.651.65
171.421.471.40
181.221.251.20
191.021.071.00
200.910.840.90
210.810.810.80
220.710.710.70



Q:Wire 1 and wire 2 are made from the same metal. Wire 2 has a larger diameter than wire 1. The electric field strengths E1 and E2 are equal. A) Compare the values of the two current densities. Is J1 greater than, less, or equal to J2?B) Compare the values of the currents I1 and I2. Is I1 greater then, less or equal to I2?
The current will be more dense in the smaller wire. The value of the current is inversely proportional to the resistiance of the wire. Resistance = resistivity * length / Area since the wires are of identical material and length, the only thing left to vary is the cross-sectional area. Area is proportional to the square of the radius (diameter), so the current will be proportional to the square of the diameter. I2 is proportional to I1^2 I2 is larger than I1 .
Q:One wire has part of the plastic coating on the end, the other wire does not.
the lead is the wires showing. lead wire can also mean attaching a wire and feed it through a wall attach other end to the wire and pull it through. Now if you need both ends to have wire showing take a utility knife firmly place wire on block of wood and lightly cut through the caseing. thats the thick wire that en cases the other wires and peal back and then cut it off. then carefully hold blade of utility knife and wire aganst your thumb on a 45 degrees away from you and pull that will strip the plastic off the wires hope that answers your question dave
Q:What are the effects on an amp when you use power/ground wires that are too small? I bought a set of 8 guage wires off of OKorder, and it stated they can handle up to 1000W. I'm using a Kenwood KAC-9103D amp, 500x1 @ 4ohms, 900x1 @ 2ohms, and 900+ x1 @1ohm (1800 W max power). My subs are Kicker VR8, dual voice coil, 4ohms, wired in parallel. Was it a mistake to go with 8 guage wiring? Should have I gone with 4 guage?
Using smaller wires will cause your wire to heat . As the wire gets hot conductivity decreases giving less current to the amp. It seems like you are spending some money for the equipment i would use a 4 gauge to protect your investment. I have seen people car catching fire because of bad audio wiring
Q:A wire is 1.5 m long and has a diameter of 1.5 mm. The stretch modulus of the wire is 6.2 x 10^10 N/m^2. If a force of 400 N is applied to end of the wire then the increase in length of the wire is???please help, thanks
The stretching of wire by longitudinal force: If F force applied across the crosectional area A of wire of radius r and lenght L then the wire elaogates in the dirextion of force Stress P = F / A A = pi* r^2 = (1.5/2)*10^-3 = 7.5 *10^-4 m^2 strain produced = dL / L = increase in length / original L Young's modulus or elastic (stretch) modulus for the maretial, within elastic limits, Y = stress/strain strain = stress / Y dL = F * L / A * Y = F * L / pi (r^2) * Y dL = 400* 1.5 / 3.14 (7.5 *10^-4)^2 * 6.2*10^10) meter dL = 0.005479 * meter dL = 5.479 millimeters increase in length
Q:can anyone please tell me what does hook-up wire mean and how does it differ from other kinds of wires such as light duty and heavy duty?Also,which one should I use for breadboards?
Hookup wire is a term usually reserved for wire sizes smaller than 16 AWG, usually single strand conductor. It is generally used in applications where current-carrying capacity is not of prime importance. Breadboarding is one of these applications, but usually uses 22AWG or smaller wire.
Q:Ceiling lights wire guage
What Wire Size To Use
Q:The black wire is called ground but what is the red wire called?
The most common term I've heard for this is source.
Q:Given following setup of three wires in the plane of the page with I1 = 1.3 A (to the right), I2 = 3.4 A (to the right), I3 = 4.5 A(to the left) and each wire is separated by 3 m.I'm completely lost, I need to..1. What is the direction of the magnetic field at wire 3 due to wires 1 and 2?2. What is the direction of the force on wire 3 due to wires 1 and 2?Any help would really be appreciated! Thanks!
I assume that those wires are sitting parallel 3 m apart from one another. 1. The magnetic field around a wire forms concentric circles around the wire. Wire 1 and Wire 3 are parallel so when you draw a concentric field line around Wire 1 with radius 6 m, you get a magnetic field line passing Wire 3 at a right angle. And a concentric field line around Wire 2 with radius 3 m passes Wire 3 at a right angle. Both magnetic fields have the same direction because the current in both wires flows in the same direction (to the right). Using the right-hand rule, you can find that the magnetic field at wire 3 due to Wire 1 and Wire 2 goes into the page. Ans: Into the page 2. The force on a wire can be calculated in the following manner: I X B * L. Here I is the current on Wire 3, B is the magnetic field due to Wire 1 and Wire 2, L is the length of Wire 3, and X is the cross product operator. So I cross B would give the direction of the force. Now use the right-hand rule, I cross B will give the force direction pointing down. This means the force due to the magnetic field would repel Wire 3 from Wire 1 and Wire 2. Ans: The force on Wire 3 due to Wire 1 and Wire 2 would repel Wire 3 from them.
Q:I am trying to install an outside motion activated light fixture, there is a box with a yellow wire that did not have power... I found a white wire with power and joined it to the yellow wire...and after installing the fixture (white wire to white wire, black wire to black wire) my fixture is not turning on... uld it be because of the two kind of wires??
This does not sound like a conventional setup that meets code. There are two ways to connect switched power to a box. The first is to do the switching before the box, in which case you should see one black, one white, and one bare copper wire (ground) coming out of the box. You would hook your fixture as follows: black to black, white to white, and green and bare to the box. The second configuration has the wires from the switch joining the power wires (black, white, ground) in the box. In this case, the black wire should always be hot, no matter what position the light switch is in. The wires from the switch should be the same as from the circuit: black, white and bare copper (ground). What you describe sounds very suspicious, unsafe, and not to code. Unless you are very familiar with safe electrical practices and residential wiring, I suggest you call in an electrician to troubleshoot the problem and correct it.
Q:the plug only has room for black,red,ground wire.. what do i do with the white wire
There okorder /... is a 3 wire plug used for 208 or 240v (there is no 220v in the US). It has two hots (gold screws) and a ground (green screw). A typical 10-3 cord has a black white and green white, connect the green wire to the green screw and the black and white wires to the gold screws. An L6-30 is not compatible with devices that have a 240/120v configuration that use both 240v and for 120v and need a neutral connection, for this you would need to use a 4 wire L14-30. Also be aware there are some special rules about ranges and clothes dryers, please update you question if that's what you are dealing with.

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