Galvanized Steel Wire Rope For Elevator

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Loading Port:: Tianjin

Payment Terms:: TT OR LC

Min Order Qty:: 200 m.t.

Supply Capability:: 20000 m.t./month

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Quick Details

Steel Grade: Carbon Steel
Standard: ASTM, BS, DIN, GB, JIS
Wire Gauge: 0.7MM-40mm
Place of Origin: Chongqing, China (Mainland)
Type: Galvanized
Application: Steel Wire Strand
Alloy Or Not: Non-alloy
Special Use: Cold Heading Steel
Model Number: CH010908

Packaging & Delivery

Packaging Details:	Coils or as per your request.
Delivery Detail:	30days

Specifications

Galvanzied,High Anti-Corrison
ISO9001:2008 cert.
20years experience .

Galvanized Steel Wire Strand

Conductors for overhead lines, galvanized steel wire strands, messenger wire, overhead ground wire and stay wire
1 x 7, 1 x 19 from 1.0mm to 4.19mm with BS183, BS4565, BS443, ASTM-475, ASTM363, ASTM640, ASTM498, BSI EN 50, 189 and IEC888 standards
Round wire concentric lay overhead electrical standard conductors IEC 1089
Galvanized coating on wire BS 443

Packing Finish:In Coils,Plastice paper,Strong PVC Clothes.

Q: A long horizontal wire carries a current of = 52 . A second wire, made of 1.00--diameter copper wire and parallel to the first, is kept in suspension magnetically 5.0 below.What is the magnitude of the current in the lower wire?: The lower wire is kept in suspension magnetically means that the downward force of gravity is equal to the upward magnetic force. Its NOT an easy problem so we need to solve it in small steps. Let's find the two forces acting on the lower wire: (*) Downward force of gravity = mg = (volume) x (density) x (gravitational acceleration) = (pi r^2 L) x(8920)x(9.8) = 0.06896L We assume the radius of the wire is 0.5 mm or 0.0005m, copper density is 8960 N/m^3, gravitational acceleration = 9.8 m/s^2 (**) Upward magnetic force = mu(zero) x i(one) x i(two) x L / (2 pi d) = 2.08x10^(-4) L i(two) mu(zero) is a constant = 4 pi 10^(-7), i(one) is the current in the first wire = 52A, i(two) is the unknown current in the second wire, d is the distance between the wires = 5 mm or 0.005m The forces are equal, therefore 0.06896L = 2.08x10^(-4) L i(two) We divide both sides by L (the unknown length of the lower wire) and now we can solve for the current i(two) ANSWER: i(two) = 331.5 A

Q: why do we use copper wires as connecting wires: For better conductivity and durability.

Q: where does the expression 'down to the wire', come from?: I found this online: The wire is used in a four-legged footrace-- at least I've only ever heard the word tape used for races involving bipeds. That and ribbon. The wire in question is an actual wire, and it's used in the Sport of Kings, horseracing. A tape or ribbon would be too stretchy to instantaneously trip the shutter on the finishing-line camera when it was crossed. A horse has no problem busting through a single strand of wire.

Q: I am installing a ceiling fan. The directions say to connect the blue and black wire from the fan to the black wire coming from the ceiling and the white to the white from the ceiling using a wire nut. I have connected those with no problemThat leaves me with a green ground wire coming from the fan. However, the only ground wire coming from the ceiling is a naked solid copper wire. How am I supposed to connect those using a wire nut??: Early on as an electrian I had a mentor who gave me this tip....take the stranded wire and lightly rub it in a clockwise direction, not a real twist just mold it so it sticks together a bit, place the two wires side by side but cheat the stranded wire up a bit so it (apprears) longer than the solid by maybe 1/32 of an inch. place the wire nut on and twist, you will feel it grab continue toi tighten just until it begins to pull the insulated part of the stranded wire taught.... you will see what I mean and understand....gently tug on stranded wire to make sure the joint is good.

Q: The wire is to the box: Black wire= hot goes to the the black screw. White wire = neutral goes to the other side. Looking from the plug side, the hot/black wire is the smaller slot The larger slot is the neutral.

Q: what if I use a 100 amps.main braker to wire my range and dryer: NO each appliance has to be wired to the panel on its own breaker Dryers is normally # 10 wire and on a 30 amp 2 pole breaker. Three wire receptacles can still be used if they are existing in older homes and the appliance has to be wired for that 3 wire receptacle.Newer dryers have 4 wires and have a separate ground unlike the older dryers that used the neutral wire and ground together. A range can be # 4 wire or in some case # 6 wire depending on the KW rating of the range and have to have a 40 or 50 amp breaker on them as well. You should not put them together of course. Call an electrician and have ot done properly and it could save you form a heartache or worse.

Q: I removed a dishwasher and now the wires are exposed. I turned off the circuit to that outlet. I am planning on waiting a while to replace the dishwasher. I want to turn the circuit back on so I can use the other outlets, but don't want to leave the wires exposed. Any ideas?: wire nuts that can hold 1 .. 14awg wire or a bit smaller... twist one on each individual wire and give it a little tug, it sould not come out, then wrap some electrical tape around each of them

Q: If you hang a pot-plant with mass of 8kg from two lengths of wire attached to a horizontal beam 100cm apart. The wire on the left has a length of 50cm and the wire on the right has a length of 75cm.What is the tension in both wires?: The tension in both wires.? If you hang a pot-plant with mass of 8kg from two lengths of wire attached to a horizontal beam 100cm apart. The wire on the left has a length of 50cm and the wire on the right has a length of 75cm. What is the tension in both wires? In the triangle ABC, AB(c) = 100 cm, BC (a) = 50 cm and AC (b) = 75 cm 2s = a+b+c = 225 cm s = 112.5 s-a = 112.5 - 50 = 62.5 s-b = 112.5 - 75 = 37.5 s-c = 112.5 - 100 = 12.5 tan A/2 = √ {(s-b)*(s-c) / [s*(s-a)] = √ {37.5*12.5) / [112.5*62.5] A = 28.95? tan B/2 = √ {(s-c)*(s-a) / [s*(s-b)] = √ {12.5*62.5) / [112.5*37.5] B = 46.57? C = 180-28.95-46.57 =104.48? --------------------------------------... 46.57? is the angle between horizontal and 50 cm wire. 28.95 is he angle between horizontal and 100 cm P is the tension in the 50 cm wire and Q is the tension in the 75 cm wire Equating the horizontal components of the tensions P cos 46.57? = Q cos 28.95 ? P = Q cos 28.95 ?/ cos 46.57? P = 1.27 Q-------------------1 Equating the sum of the vertical components of the tensions to the weight of the pot P sin 46.57? + Q sin 28.95 = 8*9.8 N 0.73P + 0.48 Q = 78.4N 0.73(1.27 Q) + 0.48 Q = 78.4N Q = 55.72 N and P = 70.76 N ============================= Or use Lamis theorm Angle between P and Q = 104.48? Angle between P and the pot = 90 + 46.57? Angle between Q and the pot = 90 + 28.95 By Lamis theorm P/ cos 46.57? = 78.4/ sin 104.48? P = 55.67 N and Q = (78.4/ sin 104.48? ) cos28.95 = 70.85N ====================================

Q: Why would I want to upgrade the wires on my airsoft gun? What does it do?: I think it prevents the wires from overheating and melting the insulation which could lead to a short.

Q: friend i want litz wire in this wire consits of group of enamled coted copper wire(like machine winding wire with multi lead wire),so i want types different guages(that each lead in wiretotal wire guage) and no of leadds.my pupose is for project wire for with standing wire capcity of 20amp's. please give information............................: www.okorder / I am pretty sure you can get it here

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