Electro Galvanised Steel Wire

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Galvanised Steel Wire

(1) Quality : Meet GB/T 343 standard and other requirements of relevant standards .

(2) Zinc Coating: Meet GB/T 15393 standard and other requirements of relevant standards .

(3) Raw Material : Wire rod ——1006 , 1008 , 1018 , Q195 , etc, and zinc with 99.995% purity.

(4) Tensile Strength Range

Size (mm)	Tensile Strength (mpa)
0.15-1.60	290-550
0.65-1.60	400-550
1.61-6.00	400-1200

(5) Application : Used in wire mesh , artware , metal hose , binding for agriculture and construction , etc.

(6) Packing

Size (mm)	Coil Size	Spool Packing	Big Coil Packing
Size (mm)	Coil Size	Spool Packing	ID (mm)	OD (mm)
0.15-0.26	6 inch	1-14kg/spool
0.27-0.60	8 inch	1-100kg/spool
0.61-1.60	12/14/16 inch	1-100kg/spool	250-400	400-770
1.61-6.00		14-500kg/spool	450	800
1.61-6.00		14-500kg/spool	508	840

(7) Zinc Coating

Meet GB/T 15393 standard.

Size (mm)	Weight of Zinc-Coating ( g/m2 )
	A		AB	B	C	D	E	F
	A1	B2
≤0.25			30	20	18
>0.25-0.40				30	25	20
>0.40-0.50					30	20
>0.50-0.60					35	20
>0.60-0.80	120	110			40	20
>0.80-1.00	150	130			45	25
>1.00-1.20	180	150			50	25
>1.20-1.40	200	160			50	25
>1.40-1.60	220	180			50	35	30
>1.60-1.80	220	180			70	40	30
>1.80-2.20	230	200			80	50	40
>2.20-2.50	240	210			80	55	40
>2.50-3.00	250	230			90	70	45
>3.00-4.00	270	250			100	85	60	30
>4.00-5.20	290	270			110	95	70	40
>5.20-6.00	290	270	245		110	100	80	50

Q: I have a 2002 Chevy blazer 4.3 motor we'll I found some wires that look like trailer wires on the back of the car and I'm trying to connect a 4flat trailer plug in. So the wires are following on the car. Yellow is left blinkerGreen is right blinkerBrown is running lights Blue is brake lightsWhite groundSo the 4 flat wires are as following White groundYellow is left turnGreen is right turnBrown is taillightsSo my question is how can I get my brake lights and running lights on the trailer plug in. Cause I have 5 wires on my vehicle and only 4 on my trailer plug. Please help: On okorder /... also available at your local auto parts store

Q: I want to get an underground fence but i cant figure out what the difference in the wire they use and regular insullated wire. What is the difference and why can't i use regular wire instead of the wire that comes with the kit: There isn't anything special about the wire that comes with the kit, it is just wire. If you have already installed the fence and just need to enlarge the area you can use your own wire just make sure it is the same gauge wire as is already hooked up.

Q: running wire from wall out let to a on and off switch and then to another outlet: What is your problem ? i can be contacted at johnd_82@yahoo

Q: I recently purchased a used car already wired for an amplifier, however, when I looked at the wiring i found that the installer ran 8 gauge wire and then crimped it to a 12 gauge wire (with fuse) that connected to the battery is this bad? should i change it to 8 gauge? Or does it not matter?: As long as the middle of the wire is not grounding at all. You will be fine. You can run any size gauge wire as long as it connects at each end real good and gets a good connection. The best way instead of crimping anything at all is to get a 100amp fuse where one wire end goes into a slot on each side and a screw holds it tightly. You can run the eight gauge to one side and run the twelve out of the other and thats the best way and safest way to do it so you have no crimped hack jobs on it. -Shawn

Q: Besides the speaker wires, what do the remaining 5 colored wires stand for on a stock 03 Mitsubishi Galant radio?: See if they have a Haynes book for your vehicle at an auto store. In the last pages they have the wiring diagrams and the colors.

Q: the plug only has room for black,red,ground wire.. what do i do with the white wire: You can't. You need a 4-wire receptacle to use with 4-wire cable. That is the only to wire this circuit to code. You will need to replace the cord on your appliance with a 4-wire as well.

Q: A potential difference of 13 V is found to produce a current of 0.37 A in a 3.1 m length of wire with a uniform radius of 0.42 cm.(a) What is the resistance of the wire? (b) What is the resistivity of the wire? Please show work.: P. D. applied = V = 13 V Current produced = I = 0.37 A (a) Resistance of the wire = R = V / I = 13/0.37 = 35.14 Ohm (b) R = ρL/A = (ρL) / π r?) = ρ = (R A) / L = R (π r?) / L ......... (1) R = Resistance of the wire = 35.14 Ohm , L = length of the wire = 3.1 m A = Area of cross-section of the wire = π r? r = radius of cross-section of the wire = 0.42 cm = 0.0042 m ρ = Resistivity of the wire in Ohm-m Substitute the values in the formula (1) and calculate. Take π = 3.14

Q: i am looking for a wire diagram for a 03 eclipse gts with an infinity factory radio and built in amp. i was curios if you can add another amp and sub to this system to give it a little more bass: 2003 okorder /

Q: Question about the 3.5mm cable, I cut it open and there are 4 individual wires inside of it. I've only ever seen 2 wires and a loose one. Which ones are right/left and would the other 2 both be ground?The colors are red/green/white/black. I'm assuming the red/white are right left like normal? But I'm not too sure.: do you mean an audio cable?

Q: Say you have a 5 cm current wire carrying 10 A going from left to right. Directly 1 c.m below the left end of this wire is a long wire that is perpendicular to the first wire and goes out of the page. What is the net force on the 5 cm wire?I've tried using F=ILB with the I of the first wire and the B of the second wire.: I didn't read the question so I was carefully working out the force. The wire is perpendicular to the first wire, so using the right hand rule you discover that the field it creates is PARALLEL to the first wire at this left end. The magnetic force is caused by the component which is PERPENDICULAR to the wire which is in fact zero. So there is no magnetic force at this point. As you move along the wire you get a diminishing amount of magnetism caused by the wire which is going out of the page but that field has a component which is DOWN the page. Therefore that part of the wire experiences a force which is into the page. ( take your right hand, put the thumb along the wire pointing to the right, the fingers point down the page, the palm points into the page which is then the direction of the force) I would be surprised if you were required to work out the magnitude of the force in this context. You can't use F= ILB because both the magnitude and the direction of the field varies at different points along the wire. If the perpendicular wire had been directly below the middle of the other wire there would have been no net force. If you were of a level where working out the force was appropriate you would need to set up the formula for B at various points along the wire, taking the vertical component only and integrate this over the range from 0 to 5 cm. Not a trivial mathematical task.

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