PVC coated wire

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Product introduction: selection of pvc coated wireand then processed, the line is arranged tightly,

and fixed with a bracket, the products produced are very beautiful, is also very convenient to use.

Size range 0.6mm6.0mm. This product is mainly used in binding and manor garden decorations,

both functional and beautiful，the price is very cheap, it is a garden binding choice products.

Packing:.0.1kg to 5kg coil packing,with plastic bracket, label,carton,pallet,or according to customers' requirement.

Q: HiI want to cover a large section of a wall at home with wire. There is a plug socket (electrical outlet) in the wall. How can I ensure that I do not drill into electrical wiring within the wall? Is there some way to scan a wall to locate the wires?Thanks.: You want to cover a wall with wire? Just kidding, i figured out what you were trying to say. There are good answers here already. Just be sure you are putting screws into the studs only and you will be fine. What are you covering with? Sheetrock? Wood? The glue idea sounds good too, depending on what you are putting on the wall. Again...i dont know how to cover a wall with wire. I guess if you are an artist. LOL Good luck

Q: 2 long striaght wires (20m each) ,each having a 1.0A current going up.The distance between the two wires is 1.0m(a) what is the magnetic field (magnitude and direction) at a point o.50m left of the wire 1?(b)what is the magnetic field (magnitude and direction) at a point 0.6m right of Wire 1?: Assuming Wire 2 is to the right of Wire 1: a) Bwire1 = (u*I)/(2*pi*r) = ((4*pi*10^-7)*1A)/(2*pi*0.5) = 0.000004 Bwire2 = 0.000000424 Btotal = 0.000004424 (away from wire 1) b) Bwire1 = 0.000003333 Bwire2 = 0.000005 Btotal = -0.0000017 (toward Wire 1)

Q: I want to install an LED and I need to splice into a wire.How exactly do you connect a new wire to an old wire? Do I cut it? Then what? Solder?: Soldering is by far the best method of connecting two wires. You can use the small clamp/connector methods, but they are not very permanent and tend to corrode and lose connection if ever exposed to elements or anything. If you can solder (or even try) -do it.

Q: I am replacing an outside floodlight, the cable from the house has 4 wires (black, brown, grey and yellow), but the floodlight has the standard 3 live, neutral and earth fitting. How would I wire the new floodlight.. the wiring for the old floodlight is less than a year old on a house rewire.Thanks!: Four wire power cables used to be used for 2 and 3 phase power. You would normally provide floodlight power with the use of 3 wires. How long is the cable length from house to floodlights? I would look to see what your source wire colors are and try to match those. It used to be in the USA that the red wire was used to carry the 120/240 Volts AC (50 ~ 60~ Herz). The Black wire was considered the return or negative line; and if you have a green wire it is used to put an earth ground on all the shielding, metal jackets, etc.

Q: The drawing shows two long, straight wires that are suspended from the ceiling. The mass per unit of length of each wire is 0.050kg/m. Each of the four strings suspending the wires has a length of 1.2m. When the wires carry identical currents in opposite directions, the angel between the strings holding the two wires is 15 degrees. What is the current in each wire?? Im not sure what equations to use for this problem.: You need two basic equation: 1° Force acting on conductor in magnetic field: F = B I λ ..........(1) where B is magnetic field (also called magnetic induction) I is current λ is length of wire 2° Magnetic field near straight wire carrying current I B = μo I / (2πd) ..........(2) where d is distance from the wire μo is the magnetic permeability constant of vacuum (approx. same for air) μo= 4π*10^-7 Tm/A When there are two parallel wires on distance d carrying currents I1 and I2, each of them produce magnetic field causing forces acting on wires. Magnetic field from second wire creates force on first wire: F1 = B2 * I1 * λ Magnetic field from first wire creates force on second wire: F2 = B1 * I2 * λ These forces are equal in magnitude: F = μo I1 I2 λ / (2πd) ..........(3) When currents flow in same direction forces are attractive, and for opposite direction forces are repulsive. When I1=I2, F = μo I? λ / (2πd) ..........(4) Each wire, suspended on strings, decline from vertical position for angle θ=15°/2 = 7.5°, so that the angle between the strings holding the two wires is 2θ=15°. We find F from condition of static equilibrium of torques (relative to point where strings are attached to ceiling): F L cos θ = G L sin θ ..........(5) where G is weight of wire; G = m'gλ where m' is the mass per unit of length of each wire. L is length of strings from (5) we get relation F = G tan θ ..........(6) or F = m' g λ tan θ ..........(7) and from (4) and (7) : μo I? λ / (2πd) = m' g λ tan θ ..........(8) λ on both sides cancels, and we find current I as I = √(2 π d m' g tan θ / μo) ..........(9) You didn't say if there was some initial distance between wires, so we'll assume they are suspended in same points. In that case d = 2L sinθ ..........(10) and finally I = 2 √(π L m' g sinθ tan θ / μo) ..........(11) I = √[1.2 * 0.05 * 9.81 * sin 7.5° * tan 7.5° / 10^-7 ] I = 318.034 A

Q: Or speaker wire that has an RCA plug on one end?If you know of something that is inexpensive without me having to get another preamp, please help.(this is for a turntable preamp by the way, my preamp only has RCA output.): do not use speaker wire for the turntable preamp!! use RCA cables. speaker wire is balanced wire, both conductors are identical. RCA connectorized wire is coaxial, shielded and unbalanced. You need the shielded coaxial unbalanced wire.

Q: how do you connect two copper wires together: With connectors!!! (Wait for an answer from someone who knows more!)

Q: My starter I replaced has 3 wires, two red and one black. Where does each wire go? Pictures would be very helpful if possible: The First red wire goes to the solenoid on the fender well right by the battery. the second red wire goes from the solenoid to the starter on the one main post there. the black wire goes from the engine block to the battery on the negative side. All connections must be tight but not not crushing on the battery

Q: yamazuki wire colors for a universal ignition switch: Scooter Ignition

Q: I have 2 wires that go from the Solenoid to the wiring harness. But i don't know which wires go to where. One of the wires from the Solenoid it the remote switch and the other is the power for my whole interior. There are red, orange and black wires that come from the wiring harness. but i don't know which ones to use.: I would say you should have a wiring schematic to guide you. You could try searching on line for some free information or buy a shop manual published by Chevrolet. You could try one of the Haynes manuals, but sometimes they are not as complete as the shop manuals. You could also go to a local dealer and speak with someone in the Parts Dept. or speak with a mechanic. If you want to try it yourself, I would have someone hold the key in start position, and measure the voltage on those three wires on the wiring harness. Only one should have voltage when the key is in the start position. This wire has to go to the solenoid. That's the next thing to determine, which one. One is probably a ground and one goes to the coil in the solenoid. With an ohm meter, measure the resistance on these two wires. The one with the most resistance is probably the ground, and the other one is probably the coil. If you connect this wire to the wire we mentioned earlier, you will probably be OK. After this point, I don't think you could hurt anything. If you try it and it won't work, switch wires. Good luck.

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