• Aerial insulated cable with rated voltage of 1 kV and the below System 1
  • Aerial insulated cable with rated voltage of 1 kV and the below System 2
Aerial insulated cable with rated voltage of 1 kV and the below

Aerial insulated cable with rated voltage of 1 kV and the below

Ref Price:
get latest price
Loading Port:
Tianjin
Payment Terms:
TT OR LC
Min Order Qty:
100 m
Supply Capability:
100000 m/month

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Product characteristics and application

The product is applicable for AC rated voltage of 1kV and the below, and can be used as copper core, aluminum core or aluminum alloy core weatherproof PVC and PE for aerial power line use and cross-linked XLPE insulated aerial cable.

 

Executive Standards

According to the GB 1179-83 and GB/T 1179-1999.
At the same time,we can produce by the standard IEC, the standard of England, Germany and USA recommended by the international power committee on different requests.

 

Application characteristics

(1) The rated voltage is UO/U: 0.6kV/1 kV.
(2) The maximum admissible working temperature: PVC insulation and PE insulation shouldn't exceed 70℃; XLPE insulation shouldn't exceed 90℃.
(3) The laying temperature of cables shouldn't be lower than -20℃.
(4) The admissible bending radius of cables: cables with outside diameter D lower than 25mm shouldn't be less than 4D; cables with outside diameter D of 25mm and the above shouldn't be less than 6D.

 

Type and names

(1) The type implications with letters
JK一Series for aerial use   LH一Aluminum alloy   HJ一Cross-linked polyethylene insulation
(2) Type combined with structure and product represented

Type

Name

core

Sectional area

Precautions for laying

JKV-0.6/1

Copper core PVC insulated aerial cable with rated voltage of 0.6/1 kV

1

16~240mm²

Aerial fixed laying,the service wire. etc.

JKLV-0.6/1

Aluminum core PVC insulated aerial cable with rated voltage of 0.6/1 kV

JKLHV-0.6/1

Aluminum alloy core PVC insulated aerial cable with rated voltage of 0.6/1 kV

JKY-0.6/1

Copper core PVC insulated aerial cable with rated voltage of 0.6/1 kV

JKLY-0.6/1

Aluminum core PVC insulated aerial cable with rated voltage of 0.6/1 kV

JKLHY-0.6/1

Aluminum alloy core PVC insulated aerial cable with rated voltage of 0.6/1 kV

2、4

10~120mm²

JKYJ-0.6/1

Copper core cross-linked PVC insulated aerial cable with rated voltage of 0.6/1kV

JKLYJ-0.6/1

Aluminum core cross-linked PVC insulated aerial cable with rated voltage of 0.6/1kV

JKLHYJ-0.6/1

Aluminum alloy core cross-linked PVC insulated aerial cable with rated voltage of 0.6/1 kV






Q:i'm using an older mac at uni to do illustration, i pulled the computer round to put a tablet in it and the computer shut down, there are about 20 computers in the lab....the power cable at the back that is connected to the monitor is loose, i tried to put it back in but it's crackling....can i get electrocuted from putting it back in? i can't shut down all the computers so there's still electricity running through...thanks
souds scary but its not - plug her back in your good to go!!!!
Q:I have a feeling my power quot;brickis faulty and need to find a replacement, hopwever, none of the high street retailers quot;Game, Gamestation, HMV, Argosseem to stock them.
u can contact microsoft talk to them on teh phone for 5-10mins and theyll giv u a free one
Q:I just plugged a 300V power cable into power supply that accepts 115-240V then turned on the power supply. The power supply was not connected to the motherboard. I don't have another cable so I can't really check if its still working nor do I want to try again with the 300V cord if it can potentially cause damage.
It needs to be connected to the motherboard, before it will operate. 300V, just means the capacity of the cable.
Q:My power cable says it is plug in but will not charge it. What is wrong?
It could be your cable or power supply unit went bad. Or, your power socket on the main board went south. The good thing about laptops is that the power supply unit is external and easy to swap out.
Q:I'm putting in my new power supply and gotta take out the old. But there isnt any clips to slide the cables out. I don't want to pull to hard and damage anything. How do you get it out. Do you pull hard? Help me.
Yes sometimes you gotta pull or gently wiggle these power cords off. I have trouble with some systems and i dont know what it is but I will gently take a pair of pliers and pull it off if i can't wiggle them out. Be careful not to squeeze, i just use it for grip because i have fat fingers....Good luck.
Q:I'm getting a new graphics card and my PC does not have the 6 pin power adapter already installed so i will have to buy the wire myself and connect it to the power supply.Only problem is i don't really have any clue on how to do so and can't find anything anywhere on how to do it.That's pretty much it and thanks in advance.
But If I have only one moles connector from my PSU, Can I use an Molex splitter for get the 2 connectors that I need?
Q:I am doing a test if the power supply.Can you have the computer on and plugged in with PSU out in the open, leave on the carpet ?Can you have the power cable plugged into the psu first and then try to plug in the psu cable into the mother board. Would this electrocute you? if you accidentally knocked over liquid onto the power supply while the computer is running and you touched the motherboard at the same time while you are perfectly grounded. Can this electrocute you? unpluging the psu connector while the computer is on?
I'm willing to bet that there's people out there who'll debate me on this, but the answer is a nutshell both yes and no. Part I: As for having the power supply out in the open the answer is generally no, assuming you have it on a non-conductive surface such as a sheet of cardboard, assuming your carpet has any grade of nylon in it, and assuming the wiring in your house is well-grounded. Part II: I doubt it, but it'd be a better idea if your plugged it into the motherboard first, then to the power supply, then the wall. Part III: Both yes and no. It really depends on a small number of factors like how well grounded (electrically) it is. However, liquids and electricity of any type are NEVER a good mix. Part IV: Don't even think about it. Aside from something extreme like oh say a fire, there's no surer way to kill a motherboard than to disconnect the connector while powered-up.
Q:Fourth, what causes the power cable fire accident
After the cable is burned out, the repair time is long and the loss is serious
Q:I recently purchased a new power cable for my HP laptop (v6000 series) due to the disappearance of my old one. When I first plugged in the laptop, I noticed that it did not charge. I thought this might just be due to the fact that the battery has been dead for an extensive amount of time, but after leaving the computer plugged in over night, nothing has changed.What can I do to make my laptop's battery charge?Do I need to have a more powerful power cable?Thank you all for your help.
Maybe there are something wrong with your new power cable. Are you sure if the compatible is ok? I think you must take it to the seller and required he to explains.
Q:What I really just want to know is the equation and basic concept on how to determine the optimal length of power cable needed to connect two poles while knowing only the linear density of the cable.It does not matter how much sag is produced because of limitations due to the strength of the power cable.
The web page provides very thorough information and rigorous mathematical treatment relevant to the answer you seek. But it is just too much all at once to digest. So take it piecemeal, one bit at a time! First, you must realize that the sag of the cable is the single most important design parameter and strict attention to cable weight determines the optimal length. The equation of the catenary is the precise model but a parabolic approximation may work. (parabolic approx.) ymax = (3wl?) / ?√(64EA) P = wl?/(8ymax) Where ymax is the maximum sag l is the unstretched length w is the weight/unit length E Youngs modulus A Wire area P axial tension the curve is a parabola, which is a good approximation if the depth of sag is no greater than 1/8th of the span. Use the second equation to derive the induced tension P. H:=WL?/8S S:=WL?/8H L: distance between support S: Sag at mid-span H: tension (horizontal component of tension) The tension depends purely on the loaded geometry and the weight per unit length.

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