Low Frequency Electronic Transformer
- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 800 Pieces pc
- Supply Capability:
- 10000 Pieces per Month pc/month
OKorder Service Pledge
OKorder Financial Service
You Might Also Like
*Electric power Inductor
*High power storage
*Easy insertion,low price
*Used in various electronic and industry products
Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate. We promise to offer the best products to our clients.We look forward to cooperating with all friends for more mutual benefits. |
- Q: A student wants to figure out if an unlabeled item is a capacitor or inductor. He applies a voltage with diferent frequencies and find that as the frequency goes up, the current through the item goes down. Is this a capcitor or an inductor? Why? Thanks for the help! Please explain in detail.
- An easy way to remember the answer is to apply DC (frequency 0) and see what happens: In inductor is simply a coil of wire. If DC is applied, it will be nearly a short circuit, and very high current will flow. As the frequency increases, the current will get lower. A capacitor is simply 2 parallel plates that don't touch, separated by a dielectric. If DC is applied, you will have an open circuit and no current will flow. As the frequency increases, the current will also increase.
- Q: I am looking to install an inductor to install in line with my power connector on the panel of my Celestron CPC 1100. I have had problems with batteries, like those of booster packs. They give out small power spikes and one of those spikes wiped out my RA axis servo firmware. What kind of Inductor can I use? If not what can I install inline to keep the power at 12 volts DC 2 amps with spikes up to 5 amps for slewing. Thank you
- Radio Shack has inductors and noise filters for use with car audio systems. They used to have a kit of parts for $3.99 (270-030). Don't know if it's still available. They should have others, though. Anything along the lines of a voltage regulator will require a voltage source HIGHER than the 12 volts you're looking for. I presume you're using a 12-volt battery source, so your best bet is a noise filter, with perhaps a Zener Diode as a spike clipper I'd use one rated at 15 volts and 1 watt between the filter and the electronics. It's also a good idea to make sure the power switch is turned OFF while the battery pack is being connected. Turn on ONLY after the battery connection is securely made.
- Q: and whyalso does that work when you open circiut a capacitor.
- An ideal inductor appears as a short to DC. Real inductors have some resistance due to the wire they are wound with. Remember the voltage across an inductor V L di/dt if I is constant V 0. An ideal capacitor will appear open to DC. It will charge up to the DC voltage that would appear across it if it were not in the circuit (thevenin voltage). Ic CdV/dt. if V is constant Ic is zero. Electolytic capacitors have some leakage current.
- Q: If an inductor current is 0 for tlt;0 while capacitor is being charged (the switch is on the capacitor side). when for t0 the capacitor is fully charged and switch moves in such a position that both capacitor and inductor are now connected in series. Will the capacitor charge the inductor? what will be the current in inductor for t0?
- If the closing of the switch connects the inductor and capacitor in series into a closed circuit, then the capacitor will discharge through the inductor which will store the energy in its magnetic field. Then the inductor will transfer this stored energy back to the capacitor which will become charged with the opposite polarity (storing the energy in its electric field) and then discharge again in the opposite direction through the inductor. This swinging back and forth of the stored energy between inductor and capacitor will continue indefinitely. With resistance in the circuit (and in practice there is always some) the swings will gradually die out. The undamped swing frequency 2π/√(LC).
- Q: Having a bit of trouble with this question; I'm asked to calculate the time in ms it takes to dissipate 40% of the initial stored energy of an Inductor.I know that the initial stored energy is 62.5 JThe time constant is 50msV 200e^(-20t)I 12.5e^(-20t)I've worted out the above values, but I cannot see how I can work out the time taken for it to discharge 40%, as i keep getting a negative time value.I would be very grateful of any help :)(P.S. I also need the same for a capacitor when I have similar values)
- 0.4 e^(-20t) ln(0.4) -20t t ln(0.4)/(-20) t (-0.916)/(-20) t 0.0458 46ms
- Q: a coil wrapped around a magnet do the same.
- A coil wrapped around a magnet is an inductor.
- Q: How is the ripple factor affected when a variable load is connected to a series inductor filter? My text book doesn't explain it in terms I understand.
- A power supply first rectifies AC, changing it to pulsating DC. A .filter is used to smooth the pulsations to produce DC with no pulsations
- Q: A certain circuit consists of an inductor of 55 mH in series with a resistor of 90 Ω. At a moment when the current in the circuit is 21 A, a switch in the circuit is opened. How long will it take for the current to fall to 7.14 A? Answer in units of s.I thought that this one was easy. first time around I used i(Io)(e^-Rt/L) --- 7.1421e^(-90t/(55x10^-3)) 2.53926105e-4this is wrong. Then based on someone's advise I got on here, I used the equation i(Io)e^(t/-RL) and I got an answer of 5.34.also wrong! Please help! What am I doing wrong? What's the answer??
- 7.14 21 e^ - (R/L)t e^-(90/0.055) t 0.34 e^- (1636.36 t) 0.34 ln both sides : - 1636.36 t - 1.0788 hence t 6.59 x 10^-4 s
- Q: A resistor and an inductor are connected in series to an ideal battery of constant terminal voltage. At the moment contact is made with the battery, the voltage across the inductor isa. greater than the battery's terminal voltage.b. equal to the battery's terminal voltage.c. less than the battery's terminal voltage, but not zero.d. zero.Thanks! :)
- b
- Q: capacitorinductorresistorabove devices work on what, ac current/voltage, dc current/voltage , bothgive answer for each in very very brief.also explain why capacitance of capacitor increases when dielectric is used in terms of electronic current and charges on plates and dielectric.
- Very breifly: Resistors - a gadget that provides 'resistance' to cutting-edge pass. Capacitors - a gadget which could save a cost. Inductors - a gadget that opposes a metamorphosis in cutting-edge.
1. Manufacturer Overview
Location | Shenzhen, Guangdong, China (Mainland) |
Year Established | 2006 |
Annual Output Value | US$2.5 Million - US$5 Million |
Main Markets | North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market |
Company Certifications | CE Certificates |
2. Manufacturer Certificates
a) Certification Name | |
Range | |
Reference | |
Validity Period |
3. Manufacturer Capability
a) Trade Capacity | |
Nearest Port | Shekou,Yantian |
Export Percentage | 51% - 60% |
No.of Employees in Trade Department | 3-5 People |
Language Spoken: | English, Chinese |
b) Factory Information | |
Factory Size: | 3,000-5,000 square meters |
No. of Production Lines | 9 |
Contract Manufacturing | OEM Service Offered Design Service Offered Buyer Label Offered |
Product Price Range | Average |
Send your message to us
Low Frequency Electronic Transformer
- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 800 Pieces pc
- Supply Capability:
- 10000 Pieces per Month pc/month
OKorder Service Pledge
OKorder Financial Service
Similar products
Hot products
Hot Searches
Related keywords