SMD Multilayer Ferrite Chip Bead 0805

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1.SMD multilayer ferrite chip bead

2.High Impedance Characteristics

3.size: 0805

4.RoHs

5.competitive price

Features:

*Low crosstalk/DCR, high reliability

*Low crosstalk between adjacent circuits

*Single MZA series chip provides noise attenuation for four lines, ideal for various highly miniaturized I/D lines

*Internal electrodes feature low DC resistance, minimizing wasteful power consumption

*Electroplated terminal electrodes accommodate flow and reflow soldering

*Mololithic structure ensures high reliability

*Operating temperature range from -25 to 85℃

Applications:

*High-frequency noise counter measured in computer

*Printers

*Portable telephones and other equipments

*VCRs

*Televisions

Q: current under one volt?: Variable inductors are not used very often, but a powdered iron toroid could be used. I would be built something like an auto transformer. Most diodes have less than a volt when forward biased.

Q: 1)50v 1 khz 2)50v 100hz 3)50v dc: 3) because the impedance of the inductor is zero at DC.

Q: Can a capacitor discharge itself through an ideal inductor ? If yes state the reason , if No how will the charge on the capacitor will behave ?: A charged perfect capacitor connected to a perfect inductor will have an oscillating voltage: discharge to 0, recharge to initial charge value with opposite polarity, back to 0, etc. forever. This is a sinusoidal oscillation which takes place at a frequency 1/sqrt(LC) rad/s. The reason for the oscillation is explained in the ref., which discusses such a circuit with added resistance. The resistance absorbs energy and causes the oscillation to damp out over time, but the behavior of the capacitor and inductor are the same without resistance.

Q: A 0.595 H inductor is connected in serieswith a ?uorescent lamp to limit the currentdrawn by the lamp.If the combination is connected to a57.3 Hz, 93.5 V line, and if the voltage acrossthe lamp is to be 26.9 V, what is the currentin the circuit? (The lamp is a pure resistiveload.)Answer in units of A.Please help!!!!: Calculate inductive reactance by formula X(L) 2 (pi) f L 2 *3.14 * 57.3 * 0.595 214.57 ohm Applied voltage 93.5 v. By Kirchoff;s law, this equals voltage drops in R and XL I*XL + I*R93.5 But these 2 voltages have phase difference of 90 deg so they must be added vectorially we know I*R 26.9 I*XL (93.5 ^2 -26.9^2)^0.5 i*XL89.54 i89.54/214.57 0.41733 Amp

Q: (a) How long will it take for the current to reach 67% of its maximum value?(b) What is the maximum energy stored in the inductor?(c) How long will it for the energy stored in the inductor to reach 67% of its maximum value?: oubaas: are you able to describe why for the inductor you do not use the a million-e^even if and for the resistor you do? i'm purely attempting to appreciate the thoughts previously for my midterm. thanks!

Q: and what do you think its should resistance be: An inductor is a coil. It builds up an counter electromagnetic field that increases opposition to current flow as you increase current. The resistance is called inductance. It's variable depending on current pulled through it. Their good for things like filters because any spike in current is opposed by the built up field.

Q: are connected to 240V 50 Hz AC mains. a current of 3A flows lagging 31degrees behind the supply of voltage while the voltage across the inductor is 171V.determine the resistance and inductive reactance.: If I told you how long ago it was when I last did problems like this you wouldn`t believe me! However I am tempted to have a go. For calculation purposes , let 3A current lag by 30 ° rather than the 31 ° you suggest. Also let voltage across inductor be 170 V Vr ? 240 ? - 170 ? Vr 170 V (voltage across resistor) 170/3 R 57? let inductive reactance X ? Voltage across inductance 170 v I 170 / X 3X 170 X 57? I will be pleasantly surprised if this is correct !

Q: 645 Hz. What is the current in the inductor?: in this case IE/XL where XL 2*pi*645*.085h in ohms

Q: How do you do this problem?Using the expression relating the rate at which current changes in an inductor to the voltage produced at it, find the voltage across the inductor when a switch supplying 6.8 A to a 6.5 mH inductor is suddenly opened. Assume that current drops linearly to zero in 3.4 milliseconds.: This Site Might Help You. RE: Voltage across an inductor? How do you do this problem? Using the expression relating the rate at which current changes in an inductor to the voltage produced at it, find the voltage across the inductor when a switch supplying 6.8 A to a 6.5 mH inductor is suddenly opened. Assume that current drops linearly to zero in 3.4

Q: I'll try and explain my confusion as best I can:Lenz's law says that a changing current through a solenoid produces a magnetic field that generates an emf that opposes the current, right?Current through an inductor (when it is constant) produces a magnetic flux that 'favors' the constant current, right?So my question is; when you connect a inductor to a voltage source (DC), what exactly happens while the inductor is resisting the current (or 'charging up')? And what makes it stop?Also, how do you physically explain the phenomenon of an inductor producing a voltage HIGHER than the source it was connected to, when the circuit is rapidly open (please try not to use the calculus of inductors to explain this)?Any help would be hugely appreciated.: Assuming zero resistance, when you connect the battery, the current will start increasing, but only at a rate the generates a back emf equal to the voltage. Theoretically, with no resistance, it will increase for ever. However in actuality the battery will start generating an internal resistance at large currents and there will be a voltage drop across that resistance.

Our products have highest quality and competitive prices.Our well-equipped facilities and excellent quality control throughout all stages of production enable us to guarantee total customer satisfaction. As a result of our high quality products and outstanding customer service, we have gained a global sales network.

1. Manufacturer Overview

Location	Guangdong,China (Mainland)
Year Established	2010
Annual Output Value	US$10 Million - US$50 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe
Company Certifications	ISO 9001:2000

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Export Percentage	41% - 50%
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