Low Frequency Toroidal Needle Insert PCB Mounted Transformer
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- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 1000 Pieces pc
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- 30000 Pieces per Month pc/month
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1.Professional engineer
2.Qualified material competative price
3.small loss
4.usage:power phase:single coil
5.structure:toroidal
6.core dimension:adjustable by clients
7.size:follow customer's request
8.Remark:we can produce it according client's requirement
Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate.We promise to offer the best products to our clients.We look forward to cooperating with all friends for more mutual benefits.
- Q:if i have coupled inductors with mutual inductance M ,how would i go about replacing them with 1 equivilant inductor and what would be its value ?
- An equivalent single X value for the two initial inductances X1and X2, having mutual inductance M, very much depends on how X1 and X2 are connected into a circuit and upon how X is to be connected. There is not a unique answer independent of circuit connection.
- Q:For an ideal conductor in an ac circuit explain why the voltage across the inductor must be zero when the current is at the maximum
- I would answer as i know: From equation V L (di/dt), it tells us something. The nature phenomenon of an ideal or any practical inductor is that it will protect current not to change rapidly.For example, if the current at first condition is 5 Amp. but suddenly you increase it to 6 Amp. the inductor will act aginst the change so it will increase by some amount of time not suddenly increase.The time depend on many factors-induction,etc. At the maximum point of waveform,the current is quite constant.So,it's not nessessary for the inductor to act against the current.The Vol. so would Zero. Does this help?
- Q:A parallel RLC circuit consists of a 3.7 mH inductor, a 4.7 ?F capacitor, and a 1.4 ? resistor driven at 150 Hz:1.) Calculate the reactance of each component at the driving frequency (f 150 Hz, but youprobably want ω).2.) Calculate the impedance Z for this circuit. Remember that you need to use the AC versionof Ohm’s law appropriately, since the current is common.
- L 3.7 mH C 4.7 μF R 1.4 Ω f 150 Hz Reactance of i) Capacitor X_c 1/(2πfC) 1/(2*3.14*150*4.7*10^-6) 225.87 Ω ii) Inductor X_? 2πfL 2*3.14*3.7*150*10^-3 3.4854 Ω iii) Resitor X_r R 1.4 Ω ___________________________ Impedance of circuit Z sqrt((X_? - X_c)^2 - R^2) Z sqrt((3.4854 - 225.87)^2 - 1.4^2) 222.38 Ω
- Q:A. leads the voltage B. is in phase with the voltage. C. is a square wave D. lags the voltage
- The answer is D; current will lag the voltage. Just remember ELI the ICE man. This is the way I was taught to remember this. ELI, E (voltage) leads I (current) in an inductor (L). ICE, I (current) leads E (voltage) in a capacitor (C).
- Q:An RLC circuit contains a 4.100e-6 F capacitor in series with an inductor. What should the value of the inductance be for a resonance frequency of 63.0 rad/s?Do we have to have the Equivalence Capacitance as 1/C, since the capacitor is in series?The formula for Resonance frequency is: omega 1 / (SQRT(L*C))where L ImpedanceC Capacitancebut Capacitance in series would be 1/4.1E-6 F which equals 2.44E5 F.Is this correct so far?OK if so, solving the resonance frequency for L would give: L 1 / C* omega^2omega 63 rad/s soomega^2 3969 rad/sso1 / (2.44E5 * 3969) 1.033E-9is right?! PLEASE HELP!!
- Capacitive reactance, Xc 1/WC Inductive reactance, XL WL At resonace the capacitive and inductive reactance are equal. Xc XL Therefore, 1/W x C WL L 1/(W^2 x C) L 1/(63 x 63 x 4.1 x 10^-6) L 61.45 H. Wow! that's a big inductor. Are you sure W is correct?
- Q:whats the diffrence between a inductor with a medal and a normal inductor?
- Induction with a metal core produces a far stronger force than an inductor with an air core. The metal consolidates the magnetic field lines so they are greatly intensified over just a air core inductor
- Q:A 33.0 mH inductor has a reactance of 2.00 k.(a) What is the frequency of the ac current that passes through the inductor? Hz(b) What is the capacitance of a capacitor that has the same reactance at this frequency? F(c) The frequency is tripled, so that the reactances of the inductor and capacitor are no longer equal. What is the new reactance of the inductor? k(d) What is the new reactance of the capacitor? k
- The impedance (reactance) for an inductor wL where: w is the angular frequency (i.e. w 2 pi frequency) L is the inductance
- Q:Hi, I'm a student majoring in manufacturing engineering. Recently I've received an assignment about finding the manufacturing process of a wide variety of products. One of the product is an inductor. I have search online and on books about high volume manufacturing process of inductor but I couldn't find anything expect a bunch of patents. I'm wondering if any one happen to know how inductor are manufactured in high quantities? Thank you very much for any help.-Calvin
- It is dependent on the type of inductor, but in all cases an inductor is a wire wound in a coil either in air or around a core. High speed manufacture of an inductor would then involve a method of winding the wire around the core in a high speed automated fashion. Much like winding thread onto a spool,
- Q:I'm building a circuit in a program called Cadence and the inductor has a little circle on one side of it but not on the other. So does the inductor have a direction? Should the part with the circle be connected to the voltage source or should the other side be connected to it?
- inductors do not have polarity. .
- Q:Hi,i need help here;
- L 2 henry and R 1/3 ohm Since the switch was in the A position for a long time before it was switched to the B position at t 0, there is no current in the inductor at t 0+ At t 0+, 1 amp V/1Ω + (1/L)(∫ Vdt) The voltage across the inductor will be V(t) 1(e^ -(t/τ) for 0+ ≤ t 2 seconds where τ L/1Ω L since the resistor is 1Ω The current through the inductor will be i (t) (1 - e^-(t/τ) amps from 0+ ≤ t 2 seconds where τ L/1Ω L since the resistor is 1Ω At t 2- seconds i (2-) (1 - e^-(2/L) amps (1 - e^-(1)) since t/τ 2/L 1 at t 2-, L must be 2 Henry At t 2 seconds the switch is thrown back to A. The inductor current will be i( t2+) (1 - e^-1)(e^-(t/τ) where τ L/R 2/R i(6) (1 - e^-1)(e^-(6/τ) (1 - e^-1)(e^-(1) so 6/τ 1 6/(2/R) 3R R 1/3 ohm
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1. Manufacturer Overview |
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| Location | Shenzhen, Guangdong, China (Mainland) |
| Year Established | 2006 |
| Annual Output Value | US$2.5 Million - US$5 Million |
| Main Markets | North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market |
| Company Certifications | CE Certificates |
2. Manufacturer Certificates |
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| a) Certification Name | |
| Range | |
| Reference | |
| Validity Period | |
3. Manufacturer Capability |
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| a)Trade Capacity | |
| Nearest Port | Shekou,Yantian |
| Export Percentage | 51% - 60% |
| No.of Employees in Trade Department | 3-5 People |
| Language Spoken: | English, Chinese |
| b)Factory Information | |
| Factory Size: | 3,000-5,000 square meters |
| No. of Production Lines | 9 |
| Contract Manufacturing | OEM Service Offered Design Service Offered Buyer Label Offered |
| Product Price Range | Average |
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Low Frequency Toroidal Needle Insert PCB Mounted Transformer
- Ref Price:
-
- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 1000 Pieces pc
- Supply Capability:
- 30000 Pieces per Month pc/month
OKorder Service Pledge
Quality Product, Order Online Tracking, Timely Delivery
OKorder Financial Service
Credit Rating, Credit Services, Credit Purchasing
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