Low Frequency Toroidal Needle Insert PCB Mounted Transformer

Ref Price:

Loading Port:: China Main Port

Payment Terms:: TT or LC

Min Order Qty:: 1000 Pieces pc

Supply Capability:: 30000 Pieces per Month pc/month

Inquire Now

Add to My Favorites

OKorder Service Pledge

Quality Product, Order Online Tracking, Timely Delivery

OKorder Financial Service

Credit Rating, Credit Services, Credit Purchasing

You Might Also Like

USB Charger 12V 24V

Home Office Appliance Single Modified Sine Wave 200 Watt 300 Watt UPS Plug

AC Motor Drive

MV Voltage 3KV 6KV 10KV Frequency Inverter

High Voltage 11KV Variable Frequency Drive

High voltage 6KV Converter Frequency

Variable Frequency Drive 3.3KV 630KW VFD

High Voltage Static Var Compensator （SVC）

1.Professional engineer

2.Qualified material competative price

3.small loss

4.usage:power phase:single coil

5.structure:toroidal

6.core dimension:adjustable by clients

7.size:follow customer's request

8.Remark:we can produce it according client's requirement

Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate.We promise to offer the best products to our clients.We look forward to cooperating with all friends for more mutual benefits.

Q: could anyone help me explain and solve the physics question?see the following images ( inculding the answer: Answer is b This question assumes a specific type of inductor. The most simple inductor is the air core coil. In that type the length l of the coil is in the denominator of the expression for L. Thus if the length is half, L is doubled. Therefore a is NOT correct. R/L is half and VL(t) Vm*e^-Rt/L so the charge time IS NOT Doubled. It is longer but not doubled. Energy in the inductor EL 1/2 *L*I^2 is doubled when L is doubled so c is NOT correct The magnetic field in a coil IS proportional to the number of turns of wire per unit LENGTH. Thus the magnetic field in the coil IS DOUBLED too. So d is NOT correct. The answer must be b

Q: Hi, can somebody please help me with this inductor problem? I'm stuck on it and need some help i think that I have the general idea, but need some guidance.: This is a step-value function and will need to be solved piece-wise. For t 0 to 5us: Since I (1/L) Vdt therefore:: I (1 / 2E-3) * 10V * 5us 500 * 10V * 5us 25mA For t 5us to 15us I (1 / 2E-3) * -10V * 10us 500 * -10V * 10us -50mA For t 15us to 20us I (1 / 2E-3) * 10V * 5us 500 * -10V * 5us 25mA The total current from t 0 thru t 20us 25mA -50mA +25mA 0 mA

Q: i am making an Am transmitter and i need a 5 mH inductor for the 1MHz oscillator.: That is a very big coil to make yourself. It is too big to resonate at 1 MHz. About 70 microhenries would resonate with 360 pF at that frequency. It would be easier to get an oscillator coil from an old transistor radio and put about 300 pF across it. If fact it already covers about 1 MHz to 2 MHz with the existing tuning capacitor. If you want to make the coil yourself, use Wheeler's formula: The classic formula for single-layer inductance (air core) is called Wheeler's formula, which dates back to the radio days of the 1920s: L(N^2 times R^2) / ( 9 *R + 10 *H) where: L inductance in micro-Henries N number of turns of wire R radius of coil in inches H height of coil in inches In most countries, transmitters are not permitted on any frequency unless authorised, and especially not in the middle of the AM broadcast band.

Q: An Lc Circuit has an inductance of L 0.020 H and a capacitance C 12 microfarads. The total energy stored in the circuit is E 1.0 Joule.a) what is the maximum magnitude current across the inductor?b) What is the maximum magnitude voltage across the capacitor? c) What is the time interval between the occurrence of maximum magnitude current and maximum magnitude capacitor voltage?Any help would be appreciated. I have an answer for part a and b, however I would like to check that answer and am unsure as to how to solve part c. Thanks!: you in addition to mght prefer the frequency. the internet impedance is the sum of XL and XC which cancel out, so that's going to be inductance under resonance, capacitance above resonance and intensely low at resonance in a sequence circuit. No resistance is a mathematical abstraction, does no longer exist often talking, because it would desire to contain infinity, however the question is incomplete.

Q: An RLC circuit with a capacitance of 0.010 uF is found to resonant with a frequency of 1.30×104 Hz. What is the value of the inductor? Also what are the units of the inductor. Thanks: X ind2TTfL , X cap1/(2TTfC), at resonance,X ind Xcap,2TTfL1/(2TTfC), 4TT^2f^2LC1, L1/(4TT^2 f^2 C)1/[4TT^2 (13000)^2 (0.01 x 10^-6)] L0.014988 henry14.98 mili-henry God bless you.

Q: Does current flow through an inductor if it is connected to a dc source without any other component such as resistance or capacitor?: Yes, the current will rise until it is limited by the source or until the wire of the inductor fuses open.

Q: Almost every circuit I have seen as an rf receiver, it uses inductor and a capacitor as a tank circuit. Why not just use RC circuit with opamps to select a specific frequency and than get desired gain too?: first, op amps don't work well at RF frequencies. Those that do are expensive. second, a frequency filter using only R's and C's has a pretty broad bandwidth, and would not select adjacent channels very well.

Q: I just want to know if i got the general idea of inductors downthey store current energy because when a magnetic field is running through the coils, a current is induced and adds up proportionally to the number of coils? does that explain how inductors store energy?: You are on the right track Are you only interested in stored energy? Have a read of this, Should help!

Q: i know an inductor prevents current from jumping to its maximum. but what happen after that?: I believe that it prevent sudden current changesso it will also prevent the stoppage of electrons once the source is turned off (so current slowly dwindles, instead of turning off like a switch) the inductor does not affect the final steady-state value of the current flowing around the circuit, it certainly does affect how long after the switch is closed it takes for this final current to be established.

Q: I have simple rl circuit two resistance in parallel and a inductor - 5 H in parallel. I need to thevenize the circut but I do not know how to handle with the inductor, wich is in value of 5 Hplease help thank you: RF and 5Henry inductor does not seem to go together. ANyway, R of an inductance can be measured by an ohm meter. I guess what you need is XL which is 2.pi.f.L. Calculate this at the frequency of your choice. Then if an R is across it, the parallel impedance is |RZ/(R+Z)|, where Z j*2.pi.f.L. If XL denotes 2.pi.f.L, then Z jXL, and parallel impednace is R*XL/sqrt(R^2+XL^2)

Our goods sell very well and gain a good reputation from the clients with our production scale, environmentally friendly products, excellent product quality, first-class enterprise management, the most competitive price and perfect service.Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on.

1. Manufacturer Overview

Location	Shenzhen, Guangdong, China (Mainland)
Year Established	2006
Annual Output Value	US$2.5 Million - US$5 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market
Company Certifications	CE Certificates

2. Manufacturer Certificates

a) Certification Name
Range
Reference
Validity Period

3. Manufacturer Capability

a) Trade Capacity
Nearest Port	Shekou,Yantian
Export Percentage	51% - 60%
No.of Employees in Trade Department	3-5 People
Language Spoken:	English, Chinese
b) Factory Information
Factory Size:	3,000-5,000 square meters
No. of Production Lines	9
Contract Manufacturing	OEM Service Offered Design Service Offered Buyer Label Offered
Product Price Range	Average