• Low Frequency Cheap Filter/Iductor System 1
Low Frequency Cheap Filter/Iductor

Low Frequency Cheap Filter/Iductor

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*low frequency Inductor/filter

*High power storage

*Easy insertion,low loose

*Used in various electronic and industry products

 

 

Type

Specification

Inductance

Work Frequency

 

I-TYPE

INDUCTOR

φ1.8×2

1uH-10uH

1KHz-100MHz

φ4×6

1uH-50uH

1KHz-100MHz

φ6×8

1uH-10uH

1KHz-100MHz

φ8×10

1uH-30uH

1KHz-100MHz

φ9×12

1uH-100uH

1KHz-100MHz

φ12×14

10uH-100uH

1KHz-100MHz

φ14×16

10uH-100uH

1KHz-100MHz

φ16×18

10uH-10uH

1KHz-100MHz

φ18×18

100uH-100uH

1KHz-100MHz

φ18×20

100uH-100uH

1KHz-100MHz

φ22×24

10uH-500uH

1KHz-100MHz

remark:we can produce it follow client's requirement

 

 

Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate.We promise to offer the best products to our clients. We look forward to cooperating with all friends for more mutual benefits.

 

 

Q: i'm doing final year BE project on two input boost converter, i'm finding difficulties in design of L and C.
diverse electrolytes have diverse overall performance, yet i think of the .22uF cap from the CRT could desire to paintings. As for the 2N3055, one million.5 amps at 25 volts is 37.5 watts. the suggestion sheet does not record the thermal resistance from case to ambient, yet I heavily doubt it may burn up 37.5 watts and not utilizing a heatsink. in case you seem for it, you are able to probable locate the thermal resistance for a typical TO-3 equipment.
Q: A 3.0A current passes through an inductor. If the inductor stores 19 J of energy, what is the inductance?A) 3.6 HB) 4.22 HC) 85.5 HD) 57 H
The energy stored is E(1/2)LI^2 where E: energy L: inductance I: current so L2E/I^2 L2*19/3^2 L4.22 H
Q: Having a bit of trouble with this question; I'm asked to calculate the time in ms it takes to dissipate 40% of the initial stored energy of an Inductor.I know that the initial stored energy is 62.5 JThe time constant is 50msV 200e^(-20t)I 12.5e^(-20t)I've worted out the above values, but I cannot see how I can work out the time taken for it to discharge 40%, as i keep getting a negative time value.I would be very grateful of any help :)(P.S. I also need the same for a capacitor when I have similar values)
0.4 e^(-20t) ln(0.4) -20t t ln(0.4)/(-20) t (-0.916)/(-20) t 0.0458 46ms
Q: I am making an inductor coil. But I don't have any enameled copper wire, I just have solid copper wire, will this work as a improvisation?
If they are open air coils where each turn does not touch the other, you can use uninsulated wire. If the turns touch, you then need insulated wire, enameled wire the best.
Q: a)A capacitor offers infinite resistance to AC and Inductor to DC b)A capacitor offers infinite resistance to DC and Inductor to ACc)A capacitor offers no resistance to DC and Inductor to DCd) A capacitor offers infinite resistance to DC and Inductor offers no resistance to ACpls send me the correct answer and the reason for the answer ?
B - A cap is a short to AC and an open to DC. While an inductor is a short to DC and an open to AC. The reactance of an inductor is 2*pi*f*l. If frequency is large (AC case) the reactance is also large, like and open. If frequency is 0 (DC case), then the reactance is 0, like a short. For caps, it is just the opposite as reactance 1 / 2*pi*f*C
Q: and what are the possible components.
An inductor is a component that is made from a coil of wire. If a DC current is applied to it, it will pass straight through, since it's just a bunch of wire. However, when the current passes through the wire, it will create a magnetic field around the wire. This will not do anything to a DC current, but if it's an AC current, where the curernt direction is changing and the amount of current rises and falls with the voltage, that magnetic field will also expand and contract. If the wire was straight, this would have no effect, but since it's coiled, the magnetic field caused by the current flow will pass through other coils of wire in that same inductor. Remember that a current flowing through a wire creates a magnetic field? The reverse is also true - a magnetic field crossing a wire will create a current flow, just like in a generator. As the AC current rises and falls in the inductor, the magnetic field expands and contracts, crossing the wires of the inductor, and creating its own currents, which interfere with the input current, which creates resistance to that AC current. The end result is this - a DC current passes through an inductor with no resistance, but an AC current passing through causes resistance. Because the resistance is only for AC, it isn't measured in Ohms, it's measured in Henries.
Q: does it slow down the current or stops the current into the coil?
A most common application of an inductor (sometimes called choke) would be as part of a signal frequency filter
Q: A resistor and an inductor are connected in series to an ideal battery of constant terminal voltage. At the moment contact is made with the battery, the voltage across the inductor isa. greater than the battery's terminal voltage.b. equal to the battery's terminal voltage.c. less than the battery's terminal voltage, but not zero.d. zero.Thanks! :)
At time equal 0+ the inductor voltage is equal to the battery voltage.
Q: Explain the difference between the two quantities.
In a DC circuit the resistance of the componets you speak of are constant: the resistnce, R, will have a value of R Ohms; the capacitance, C, normally has a very high value, say, many Meg ohms; and the Inductor, L, is generally a lowish resistance. In AC circuits however, the resistance of both the capacitor and the inductor change depending on the frequency of the applied ac signal, while that of the resistor, R, still remains constant. It's because the resistance of the capacitor and inductor now depends upon the frequency of the signal that we give it a different name- we call it Reactance. We say that the capacitor has capacitive reactance and the inductor has inductive reactance; both of which are measured in ohms.
Q: Hello. in basic electronics i learnt that : In DC (analysis) , Capacitor lt; open switch. and inductor lt; short circuitIn AC analysis, Capacitor lt; short circuitBut i also learnt that in AC current, Capacitor 's current is i CdV/dt and Zc jXcI also learnt that when at t0, the uncharged Capacitor acts as short-circuit (why?) and after charge(t--infinite), acts as an open circuit.And at t0 , the inductor acts as an open circuit and at t--infinite , inductor acts as short circuitCan you make an explanation to these?
Read your textbook. In particular study the part about exponential charge/discharge. Trying to re-write your textbook here would be nearly impossible (and unnecessary). Doug
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1. Manufacturer Overview

Location Shenzhen, Guangdong, China (Mainland)
Year Established 2006
Annual Output Value US$2.5 Million - US$5 Million
Main Markets North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market
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