• Low Frequency Cheap Filter/Iductor System 1
Low Frequency Cheap Filter/Iductor

Low Frequency Cheap Filter/Iductor

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China Main Port
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TT or LC
Min Order Qty:
1000 Pieces pc
Supply Capability:
10000 Pieces per Month pc/month

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*low frequency Inductor/filter

*High power storage

*Easy insertion,low loose

*Used in various electronic and industry products

 

 

Type

Specification

Inductance

Work Frequency

 

I-TYPE

INDUCTOR

φ1.8×2

1uH-10uH

1KHz-100MHz

φ4×6

1uH-50uH

1KHz-100MHz

φ6×8

1uH-10uH

1KHz-100MHz

φ8×10

1uH-30uH

1KHz-100MHz

φ9×12

1uH-100uH

1KHz-100MHz

φ12×14

10uH-100uH

1KHz-100MHz

φ14×16

10uH-100uH

1KHz-100MHz

φ16×18

10uH-10uH

1KHz-100MHz

φ18×18

100uH-100uH

1KHz-100MHz

φ18×20

100uH-100uH

1KHz-100MHz

φ22×24

10uH-500uH

1KHz-100MHz

remark:we can produce it follow client's requirement

 

 

Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate.We promise to offer the best products to our clients. We look forward to cooperating with all friends for more mutual benefits.

 

 

Q: I live in Canada, markham, ontario. Is there any factory that builds industrial inductors of that many henries? I've been googling but have had no luck. Please refrain from asking why i want it. I just do.I'd appreciate the help. Thanks.
You can't buy an inductor with a value of 1 million henries. It would be huge and extremely heavy.
Q: A 4 mH inductor is connected to an AC voltage source of 149 V rms. If the rms current in the circuit is 0.83 A, what is the frequency of the source?
Use the equation X 2pi*f*L. You are given X indirectly, through V and I. Since I V/X, X V/I. Once you solve for X you can put this in the first equation and solve for f. X V/I 149/.83 179.52 X/(2pi*L) f 179.52/(2pi*.004) 7142.797 Hz
Q: A 0.56-m H inductor stores 3.5×10-5 J when carrying a DC current. What is the magnitude of that current?
3.5×10-5 J (1/2) 0.56 x10^-3 i^2 i 0.356 A
Q: I'm building a crystal radio for my first time. Every example I've seen uses a tube of radius 2 inches around which the wire is wound. My goal is to build something which fits in an altoid container. I'm planning on using magnet wire and a section of a disposable bic pen for my inductor. I'm waiting on which gauge of wire to purchase because I assume the formula takes that into account as wellany suggestions?
Inductance is a function of cross sectional area so if you reduce the cross section you have to increase the number of turns. The approximate formula for an air inductor is L(uH) d^2*n^2/(9N+10L) where d is the diameter, n is the number of turns and L is the length of the winding. So if you decrease the the diameter you'll have to add a corresponding number of turns. A narrower coil will reduce the Q (goodness factor) of the coil as well. If you want to use an Altoid container I'd recommend you use a plastic one and wind the coil around the outside and varnish it, alternatively wind the coil around a roll of card or paper on a ferrite rod. About 88 turns on a ferrite rod (or a toilet roll inner approx 1.5 if you don't use the Altoid container) is good for the AM band, probably need an extra 10+ turns or so if you wind over a bic pen. Try winding 110 turns and tap every ten turns from the 80th turn. Use 24-28 (awg/swg) gauge wire. You can use up to 34 gauge but it's more fragile and the Q of a winding is lower. Other tips, use a decent germanium diode (OA81, IN34 etc.) for your detector and an earphone from an old telephone handset. Crystal sets are completely reliant on a good antenna and a good ground. The ground from a power outlet will work although a ground spike in the earth outside the house is better. The antenna should be the longest wire you can manage, at least 20ft, preferably double that. Before you start coil winding or construction there are a number of crystal radio (sometimes called foxhole radios) kits on Amazon and the like which are quite reasonably priced. It's not by accident they all use large inductors as they give better performance.
Q: 1. At what frequency will a 32.0-mH inductor have a reactance of 660 Ω?2. What is the reactance of a 9.2-μF capacitor at a frequency of (a) 60.0 Hz, (b) 1.00 MHz?3. A 3800-pF capacitor is connected in series to a 26.0-μH coil of resistance 2.00 Ω. Whatis the resonant frequency of this circuit?4. Determine the total impedance, phase angle, and current in an LRC circuit connected to a 10.0-kHz, 1025-V (peak value) source if L 32.0 mH, R 8.70 kΩ, and C 6250 pF.
I'll give you hints, not answers. 1. Z (impedance) of an inductor j2(pi)(f)L 2. Z of a capacitor 1/(j2(pi)(f)C). 3. Set Z capacitor equal to Z inductor and solve for f. But this time, add '2' (without a j) to the impedance of the inductor. 4. Use circuit analysis using the Z's given above. The phase angle is calculated as follows. Ztotal a+Bj phase angle arctan(B/a). Make sure the angle corresponds to the quadrant a and B are referring to. Good luck.
Q: i am an engineer and i want to know what an inductor does because they look really intresting
An inductor allows passage of DC current but resists AC. AC loads become current shifted with respect to voltage by up to 90 degrees in the negative direction. It also stores energy as magnetic energy in it's core when the current is disconnected the magnetic field begins to collapse and the energy is released as an electrical current in the same direction as the original flow. An inductors complement is a capacitor.
Q: I figure if I new what factors effected the frequency I could determin the physics of how it works.
Impedance of inductor Xl 2πfL Impedance of capacitor Xc 1/(2πfC) At resonance: Xl Xc 2πfL 1/(2πfC) (2π)^2 * f^2 * LC 1 f^2 1/((2π)^2 *LC) f 1/(2π√(LC))
Q: And the inductor is in series with a resistor and the battery was connected for a long time
After a long time an inductor acts like a short circuit, meaning all the current flows through the element, and there is no effective resistance. Therefore, the voltage across it would be V 0, as there is no voltage across a short circuit.
Q: 1 )an inductor connected to a dc source, amount of current flow depends ona) dc resistance b) reactance c) inductance2) an inductor in a circuit opposes a) starting current b) stopping current c) AC d) all of the above3) Placing an inductor in series with a lamp that is connected to AC souce wll cause the lamp toa)glow brighter b) burn out c) glow dimmer d) overload the sourceDc resistance of an an inductor is always equal to the inductors reactance. True or falseDc resistance and reactance of an inductor have very different effecs in an AC circuit. True or falsewhen dc is applied to an inductor only the inductor's reactance affcts current flow. True/ False
Presence doesnt advise you will desire to have degree presence. merely ability that persons observe you. once you talk human beings tend to hearken to. And sure even nonetheless you have a social phobia human beings would hear to you basically becuz of ways you look, act or talk
Q: a measured value of 100 ohm and the another has a measured value of 10 Ohm.Which inductor would you choose to use in a circuit where the narrowest possible bandwidth is required and why? A. Use 100 Ohm inductor because it has a higher Q. B. Use the 100 Ohm inductor because it has a lower Q. C . Use 10 Ohm inductor because it has a higher Q D.Use the 10 Ohm inductor because it has a lower Q.
C . Use 10 Ohm inductor because it has a higher Q Q wL/R where w is the frequency in radians per second, L the inductance and R the resistance of the inductor.
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1. Manufacturer Overview

Location Shenzhen, Guangdong, China (Mainland)
Year Established 2006
Annual Output Value US$2.5 Million - US$5 Million
Main Markets North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market
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Nearest Port Shekou,Yantian
Export Percentage 51% - 60%
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Language Spoken: English, Chinese
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Factory Size: 3,000-5,000 square meters
No. of Production Lines 9
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