Aluminium Alloy Model No. 186 for the best quality performance

Aluminium Alloy Model No. 186 for the best quality performance System 1

Aluminium Alloy Model No. 186 for the best quality performance

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Loading Port:: Shanghai

Payment Terms:: TT OR LC

Min Order Qty:: 500 set

Supply Capability:: 5000 set/month

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Wheel Aluminium Alloy Model No. 186 for the best quality performance

Product Description：

1) Lighter than tube wheels makes the car much more oil saving.

2) Better cooling performance in longdistance and high speed driving keeps the car safe enough.

3) Bigger external diameter let the driver feel much more comfortable.

4) High speed lowering tyre termperature can reduce wear resistance prevent tyre-shoulder seperation

Size	ET	CB	Hole	P.C.D	Finish
18X9	-12~+25	87-130.8	5/6/8	114.3-180	BLACK/M.FACE

Production Procedure:

1) Casting Machine Melting & Full Heat Treatment

2) CNC machine CNC made in Taiwan

3) Painting Line Full automatic Painting

4) Quality Control Certifications : JWL.VIA Japanese Standard

Impact fatigue testing

Bending fatigue testing,

Radial run out testing

Dynamic balance testing.

Air-tightness testing

Q: If all connector sizes are known, include steering knuckles, control arm shock absorbers, subframe space geometries.: To calculate, but the calculation is more complex, it is best calculated by commercial software ADAMS, the software comes with McPherson suspension template, enter the hard point position, and then through the virtual suspension test can get the wheel camber, (Ie, the K characteristics of the suspension), if the need to obtain C characteristics, but also the need for elastic components, bushings and other characteristics of the data.

Q: How do you get it? I saw on a website you need to use the wheel over 50% of the time and race in 100 grand prix races. Is this true? Can someone tell me how they got theirs? Thanks: Mario karts is this style of stable sport im a famous person wheel even if it extremely is ranks I even have had it for sometime yet once you replaced into using the numshack it wuld be a golden numshack or perhaps if controller

Q: hey! so i heard this song and i need to know what its called.it goes like and the wheels keep on turnin‘ (and the wheels keep on turnin)its kind of slow, kind of country.help!!!: wheel in the sky by tony banks ? try that.

Q: if i were to get a widebody kit, im assuming i need wheel spacers as well, correct? or is there another way: difficult factor. look into from google and yahoo. that will will help!

Q: I‘m not getting what types of formulas to use for these questions, please post formulas and show work if you provide answer or you can just explain the formula I need to use. Thanks!1. A bicycle with a 28-inch wheel (diameter) travels a distance of 800 feet. How many revolutions does the wheel make (to the nearest revolution)?a. 212 revolutionsb. 103 revolutionsc. 218 revolutionsd. 109 revolutions2. A wheel with a 20-inch radius is marked at two points on the rim. The distance between the marks along the wheel is found to be 3 inches. What is the angle (to the nearest tenth of a degree) between the radii to the two marks?a. 4.6°b. 10.6°c. 6.6°d. 8.6°: 1) The distance a wheel travels in one revolution is the distance around the wheel - otherwise known as circumference. Circumference (diameter)*(Pi) So. 28-inch wheel means diameter 28 So, the distance the wheel covers in one revolution is C 28pi inches Total distance covered: 800 feet 800*12 9600 inches. (total distance covered) / (distance covered in one rev) number of revolutions 9600 / 28pi 9600 / 87.9645943 109.134818 revolutions 109 revolutions (rounded) ************** 2) diameter 2 * radius diameter of wheel 2 * 20 40 inches Find the total circumference of the wheel: C 40pi 125.6637061 inches (partial circum) / (total circum) (angle) / 360 (It's angle/360 because there are 360 degrees in a whole circle.) so. 3 / 40pi x / 360 0.0238732741 x / 360 360(0.0238732741) x 8.594366927 x 8.6 x (rounded)

Q: Alright so we got a 40cm (diameter) 35kg wheel on an incline (22 degree). There is a force pulling the wheel from the top of the wheel. Find a) the required force F (i‘m guessing this means so that the wheel doesn‘t roll down the slope) and b) the minimum coefficient of friction required between the barrel and slope. im thinking for the first part you do moments about the bottom of the wheel (contact section) and find F (components for the moment would be from the force and CG). And then in part B you use that F and do a normal fiction/incline problem. Is this the correct thinking? Cheers: The torque caused by the forces causes the wheel to roll. I choose the pivot point at the point where the wheel touches the incline surface. The component of the weight that is parallel to the incline is causing the wheel to accelerate down the incline. This force is located at the center of the wheel, which is 20 cm from the incline. Force parallel mass * g * sin θ 35 * 9.8 * sin 22 128.5 N The torque caused by this force 35 * 9.8 * sin 22 * 0.20 25.698 N*m This torque causes the wheel to roll down the inline. The force pulling the wheel from the top of the wheel is causing the wheel to accelerate up the incline. This force is located at the top of the wheel, which is 40 cm from the incline. Torque F * 0.40 This torque causes the wheel to roll up the incline. The friction force is located at the surface, so, the friction force produces no torque. Torque caused by force on top of wheel Torque caused by force at center of wheel F * 0.40 25.698 F 64.245 N Force parallel down the incline – Force up the incline 128.5 – 64.245 62.245 N (down the incline) This is the total force is directed down the incline, so the friction force must be directed up the incline. Ff ? * mass * g * cos θ ? * 35 * 9.8 * cos 22 ? * 35 * 9.8 * cos 22 64.245 ? 0.202 Sorry about my math error!

Q: ok so i was wondering are running wheels bad for rats? because the cage i have ordered comes with one. shoulld i take it out?: Yeah, rats love wheels. Just make sure it's large enough for it to run comfortably in.

Q: Why the wheel to be made into a circular axle should be installed where: Axle to the ground from the constant distance only to be able to do ah, or else the shape of the car will have a greater shock. Axial, of course, in the center of the heart ah.

Q: If you have a wheel and axle simple machine, like a doorknob, where would the resistance force, the effort force, and the fulcrum be? Thank you!: confusing stuff. check out from yahoo or google. that will help!