• A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread System 1
  • A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread System 2
  • A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread System 3
  • A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread System 4
  • A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread System 5
A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread

A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread

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Loading Port:
Qingdao
Payment Terms:
TT OR LC
Min Order Qty:
5000 pc
Supply Capability:
6000000 pc/month

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1.Description of Drainage trench cover:

Drainage trench cover is widely used in the urban road, the square, the botanical garden, the wharf, the airport, the parking lot, the road, each kind of industry, the civil project, etc.

 

2.Main features of Drainage trench cover:

 I--Carrying 20 tons of weight

II—Carrying 14 tons of weight

III---carrying 6 tons of weight

IV---carrying 2 tons of weight

V---Carrying pedestrian weight

 

3.Glass Wool Blanket Images:

 A255/40/100 Aluminum Bar Grating For Deck Access Stair Tread

 

4. Drainage Trench Cover Technical Parameters:

 

These drain cover plate applies to the road cross-sectional and longitudinal drain. The drains width ranging from 200mm to 550mm.

A means the steel grating length

H means the steel grating height

A means the frame length

H means the frame height

 

5.FAQ

We have organized several common questions for our clientsmay help you sincerely 

How about your company

A world class manufacturer & supplier of Drainage trench cover is 

one of the large scale professional investment casting production bases in China,consisting of both casting foundry forging and machining factory. Annually more than 8000 tons Precision casting and forging parts are exported to markets in Europe,America and Japan. OEM casting and forging service available according to customer’s requirement.

How to guarantee the quality of the products

We have established the international advanced quality management system every link from raw material to final product we have strict quality test; We resolutely put an end to unqualified products flowing into the market. At the same time, we will provide necessary follow-up service assurance.

 


Q:1100 scope of application of aluminum plate
1100 aluminum plate is generally used in utensils, heat sink, caps, printing plates, building materials, heat exchanger components, but also can be used as deep stamping products. It is widely used in various fields ranging from cooking utensils to industrial equipment
Q:Can the aluminum sheets be used for manufacturing chemical storage tanks?
Indeed, chemical storage tanks can be manufactured using aluminum sheets. Aluminum proves to be a flexible substance with numerous benefits for this particular application. Notably, its lightweight nature, resistance to corrosion, and impressive strength-to-weight ratio make it an ideal choice for securely storing a wide range of chemicals. Moreover, aluminum can be effortlessly molded into various configurations and dimensions, enabling the customization of storage tanks to suit specific needs. Nevertheless, it is crucial to take into account the type and concentration of the chemicals to be stored, as certain substances may potentially react with aluminum. In such instances, it becomes vital to employ appropriate coatings or linings to avert any chemical reactions.
Q:What is aluminum sheet?
Aluminum sheet refers to a thin, flat piece of aluminum that is commonly used in various industries for its lightweight, durable, and corrosion-resistant properties. It can be easily bent, cut, and formed into different shapes, making it versatile for applications such as construction, automotive, aerospace, and packaging.
Q:Are 101 aluminum sheets suitable for chemical storage tanks?
No, 101 aluminum sheets are not suitable for chemical storage tanks as they lack the necessary corrosion resistance for handling and storing chemicals.
Q:How do aluminum sheets perform in terms of dimensional stability?
Aluminum sheets generally exhibit good dimensional stability due to their low coefficient of thermal expansion, meaning they are less likely to warp or deform when exposed to temperature changes compared to other materials.
Q:A solid aluminum sphere has a mass of 83 g.Use the density of aluminum to find the radius of the sphere in inchesExpress your answer using two significant figures.I can't figure this out :(
Aluminum has a density of 2.702 g/cm^3. 83 g x (1 cm^3 / 2.702 g) = 30.7 cm^3 That's the volume of the Al sphere. The formula for the volume of a sphere is V = (4/3)(pi)(r^3) where r is the radius. 30.7 = (4/3)(3.1416)((r^3) 7.33 = r^3 1.94 cm = r 1.94 cm x (1 in / 2.54 cm) = 0.76 inches.
Q:I know aluminium forms a protective layer of aluminum oxide and hence water does not corrodes it easily.However, since the oxide is amphoteric, won't it react with acids and subsequently be dissolved?What is the main reason aluminium cans are used?
because they are light and easy to smash with your hand
Q:Are the aluminum sheets suitable for manufacturing heat exchanger tubes?
Yes, aluminum sheets are suitable for manufacturing heat exchanger tubes. Aluminum has excellent thermal conductivity, corrosion resistance, and is lightweight, making it an ideal material for heat transfer applications.
Q:How does the thickness tolerance of aluminum sheet affect its usability?
The usability of aluminum sheet is greatly influenced by its thickness tolerance, which refers to the acceptable deviation from the specified thickness. This tolerance is typically expressed as a range or a plus/minus value. Having a tighter thickness tolerance guarantees that the aluminum sheet consistently meets the desired specifications. This is crucial in industries such as aerospace, automotive, and construction, where precise dimensions are necessary. Even a slight deviation in thickness can have a negative impact on the performance and functionality of the product. For example, in aircraft manufacturing, the thickness tolerance of aluminum sheets used for structural components is of utmost importance. A thin sheet could compromise the structural integrity, while a thicker sheet could add excess weight, affecting fuel efficiency. Similarly, in the automotive industry, precise thickness tolerance is vital to ensure compatibility and fitment of various components. On the other hand, a looser thickness tolerance may be acceptable in applications where precise dimensions are not as critical. For instance, in general fabrication, signage, or decorative purposes, a wider thickness tolerance may not significantly affect the usability or appearance of the aluminum sheet. Furthermore, manufacturing aluminum sheets with tighter thickness tolerances generally incurs higher costs due to increased precision and quality control measures. Therefore, the desired level of tolerance should be carefully balanced with the intended use and cost considerations. To conclude, the usability of aluminum sheet is directly influenced by its thickness tolerance, particularly in industries that require precise dimensions. Selecting the appropriate tolerance level is essential to ensure that the sheet meets the necessary specifications and maintains the desired performance and functionality of the final product.
Q:A construction worker uses a steel tape to measure the length of an aluminum support column. If the measured length is 17.7 m when the temperature is 21.2°C, what is the measured length when the temperature rises to 35.4°C? (Note: Do not neglect the expansion of the steel tape. Give your answer to three decimal places.)I am really confused... Could someone solve it for me with a step-by-step explanation? Thank you so much.
Assume linear thermal expansion with constant expansion coefficient. The change of length is given by: ΔL = L?·α·ΔT (L? initial length, α linear thermal expansion coefficient) The overall length of an object as function of temperature is: L= L? + ΔL = (1 + α·ΔT) · L? Consider the measurement at 21.2°C as reference: The aluminum column changes its length to L= (1 + α_aluminum · ΔT) · L? = (1 + 23×10-6 ^C°-1 · (35.4°C - 21.2°C) ) · 17.7m = 17.705m That would be the length measured with a steel tape at reference temperature of 21.2°C. Unfortunately the steel tape expands too. Because the scale increases with the expansion it measures too short. On the expanded tape you read the length L? while the actual length is L. Hence the measured length is: L? = L / (1 + α_steel · ΔT) = 17.705m / (1 + 11×10-6 ^C°-1 · (35.4°C - 21.2°C) ) = 17.003m

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