• Single Core LSZH material Insulated Fire retardant Cable 450 /750 V WDZ-BYJ System 1
  • Single Core LSZH material Insulated Fire retardant Cable 450 /750 V WDZ-BYJ System 2
  • Single Core LSZH material Insulated Fire retardant Cable 450 /750 V WDZ-BYJ System 3
Single Core LSZH material Insulated Fire retardant Cable 450 /750 V WDZ-BYJ

Single Core LSZH material Insulated Fire retardant Cable 450 /750 V WDZ-BYJ

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Loading Port:
Shanghai
Payment Terms:
TT OR LC
Min Order Qty:
1000 m
Supply Capability:
30000 m/month

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Single Core LSZH material Insulated Fire retardant Cable 450 /750 V

Production Introduction for Single Core LSZH material Insulated Fire retardant Cable 450 /750 V:

Voltage Rate: 300/500V, 450/750V

Range of Nominal cross section: 0.75 mm2 ~ 630 mm2

Conductor: Class 1/2 Plain annealed copper wires, solid or stranded

Constructions Insulation: XLPE or LSZH material

Core color: Brown, Grey, Black, Blue, Green/Yellow or others on request

Max. Operating Temperature: 70 , can be 90 ,105 and 125 as per

requirement

Packing: 100 meter/roll or as per requirement

 

Application for Single Core LSZH material Insulated Fire retardant Cable 450 /750 V:

These cables is with features of fire retardant, low smoking and halogen free, it is applied to fixed installing with heat resistance requirement of the places with a special demands of flame retardancy, the density of smoke emission and toxic index if the cable is burnt, such as subway, tunnel, nuclear power station, etc.

 

Production Standard for Single Core LSZH material Insulated Fire retardant Cable 450 /750 V:

I EC 60332, IEC 61034, IEC 60754, BS 7211 , HD 22.9, VDE0282, GB/T19666

 

The  Feature for Single Core LSZH material Insulated Fire retardant Cable 450 /750 V:

The cable can be of flame retardance, fire resistance and other property

 

Packing photo for Single Core LSZH material Insulated Fire retardant Cable 450 /750 V:


Single Core LSZH material Insulated Fire retardant Cable 450 /750 V WDZ-BYJ

Single Core LSZH material Insulated Fire retardant Cable 450 /750 V WDZ-BYJ

FAQ For Single Core LSZH material Insulated Fire retardant Cable 450 /750 V:


Q1:What is the Production Capacity for your factory?

About 80 kilometer every day

 

Q2: What is the Minimum Order Quantity For Single Core PVC Insulated Cable 450 /750 V?

MOQ: 10000 meters for small size, 5000 meters for middle size, 1000 meters for big size

 

Q3:What is the delivery time for these cables?

10~15 working days

 

Q4: What standards is the product complying with?

    We can produce thousands of electric wires and power cables complying with different standards, such as: GB, JB , IEC, BS, AS/NZS, VDE, UL ETC.



Q: I need power cables for my sony laptop
Go search online or maybe buy at your local computer shop :)
Q: Whether the weight of the power cable per meter is calculated
12 meters below the road should be used to protect the tube, the use of rigid PVC pipe protection of course, but not necessarily have to wear armored cable
Q: how can i calculate the current carrying capacity of a power cable when the area is given?can you give me a table on this?
Table 310.16 of the NEC (2008)
Q: Copper and Aluminum are being considered for the cables in a high-voltage transmission line where each must carry a current of 50A. The resistance of each cable is to be .15ohms per kilometer.A. If the line carries power from Niagra Falls to New York (500Km), mow much power is lost along the way in the cable? Compute for each choice of cable materialB. the necessary cable diameterC. mass per meter of cable Please correct if you see anything that may be offSolving for part a:Power = I deltaV, since deltaV was not given IR=deltaVso Power = (I^2)R = 50^2 x 75 = 187.5 kW lt;-- answerR= 75 since R= .15 ohms/ km x 500kmB) resistivity of copper = 1.7 x 10^-8 ohm m resistivity of al = 2.82 x 10^-8 ohm m R = (resistivity x length)/Areawhat do i use for R? is it the 0.15 ohm/km or 75 ohm?using the 75 ohm as R, I get that the radius of the copper wire is 0.0000361 m and the diameter is then 0.0000722.Am i on the right track?
a) Power = (Current) (Voltage) = (Current)^2 / (Resistance) You got it good job b) I would rearrange your equation a bit to minimize computation. R = (resistivity x length) / Area Therefore (R / l) = (rho) / A They give you (R/I) = 0.15 ohms/km and they give you rho. Just solve for A. Your way of doing the calculation in bits (finding R and then finding A) is good, too, though. I didn't actually check your numbers. The only pitfall would be forgetting to convert km to m.
Q: is it a power cable? parallel port?
Well the Cable to your Monitor Connects to the Video Card Port, which connects to the motherboard.
Q: YJV-0.6 / 1KV-5x16 What does it mean? What does it mean? 1KV refers to what? 5 if it means 5 core, which 5 core refers to a 16mm2 cable has 5 core?
It does not look good, but also affect the wallpaper, wallpaper, in full swing, and then from the chain reaction, then it is worthless, it is recommended to use decorative decorations decorated, perhaps alone for more suitable wallpaper pattern or color ... that does not affect the wallpaper Can also play a decorative effect ... Thank you
Q: 10KV power cable can be with 380v low voltage power cable co-laying which specification which article description more
Can not! "Power Cable Design Code" Article 5.1.3 provides that the number of stents by the channel space constraints, 35kV and about the adjacent voltage level of power cables, can be arranged in the same layer of stent. 10kV power cable (actually 8.7 / 10kV) and 380V power cable (actually 0.6 / 1kV) in the interval between the 6kV and 3KV two voltage levels, not the adjacent voltage level, can not!
Q: I got a free graphics card from my cousin and my computer only has the SATA slots for graphic cards and the one he gave me has the 4 Pin cable. Is there anyway to get it converted or any cables that can go from 4 Pin to sata? I wanna see how this graphics card goes when its working fully.
Sure you don't have any molex connectors at all? Not even in your DVD drive? If so, get a Y adapter with a good amount of length. If not, then look for an adapter. Be careful as the vast majority are to convert a molex power cable to a SATA power connector, not the other way around. In the worst case you could hook up a separate power supply to it.
Q: And if so how much would that cable be and could you supply a link to get it from that place?Im really struggling to find any details of where i can get one so could you possibly check out the item and see if there is any help on there?I currently have a 3A 250v Power cable and i'm wondering if that can help?Thanks alot and if it helps ill pick a best answer soon. Thank you!
High input cable ...? Not really sure what that is, Also, that power supply is junk. 750W and it only has a single 6-pin PCI? That's sad. Good 750W power supplies are at least ?70 and have four 6-pin PCI cables. Heck, a good 430W costs more than that and it's guaranteed to perform better.
Q: Two things:1.) Why when we're using an AC to step up the voltage the power has to remain constant?2.) Why is it if we increase the voltage by a factor of 100 we have to decrease the current by a factor of a hundred and therefore I^2R is decreased by a factor of 10,000
Power is generated at the power station and transferred to the end user your home by means of power cables. Unfortunately, some power is always lost in this transfer process. It's power NOT Voltage OR Current that is required to operate your home electrical appliance. Yes, current and voltages are involved ;but it is the PRODUCT of these two that makes up the power NOT the voltage or current individually. Power = Voltage x Current Power is lost in the cables as heat as given by your i^2R. To reduce the losses then we must reduce the current I. But, if I reduce the current and keep the voltage the same then the power will fall and my kettle/Xbox/curling tongs will no longer work at home. So, to keep the power up when reducing the current I must compensate by increasing the voltage and this means using a step up transformer. Near the homes, a step down transformer is used to reduce it back down again. Since the losses in a cable are a consequence of I^2R heating then it is important to reduce the current as much as possible when transferring power. If we assume the the resistance, R of the cable is constant, then a 10,000 reduction in power (power/10,000) gives P/10,000 = I^2 x R I^2 = Power/10, 000R I = square root of [const x 10,000] I = 100. Then using power = voltage x current reducing the current by 100 means increasing the voltage by 100 to keep the power the same.

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