Hot Dip Galvanized Steel Wire For Razor Wire

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Commercial Galvanised Steel Wire

(1) Quality : Meet GB/T 343 standard and other requirements of relevant standards .

(2) Zinc Coating: Meet GB/T 15393 standard and other requirements of relevant standards .

(3) Raw Material : Wire rod ——1006 , 1008 , 1018 , Q195 , etc, and zinc with 99.995% purity.

(4) Tensile Strength Range

(5) Application : Used in wire mesh , artware , metal hose , binding for agriculture and construction , etc.

(6) Packing

(7) Zinc Coating

Meet GB/T 15393 standard.

Q: I have DirectWay and have a wireless router. I recently hardwired my computer in because I kept losing signal. The distance between my computer and the router is about 30 ft. But since I hardwired my computer in, it seems slower than when I ran the wireless adapter, i.e downloading videos and music. I was under the impression that wired was faster. What gives????: wired or wireless, you are capable of downloading way faster than whatever the cap is on your internet service

Q: wiring for generator: There are only two ways to hook up a generator to a house. The right way and the wrong way. While the wrong way may work, it is unsafe, illegal and actually could kill someone down the line. The safe, proper and legal way is to install a transfer switch. WARNING!!!!!!!!!!!!!!!!!!!!!!!!!! I have seen the local power company sue people for liability because they hook up the generator to the dryer's receptacle and when the back-feed hit the transformer down the line, it killed the pperson who working to restore the power. PLEASE, if you do this, do it the legal way. Good luck and may God bless!

Q: Some states allow the use of aluminum wire in houses in place of copper. If you wanted the resistance of your aluminum wire to be the same as that of copper, would the aluminum wire have to have a greater diameter than, smaller diameter than, of the same diameter as the copper wire? Calculate the thickness ratio of aluminum to that of copper.: The resistivity of copper is ρ_Cu = 1.72 x 10^(-8) ohm - meters, whereas that of aluminum is ρ_Al = 2.82 x 10^(-8) ohm-meters [1]. Assuming that the wire runs are the same length L, the resistance in the aluminum wire will be R_Al = ρ_Al * L/A_Al, where A_Al is the cross-sectional area of the aluminum wire. The resistance in the copper wire will be R_Cu = ρ_Cu * L/A_Cu. If we want the same resistance in both wires, we require R_Cu = R_Al: ρ_Cu * L / A_Cu = ρ_Al * L / A_Al A_Al / A_Cu = ρ_Al / ρ_Cu. Since the resistivity ρ_Al of aluminum is higher, the aluminum wire must have a larger cross sectional area to yield the same resistance. To make this precise, suppose the wires are cylindrical. Then the cross sectional area is π(R_Al)? for the aluminum wire and π(ρ_Cu)? for the copper wire: π(R_Al)?/π(ρ_Cu)? = ρ_Al / ρ_Cu R_Al/R_Cu = √(ρ_Al / ρ_Cu) = √(2.82/1.72) = 1.28 The aluminum wire must be 28% thicker than the copper wire in order to provide the same resistance.

Q: A load of 125 kip is being held by 3 wires all going up. The Wire one goes straight from the load to the horizontal. Wire 2 and 3 form a V on top of wire 1 and are 30 degrees from wire 1. This is a 2-D problem.: You need to use summation of forces. Wires 1 and 2 are gonna have the same tension on them, just in opposite directions. so in the x direction, Fx=125cos(30)+125cos(150) (the vertical wire doesn't contribute to the x-direction forces and I choose 150 because the wire on the left really has an angle of 180-30 or 150) in the y direction, Fy=125sin(30)+125sin(150)+125sin(90) (The vertical wire is a 90 degree angle) Tension=sqrt( Fx^2 + Fy^2 )

Q: Is there special speaker wire in order to run 250 watts max rms or will the oem speaker wire in the car be sufficient (did not originally have an amp and is most likely at 50 watts max rms). If I need a special wire for that please let me know what it is called and possibly an example link. Thanks!: most likely the wire pre ran in the car was 16 guage wire which is fairly small id recomend atleast 12G for speakers and 8G for a power wire.

Q: Question about the 3.5mm cable, I cut it open and there are 4 individual wires inside of it. I've only ever seen 2 wires and a loose one. Which ones are right/left and would the other 2 both be ground?The colors are red/green/white/black. I'm assuming the red/white are right left like normal? But I'm not too sure.: do you mean an audio cable?

Q: What are the types of Barbed wires?: Barbed wire is barbed wire as far as I am concerned. Otherwise google barbed wire manufacturers and see what they can supply.

Q: Wires in the dash*Radio constant*Radio Switched*Radio illumination**please match these up with the options below**Wires on the stereo itself*Dashboard Light Dimmer Switch*Amplifier Remote or Power Antenna (Positive +)*(fuze) yellow memory (negative -)*(fuze) red 12v (positive +)if someone could please help that would be great-since the wires were replaced i cant go by color: Car radio wire constant to stereo yellow memory. Car radio wire switched to stereo red 12v positive. Car radio wire illumination to stereo Dashboard Light Dimmer Switch. Don't forget to ground the black wire on the unit to the ground wire from the car harness. An extra ground strap to the chassis is a good idea also. If you don't have an amp or a power antenna, cap off the blue Remote/Antenna wire.

Q: 2.4) A wire has a resistance of 19.2 . It is melted down, and from the same volume of metal a new wire is made that is 5 times longer than the original wire. What is the resistance of the new wire?: .4) A wire has a resistance of 19.2 . It is melted down, and from the same volume of metal a new wire is made that is 5 times longer than the original wire. What is the resistance of the new wire? Resistance = ρ * (L ÷ A) ρ = resistivity L = length A = cross sectional area L * A = volume of wire. The volume is constant L1 * A1 = L2 * A2 It is melted down, and from the same volume of metal a new wire is made that is 5 times longer than the original wire. Since the length is 5 times longer, the area is 1/5th of the original volume Resistance2 = ρ * (5L ÷ 0.2A) = ρ * 25 * L/A The new resistance is 25 times the original resistance = 25 * 19.2 = 96 Ω

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