PBP Series Shielded SMD Power Inductor

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1. pbp series shielded smd power Inductor

2. Rated current:0.5-10A

3. Inductance0.5~6000uH

4. Quality assured

5. competitive price

smallest possible size and high performance they are with high energy storage

Feartures:

The Surface Mount Inductors are designed for the smallest possible size and high performance,

They are with high energy storage and very low resistance making them the ideal inductors for

DC-DC conversion in the following application.

Q: Hi, I'm a student majoring in manufacturing engineering. Recently I've received an assignment about finding the manufacturing process of a wide variety of products. One of the product is an inductor. I have search online and on books about high volume manufacturing process of inductor but I couldn't find anything expect a bunch of patents. I'm wondering if any one happen to know how inductor are manufactured in high quantities? Thank you very much for any help.-Calvin: It is dependent on the type of inductor, but in all cases an inductor is a wire wound in a coil either in air or around a core. High speed manufacture of an inductor would then involve a method of winding the wire around the core in a high speed automated fashion. Much like winding thread onto a spool,

Q: An inductor of 210 turns has a radius of 3 cmand a length of 16 cm.The permeability of free space is1.25664 x 10^-6 N/A^2.Find the energy stored in it when the cur-rent is 0.5 A. Answer in units of J.: your credit score is not good due to your age, there are things that will help you build up your credit score, like a mobile phone contract, club books, never going overdrawn in the bank and generally making regular payments on everthing that you have. however, take a little advice from a man that knows and has been around for a long time,.never have credit from anywhere, anytime. save your money, buy the things you need and never owe a penny to another person. you will never worry, it cannot get worse, the bailiff will never call and you will find that life is a whole lot easier. you may have to wait for the things you want until you have saved enough and you may be jealous of your friends when they get the latest gadget six months before you do but later in life, they will be struggling to make payments and you?? you will be quite comfortable with life and owe nothing to nobody. okay, i sound old and boring but hey, if it helps you, who cares lol

Q: I want to answer as many of my science questions as I can during the spring break so I can put the information to use.: The inductor-capacitor (LC) combination picks (selects) a particular wave frequency in two different ways. If connected in series their capacitance and inductance values can be selected such that their individual impedance is equal to each other`s and their combined impedance to the selected frequency is zero ohms. This will allow the selected (picked) frequency to pass through the LC combination with no impedance while at the same time it will present a high impedance to all the undesired frequencies above or below the selected frequency. Hence the output of the series connected LC combination would be the place where the picked (selected) frequency would be predominantly available. If connected in parallel their capacitance and inductance values can be selected such that their individual impedance values are equal to each other. At these values their combined impedance will be approaching infinity to the selected (picked) frequency. This parallel combination will offer maximum impedance to the selected frequency and a lesser impedance to the frequencies above and below the selected frequency. Hence the input of the parallel connected LC combination would be the place where the selected (picked) frequency would be predominately available.

Q: A 10 ohm resistor and 10 henry inductor are attached in series to a 10 volt DC supply. If the current i(0)2.5 amperes, what is the current after 1 second? Round in the tenths place.I got 1.55 but that isn't right.: Question doesn't make sense. Current after a long time would be 10/10 1 amp, where just the resistance would be relevant. Current when the supply is first turned on will be less, not more than 1 amp.

Q: A 288.0 mH inductor is connected across the output terminals of an AC generator that is delivering an output voltage of 135.0 mV rms. What is the alternating current through the inductor if the frequency of the emf is 0.084 kHz? What is the alternating current if the frequency of the generator is changed to 1.09 kHz?: X 2πf*L 2π*0.084*1000*0.288 152Ω I V/X 0.135/152 888?A ----- 888*1.09//0.084 11,525?A 11.5mA -----

Q: A fixed inductance L 1.07 ?H is used in series with a variable capacitor in the tuning section of a radio telephone on a ship. What capacitance tunes the circuit to the signal from a transmitter broadcasting at 6.90 MHz?answer in pFhow to solve this would be great :) a few step by steps maybe Thanks!: Why 2pi?

Q: A 10 H inductor has a resistance of 5ohms. The inductor is connected in series with an open switch. The supply is 10v dc. A 'bleed' resistor of 20 ohms is connected in parallel with the coil. What is the time taken for the inductor current to reach 2assuming initial switch on: I suspect that the 20 ohm parallel resistor confused the picture for you. However, the 20 ohm, parallel resistor is independent of the current through the inductor, and therefore is not considered in this calculation. The current flow through the inductor is modeled as an independent, RL circuit with 5 ohm resistor in series with the 10 H inductor. The reasoning is that the current through this RL branch is only dependent on voltage across the series resistance and inductor. In the ideal parallel circuit, the voltage across the RL branch is source voltage at time t 0+ (instant of switch closure). Analyze the time dependent current as you would a simple RL circuit with the 5 ohm resistor in series and ignore the 20 ohm resistor. Analysis: V(t) V(r) + V(L) V(r) i * R V(L) L(di / dt) V(t) i * R + L(di / dt) i(t) (V/R)(1 - e^(-Rt / L)) then solve for 't' with i 2 amperes.

Q: I want to find the total impendance of a coil. I think I know how to do it but I'm not sure.Z X + RX 2(pi)wLL (uAN^2)/lZ is impendance, R is resistance of the wire of the coil, X is the reactance, w is current frequency in hertz, L is inductance, u is permeability of the core, A is area of the coil loops, N is number of turns in coil, and l is the length of the coil.Together this would yieldZ (2(pi)wuAN^2)/l + RWould this be correct?: All these formulas only apply to a sine wave single frequency. Z is from ohms law if you have measured V and I: Z + V/I Ideally Z is stated as a vector |Z|, which means a magnitude in ohms and a phase angle in degrees. If X and R are known: Z + sqrt(R^2 + X^2). This is using trigonometry to account for the resulting direction of the vector (phase angle) of the two components R and X. Some calculations involving power, voltage, impedance and current are easier using vectors and trigonometry, while others are easier using complex numbers (real and imaginary component). Complex numbers have a set of rules for arithmetic using them. Adding them as for two impedances in series is very straight forward. Z as a complex number is R + jX The following formulas allow for converting from one representation to the other. PF (Power factor) true power / apparent power cos(θ) from trig. θ arccos(PF) |Z| V / I with a phase angle (θ) Rseries |Z| cos(θ) Xseries |Z| sin(θ) Z R + jX |Z| sqrt(R^2 + X^2) where X is the net reactance of XL and Xc. θ arctan(Xs / Rs)

Q: Explain the difference between the two quantities.: Impedance can have both resistive and either inductive or capacitive components (in electrical engineering-speak, we give the impedance as a complex number for a given frequency).

Q: a measured value of 100 ohm and the another has a measured value of 10 Ohm.Which inductor would you choose to use in a circuit where the narrowest possible bandwidth is required and why? A. Use 100 Ohm inductor because it has a higher Q. B. Use the 100 Ohm inductor because it has a lower Q. C . Use 10 Ohm inductor because it has a higher Q D.Use the 10 Ohm inductor because it has a lower Q.: C . Use 10 Ohm inductor because it has a higher Q Q wL/R where w is the frequency in radians per second, L the inductance and R the resistance of the inductor.

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1. Manufacturer Overview

Location	Guangdong,China (Mainland)
Year Established	2010
Annual Output Value	US$10 Million - US$50 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe
Company Certifications	ISO 9001:2000

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