Low Frequency High Quality Coil/Inductor

Ref Price:

Loading Port:: China Main Port

Payment Terms:: TT or LC

Min Order Qty:: 3000 Pieces pc

Supply Capability:: 3000 PiePieces per Week pc/month

Inquire Now

Add to My Favorites

OKorder Service Pledge

Quality Product, Order Online Tracking, Timely Delivery

OKorder Financial Service

Credit Rating, Credit Services, Credit Purchasing

You Might Also Like

Muti-functional Inverter with Battery Charger 1500 Watt 12V 220V

Frequency Inverter

0.4KW~3.7KW Single Phase AC Motor Drive

90KW AC Motor Use Converter Frequency

0.4KW~800KW CMAX Control AC Motor Inverter Frequency

CE Approved CMAX Inverter Frequency

AC/DC Adapters 12V with Line SAA Certificate

AC/DC Adapters with Line BS, UK Certificate

Specifications

1.Radial Fixed Leaded Inductors with Inductance ranging from 0.30uH to 100mH.

2.ROHS compliance.

3.Good quality and low price

4.low loose

Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate. We promise to offer the best products to our clients. We look forward to cooperating with all friends for more mutual benefits.

Q: An electric lamp is connected to battery an inductor .How can you change the intensity of lamp without changing current or voltage in coil ?: Since you have a battery the inductor will have only a transient influence on the circuits current. An equivalent circuit for an inductor is its resistance in series with its inductance. V(t)R i(t) + L di(t)/dt + R(lamp) i(t) R- resistance of the inductor R(lamp)- resistace of the lamp L - inductance Once the steady state is established we will have V(t)R i(t) + R(lamp) i(t) Opening or shortening the winding will collapse or induce the field. Fast collapse of the field can produce a high voltage spike However I would not recommend an inductor a dimming control in a DC circuit.

Q: How can I make inductors ?: You can make inductors my winding an insulated wire around a suitable core. The core is usually air or carbon. Use appropriate formula to calculate how many turns you need. Make sure that the wire is insulated. Hope this was helpful.

Q: Hello,i need some help solving this one. i'm kind of lost of which formula to apply. Thanks so much for your help. Answer Key (B) A 45-mH inductor is connected to an ac source of emf with a frequency of 400 Hz and a maximum emf of 20 V. The maximum current is:A) 0B) .018 AC) 1.1 AD) 360 AE) 2300 A: The reactance (XL) of an inductor is given by: XL 2πfL where f is the frequency in Hz and L is the inductance in henrys. XL 2π * 400 * 45/1000 XL 113 ohms Now it is just Ohm's Law i v / XL i 20 / 113 i 0.177 A i ≈ 0.18 A { I suspect a typo for answer (B) it should be 0.18 A }

Q: I can't find ferrite beads in the local market, can I disassemble normal ferrite inductors (coils) and use their cores as ferrite beads ?: It's possible, but the inductance of the bead will be small compared to a typical core inductor. Use a very small core.

Q: Before the switch is closed in a circuit consisting of a 4μC capacitor and 0.2 H inductor, the potential across the capacitor is 200 V. At some instant after the switch is closed, the instantaneous current is 0.7 A. What is the energy in the capacitor at this instant?Answer: 31.0 mJPlease show steps. Thank you.: Power in watts equals volts x amps

Q: A 0.3268 mH inductor has a length that is four times its diameter.If it is wound with 11.8 cm?1 turns per centimeter, what is its length?Answer in units of m.: If wire-wound with 11.8 turns/cm 11.8/0.01 1180 turns/m The inductance is given by; L ?o N? ? A ? 4d A ? π d? (1/64) π ?? L (4πx10^-7) (1800)π?? 0.3268x10-? ? ?√{(0.3268x10-?)/(0.0071) 0.358 m

Q: and what are the possible components.: just basicly, an inductor is a passive electronic component that stores energy as a magnetic field. In it's simplest form an inductor is made up of a coil of wire. The inductance measured in henrys, is proportional to the number of turns of wire, the wire loop diameter and the material or core the wire is wound around.

Q: How do you do this problem?Using the expression relating the rate at which current changes in an inductor to the voltage produced at it, find the voltage across the inductor when a switch supplying 6.8 A to a 6.5 mH inductor is suddenly opened. Assume that current drops linearly to zero in 3.4 milliseconds.: The voltage across an inductor is given by: v L di/dt You're told that the current drops linearly to zero (from 6.8A) in 3.4ms. So you can write the current as: i 6.8 - 2000t The slope (-2000) can be found fairly easily, it's just 6.8A divided by 0.0034 seconds, you can check to see that the formula works properly (i.e. the current at t0 is 6.8A, and at t3.4ms is 0). So now, just take the derivative of 'i' with respect to 't', and plug it into the formula for the voltage across an inductor and you have your answer. You should get a voltage of -13V.

Q: I have been searching for inductors for a 2nd order crossover and can't find exact matches, only close matches. How much will my crossover be affected if I use a 3.3 mH inductor instead of a 3.2 mH inductor? What about using a 5.0 mH inductor instead of a 5.2 mH inductor for the second one? Will it be that noticeably and undesirably affected?: The tolerance on the inductors is likely to be ±5%; the tolerance on the capacitors is more likely to be ±10%. 3.3mH is out by +0.3% from 3.2mH and 5.0mH is out by -4% from 5.2mH. It'll probably sound fine. You could even add a few extra turns (1 more for every 50: the inductance is proportional to the number of turns squared, so increasing turns by 2% will increase inductance by double that, i.e. 4%) on the 5mH inductor, or stick a piece of ferrite rod down the middle if it doesn't.

Q: At a given instant the current through an inductor is 50.0mA and is increasing at the rate of 115 mA/s. What is the initial energy stored in the inductor it the inductance is known to be 60.0mH, and how long does it take for the energy to increase by a factor of 10 from the initial value?: Energy in an inductor 0.5 L I^2 0.5 (60 x10^-3)(50 x10^-3)^2 7.5 x10^-5 J 7.5 x10^-4 J 0.5 (60 x10^-3) I^2 I SQRT [ 7.5 x10^-4 J / 0.5 (60 x10^-3) ] 1.58 x10^-1 Amps 158mA increase needed 158mA - 50mA 108mA time 108mA /115mA/s .939 sec

Our goods sell very well and gain a good reputation from the clients with our production scale, environmentally friendly products, excellent product quality, first-class enterprise management, the most competitive price and perfect service.Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on.

1. Manufacturer Overview

Location	Shenzhen, Guangdong, China (Mainland)
Year Established	2006
Annual Output Value	US$2.5 Million - US$5 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market
Company Certifications	CE Certificates

2. Manufacturer Certificates

a) Certification Name
Range
Reference
Validity Period

3. Manufacturer Capability

a) Trade Capacity
Nearest Port	Shekou,Yantian
Export Percentage	51% - 60%
No.of Employees in Trade Department	3-5 People
Language Spoken:	English, Chinese
b) Factory Information
Factory Size:	3,000-5,000 square meters
No. of Production Lines	9
Contract Manufacturing	OEM Service Offered Design Service Offered Buyer Label Offered
Product Price Range	Average