Low Frequency High Quality Coil/Inductor

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Specifications

1.Radial Fixed Leaded Inductors with Inductance ranging from 0.30uH to 100mH.

2.ROHS compliance.

3.Good quality and low price

4.low loose

Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate. We promise to offer the best products to our clients. We look forward to cooperating with all friends for more mutual benefits.

Q:A inductor L is in series with a resistor R50 ohms, and the series combination is across the 120 V rms, 60 Hz power line. If the rms voltage across the resistance R is 90 V, (I) what is the rms inductor current? (ii) Calculate the inductance L(i) VI (XL)---I90/50---I1.8 A(ii) (Vo)^2Vr^2+(VL-Vc)^2 is where I am confused. I asked my professor and he said use 2(pi)fL to helpI also calculated VL---120^290^2+VL^2. VL79.37 V rms: You ve calculated the RMS voltage of the inductor. Now you need to find the impedance of the inductor. XL ωL 2πfL Now the voltage equation for the inductor XL * i(RMS) V(RMS) 2πfL * i V L V / (2πfi) L 79.37 / (2 * π * 60 * 1.8) L ≈ 0.117 H 117 mH

Q:If R 7 ohms L 22 mH and V 95 volts, what is the voltage across the inductor at 1T?: TL/R. If you apply a 95 volt step to a series R L circuit the voltage, across the inductor will be 95 e^(-t/T). At tT the voltage will be 23.92 volts.

Q:A battery, switch, resistor, and inductor are connected in series. When the switch is closed, the current rises to half its steady-state value in 2.0ms.How long does it take for the magnetic energy in the inductor to rise to half its steady-state value?My work:the time constant for the circuit is: L/R 2.9ms-I used the equation i(t) E/r ( 1 - e ^ -RT/L)It asks for time it takes for Magnetic Energy of inductor to rise to half its steady-state value.and the only equation i know that works is U .5LI^2 but i cant use it since i dont know L or I.Please help.: U (0.5) LI^2 (1) Question is to find time when it becomes U/2 Now from the above equation, you can find I when U becomes U/2. Let it be I' U/2 (0.5)LI'^2 (2) Taking ratio of (1) and (2), 2 (I/I')^2 I' I/√2 Now we have to find time when I becomes I/√2 given that I becomes I/2 in 2 minutes I/2 E/r [1 - e^(2/2.9)] and I/√2 E/r [1 - e^(t/2.9)] Taking ratio, √2 [1 - e^(t/2.9)] / [1 - e^(2/2.9)] 1 - e^(t/2.9) √2 [1 - e^(2/2.9)] - 1.40 e^(t/2.9) 2.40 t (2.9) ln (2.40) 2.54 minutes.

Q:i'm an older brother who just wants to build his little brother a fairly decent sound system for his car (he just got his licence and dad bought him a second hand car). odd thing is, my bro likes it more if i build him stuff rather than buy them for him. now, i've seen all the formulas, guides, calculations, ohms, farads and self help guides but I cant make heads or tails about it considering i'm an architecture student and numbers and crud like that confuse me to no end. i'm pretty good when it comes to building the enclosures but i'm crap at the electronics stuff. i've already got a set of subs that dad bought (200 watts each) and another set that a cousin gave me (50 watts each) and they're all 10 inches wide. can anyone help me? what kind of inductors and capacitors do need to for both the 200 watts set and the 50?: Hifonicgts Goliath XX-3212 3200 RMS great woofer dude, audio AQ3500D.a million Amplifier is what i might cautioned to you, a pal have those amplifier on 2 of the 18 inch DC audio XL sequence 1500 watts RMS slightly dude is loud as hell at one ohm load. beat like loopy, yet I nevertheless think of that hifoncis goliath is sicker for amplifiers.

Q:A 94 mH inductor is connected to a outletwhere the rms voltage is 127 V and the frequency is 42 Hz.Determine the energy stored in the inductorat t 8.9 ms, assuming that this energy iszero at t 0.Answer in units of J: Do inductors store energy? Man! I dont think so!

Q:An inductor of 170 turns has a radius of 8 cm and a length or 30 cm. The permeability of free space is 1.25664 x 10^-6 N/A^2.Find the energy stored in it when the current is 0.6 A.: Inductance of a solenoid, air L ??N?A/Ln Ln is length in meters A is area in meters? N is number of turns ?? is the magnetic constant 1.2566×10?6?H/m (or T·m/A) use the above formula to calculate inductance. Change units to meters. then use E ?LI? Energy in an inductor to get the energy. .

Q:I'm a little confused about AC power.If a circuit has only resisters in it, then it's easy to calculate the total resistance of the circuit and from that the current and power. But does putting capacitors or inductors in a circuit change the resistance of the circuit, and thus change the average power being dissipated? I think the answer is yes, but it's a little confusing because I read that capacitors and inductors are reactive elements and draw no power?: Theoretically inductors and capacitors draw no real power, but in the real world there is a tiny sometimes a significant power loss that is resistive. Most motors have an inductive component. CFL lights are somewhat capacitive, I think. Some times we add capacitors to improve the power factor. This makes transformers and power lines, and maybe the giant alternators at the power plant more efficient. Neil

Q:and are connected in parallel. The mutual inductance between the two inductors is M1H. Determine the equivalent inductance (in H) for this system.: With mutual inductance the combined inductance is more complicated to calculate M1H 1/Ltotal ( L1 + L2 - 2(M)) / (L1L2 - M^2) 1/Ltotal (7-2) / (10-1) 1/Ltotal 5/9 Ltotal 1.8 H See also this page for future reference

Q:An inductor is connected in series with the parallel connection of another inductor - capacitor. How to find the resonance Frequency and other parameters of the circuit? Any website / application for assistance?: You can estimate this by looking at it as a parallel tuned circuit and a series tuned circuit. The C and L in parallel will resonate at a frequency given by: F^2 25330 / (L * C) where F is MHz , L is uH and C is pF This will be a maximum impedance point. The single L will also resonate in series with the C at a frequency given by the same equation F^2 25330 / (L * C) where F is MHz , L is in uH and C is in pF This will be a minimum impedance point. Don't forget to take the square root to get frequency. eg a 20uH inductance is placed in series with a 30 uH coil which has a 1000 pF capacitor across it. Series circuit : F SQRT( 25330/(20 * 1000)) 1.125 MHz Parallel Circuit: F SQRT ( 25330 / (30 * 1000)) 0.919 MHz

Q:help me to know the basics of tapping an inductor: For small air-core inductors there are a couple of methods that I have used. 1. Wind 10 turns and carry the end lead out about 1 inch away from the coil, then carry the wire back next to the 1 inch lead, back to the coil and continue winding for another 30 turns. Scrape off the insulation of the double-wire lead and use that as the tap. 2. Wind 10 turns. Scrape off the insulation at the 10th turn, leaving an opening to solder a wire on the coil. Continue winding 40 turns. Solder a wire onto the scraped off opening for use as the tap. I like the first method best, but both will work. .

Our goods sell very well and gain a good reputation from the clients with our production scale, environmentally friendly products, excellent product quality, first-class enterprise management, the most competitive price and perfect service.Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on.

1. Manufacturer Overview
Location	Shenzhen, Guangdong, China (Mainland)
Year Established	2006
Annual Output Value	US$2.5 Million - US$5 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market
Company Certifications	CE Certificates

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3. Manufacturer Capability
a)Trade Capacity
Nearest Port	Shekou,Yantian
Export Percentage	51% - 60%
No.of Employees in Trade Department	3-5 People
Language Spoken:	English, Chinese
b)Factory Information
Factory Size:	3,000-5,000 square meters
No. of Production Lines	9
Contract Manufacturing	OEM Service Offered Design Service Offered Buyer Label Offered
Product Price Range	Average