Low Frequency High Quality Coil/Inductor

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Specifications

1.Radial Fixed Leaded Inductors with Inductance ranging from 0.30uH to 100mH.

2.ROHS compliance.

3.Good quality and low price

4.low loose

Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate. We promise to offer the best products to our clients. We look forward to cooperating with all friends for more mutual benefits.

Q: Here is the question:Two ideal inductors (.10 H, .50 H) are connected in series to an ac voltage source with amplitude 5.0V and frequency 126 Hz.a) What are the peak voltages across each inductor?b) What is the peak current that flows in the circuit?I know that you use V IXL *L is subscript*.I don't know if you are supposed to use rms in the equation like Vrms Vpeak/1.4 (square root of 2).Any help would be greatly appreciated and showing me the work/equation you are using. I am just generally confused lt;. Thanks a lot.: The question ask for peak voltages and peak current. So I don`t think you have to worry about RMS values especially since the source voltage was not specified to be peak or RMS. The voltage across the .1H coil .1H / ( .1H + .5H ) x 5V .83V The voltage across the .5H coil .5H / ( .1H + .5H ) x 5V 4.17V Assuming the 5 volt ac source is sinusoidal then X of L (2 PI) x (frequency) x (inductance). The total impedance 6.28 x 126 x .6 475 ohm The current Voltage / impedance The circuit current 5V / 475 ohm 10.5 miliamps

Q: Can you please help me about this question?: After a large time has passed, for a constant e(t), capacitor current 0 inductor current e(t)/R

Q: and whyalso does that work when you open circiut a capacitor.: Remember that when a component is shorted, the situation is effectively the same thing as taking a wire from one terminal of the component to the other. That is, it's like having a wire in parallel with the component itself. Current flows through the short (or wire) instead of through the component. This is as true in AC circuits as it is in DC circuits. So if an inductor (or any other component) is shorted, then any component in parallel with it will also be shorted because it will also not have any current flowing through it. Components in series will not be shorted provided the short starts at one of the inductor's terminals and ends the other.

Q: Does the voltage in the circuit start at applied voltage with no current then voltage drops and current increases? Is this because there is a voltage drop across the coil and its magnetic field?: in a inductor free electrones r pesent when current is passed through it the free electrones start moving in a definite direction,this causes magnetism.

Q: A 10.2*10^-6H inductor with negligible resistance and a resistor are the only elements in a circuit in which a current is flowing.What must be the value of the resistor so that the current will decrease to 50.0% of its maximum value in 1.10ms ?: I Io e^(-t/τ) and τ L/R Given I/Io 0.5 e^(-1.1e-3/τ) Taking log to the base e and Solving we get τ L/R 0.00158690 R 10.2 /0.00158690 6428 ?

Q: A battery (V-9V) is connected with a resistor R1000 ohms and an inductor L 0.5mH. The circuit initially contains an open switch and at t 0, the switch is closed.a) what is the time circuit?b) Determine the Maximum current flowing in the circuit: The time constant for an RL circuit L/R (remember that L*Amps/second Amps*R so L/R has units of seconds). L/R 0.5e-3/1e3 0.5e-6 s R/L 2e6 2,000,000 After a long time an inductor is modeled as a short circuit when the current is a maximum V/R V/R 9/1000 9e-3 A 9 ma. iL(t) 9ma*[1-e^-t/(L/R)] 9ma*[1-e^-Rt/L] 9ma*[1-e^-2,000,000*t] After 5 time constants 2.5e-6 e^-2e6*2.5e-6 e^-5 iL(5*L/R) iL(2.5e-6) 9ma*(1-e^-5) 8.94ma which is 99.33% it's maximum value after only 2.5μs

Q: How do you measure whether an inductor works or not by using a multimeter?: a million. Inductor is purely a coil of twine that's frequently used to cut back EMF. In radios, inductors are used to regulate frequency. extensive inductors referred to as shunt reactors are used to cut back distribution grid voltage whilst skill intake decreases. 2. In radios, inductors are used alongside with capacitors on top of issues circuits to regulate frequency. 3. A relay is a coil and switches. whilst the coil is energized via a collection off (such as you pushing a button), electric contemporary passes by means of the coil and the generated magnetic container reasons the switches (contacts) to alter state. Open ones close, and the closed ones open. 4. ICs are miniature committed circuits using semiconductors.

Q: I want to find the total impendance of a coil. I think I know how to do it but I'm not sure.Z X + RX 2(pi)wLL (uAN^2)/lZ is impendance, R is resistance of the wire of the coil, X is the reactance, w is current frequency in hertz, L is inductance, u is permeability of the core, A is area of the coil loops, N is number of turns in coil, and l is the length of the coil.Together this would yieldZ (2(pi)wuAN^2)/l + RWould this be correct?: All these formulas only apply to a sine wave single frequency. Z is from ohms law if you have measured V and I: Z + V/I Ideally Z is stated as a vector |Z|, which means a magnitude in ohms and a phase angle in degrees. If X and R are known: Z + sqrt(R^2 + X^2). This is using trigonometry to account for the resulting direction of the vector (phase angle) of the two components R and X. Some calculations involving power, voltage, impedance and current are easier using vectors and trigonometry, while others are easier using complex numbers (real and imaginary component). Complex numbers have a set of rules for arithmetic using them. Adding them as for two impedances in series is very straight forward. Z as a complex number is R + jX The following formulas allow for converting from one representation to the other. PF (Power factor) true power / apparent power cos(θ) from trig. θ arccos(PF) |Z| V / I with a phase angle (θ) Rseries |Z| cos(θ) Xseries |Z| sin(θ) Z R + jX |Z| sqrt(R^2 + X^2) where X is the net reactance of XL and Xc. θ arctan(Xs / Rs)

Q: Act as a hpf?And why does everyone use inductors in series with speakers for low pass filters and not a cap in parallel? Caps are a fraction of the cost: PARELLEL AN INDUCTOR TO THE TWEETER SPEAKER HELP TO REMOVE LOW FREQNCY AWAY.

Q: If there is an inductor of 600 mH in a 140 V, 45 Hz AC power line, what is the current in the circuit?: Inductive reactance (2pi FL) 169.67Ω. Remember L must be in H., and F in Hz. Current (E/R) 140/169.67, 0.825A., or 825mA. approx.

Our goods sell very well and gain a good reputation from the clients with our production scale, environmentally friendly products, excellent product quality, first-class enterprise management, the most competitive price and perfect service.Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on.

1. Manufacturer Overview

Location	Shenzhen, Guangdong, China (Mainland)
Year Established	2006
Annual Output Value	US$2.5 Million - US$5 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market
Company Certifications	CE Certificates

2. Manufacturer Certificates

a) Certification Name
Range
Reference
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3. Manufacturer Capability

a) Trade Capacity
Nearest Port	Shekou,Yantian
Export Percentage	51% - 60%
No.of Employees in Trade Department	3-5 People
Language Spoken:	English, Chinese
b) Factory Information
Factory Size:	3,000-5,000 square meters
No. of Production Lines	9
Contract Manufacturing	OEM Service Offered Design Service Offered Buyer Label Offered
Product Price Range	Average