PBH Series SMD Power Inductor

Ref Price:

Loading Port:: China Main Port

Payment Terms:: TT or LC

Min Order Qty:: 1000 Pieces pc

Supply Capability:: 20,000 Pieces per Day pc/month

Inquire Now

Add to My Favorites

OKorder Service Pledge

Quality Product, Order Online Tracking, Timely Delivery

OKorder Financial Service

Credit Rating, Credit Services, Credit Purchasing

You Might Also Like

Low Frequency High Quality Coil/Inductor

Color Loop Inductor

Low Frequency Copper Wire Only Chock Coil

Low Frequency Electronic Transformer

Ferrite Chip Inductors

PBP Series Shielded SMD Power Inductor

Muti-functional Inverter with Battery Charger 1500 Watt 12V 220V

Home Office Appliance Single Modified Sine Wave 200 Watt 300 Watt UPS Plug

1. pbh series smd power inductor

2. Rated current: 1-10A

3. Inductance0.5~6000uH

4. ROHS

5. competitive price

Features:

1.SMD Power Inductor

2.Magnetic shieled surface mount inductor with high current rabing low D.C resistance

3.Excellent terminal strength

4.Packed in embossed carrier tape and can beused by automatic mounting machine.

5.Various hogh power inductors are superior to be high saturation for suiface mounting.

Applications:

Power supplu for VTR,OA equipment Digital camera, LCD television set notebook PC,

portable communication equip,ents, DC/DC converters, etc.

Q: Also ,when there are two capacitors and two inductors in a circuit,how do I calculate the resonant frequency ?: Inductance of a wire is ??L/8π ?? is the magnetic constant 1.2566e-6 H/m (or T·m/A) L is length in meters Inductance of a hollow cylinder is (??L/2π)(ln((2L/a)–1) a is the radius. thickness is negligible. 2) depends on how they are connected. Combine the two caps as series or parallel, ditto inductors.

Q: A coil has an inductance of 0.80 H and a resistance of 41 . The coil is connected to a 5.0 V ideal battery. (a) When the current reaches half its maximum value, at what rate is magnetic energy being stored in the inductor? (b) When the current reaches half its maximum value, at what rate is energy being dissipated? (c) When the current reaches half its maximum value, what is the total power that the battery supplies?: An inductor might no longer likely keep magnectic capability. It converts electric powered capability flowing with the aid of it to magnectic capability. If the electricity flow is stopped, the magnectic field colapses (like Jis4Jenius Jerald pronounced above). it extremely is termed an inductor using fact a changing magnetic field around the cord (or coil) induces electricity into it.

Q: I have built a basic telegraph to test the inductor on my scope to verify what I have been taught. I wrapped my coil around a drill bit from bottom to top in a clockwise direction with the negative lead on the bottom, positive on top. I connect the battery positive directly to the top of the coil ( positive) and the negative battery to the key switch, from the switch to the lower end of my coil. I expected as the switch was closed and current was increasing that the coil will attempt to keep it the same ( zero) by reducing the voltage by an equal amount while it is building its magnetic field. However, I am seeing a positive spike rather than a negative and I do not know why. I have connected my scope negative to the bottom of the coil ( negative) and positive to the top of the coil ( positive). Like i said, I expected a negative spike in voltage, but i am seeing a positive spike which reduces to the positive battery voltage. Please Explain ?: It is a bit difficult to visualize the experimental setup, but what I would expect that you see is this: when you close the key, the voltage across the coil should rise rapidly to the battery voltage, as the current increases, limited only by the coil and battery resistance. The scope will measure the sum of the voltage due to the coil inductance and the coil resistance, the voltage due to inductance will quickly deline to zero, and the voltage will approach the battery voltage asymptotically. Life gets much more interesting when you open the key: the current flowing through the inductor attempts to flow through the opening key contacts and will produce a spark, and you will see a large voltage spike on your oscilloscope. Figure out what the polarity should be, and see if that is what you get.

Q: Faradays law characterizes the voltage drop across an inductor asVL L di/dt where VL voltage drop (V), Linductance (in henrys; 1 H 1 V s/A), i current (A), and t time (s). Determine the voltage drop as a function of time from the following data for an inductance of 4 H: Use VLL di/dt. You should be able to figure out what di and dt are for each interval.

Q: I just have a quick question; I was reading an Engineering book, and I came across the following statement:If the rise in time of the signal is so fast that the current through the inductor increases very rapidly, producing appreciable voltage drop.I know that the voltage across an inductor is: V L(di/dt), so why would a smaller amount of time create a voltage drop? According to my understanding of that equation, shouldn't the voltage increase?Perhaps it has been too long since I have had Calc I.Thank you.: Your book is not very good. I'm not sure what it means by rise in time. If the current is increasing swiftly in shorter intervals of time then the voltage increases dramatically. You are correct in your thinking. lim dt--0 (as di--large values) di/dt infinity

Q: Find the induced emf when the current in a 47.5 mH inductor increases from 0 to 521 mA in 17.1 ms. Any help would be appreciated. If you are able to answer this one, please show your work. Thanks!: v L di/dt di/dt is the rate of change of current, or put another way, the change in current over time. You can see that this is (0.521 - 0)/(0.017 - 0) If the units are Amperes, Seconds, and Henrys on the right, the formula will produce Volts on the left.

Q: A resistor (R3000.0 ohms), a capacitor (C 0.400 micro F) and an inductor (L 5.00 H) are connected in series across a 440.0 Hz AC source for which change in V maximum 125 V. a) find the impedance of the circuit.b) find the maximum current delivered by the source.c) find the phase angle between the current and the voltage.d) Write a sentence describing the relationship between the current and the voltage in the circuit.e) find the maximum voltage across the resistor.f) find the maximum voltage across the capaitor.g) find the mazimum voltage across the inductor.h) find the resonat frequency of the cirsuit.i) find the rms current in the circuit at resonance.j) find the average power delivered to the circuit. Does anyone know how to do any of these or can tell me what formulas to use and how to use them i would really appreciate it!! Thank u!!: The formulae aren't that hard.? They're especially easy in a series circuit. First, we need to talk about omega (ω).? Omega is the angular frequency of a sinusoidal waveform, and it's equal to 2πf where f is the frequency in Hertz.? This allows you to express e.g. the applied voltage as 125 sin (ωt). Next, impedance.? Impedance can either be resistance (in phase with the current) or reactance (90° out of phase with the current).? Reactances are measured in imaginary ohms (yes, imaginary numbers!).? The convention is to represent √-1 as the letter j. The reactance of a perfect inductor is jωL The reactance of a perfect capacitor is 1/(jωC) Note that 1/j -j, so capacitive reactance is the opposite of inductive reactance. Now, to get the reactance of your series circuit you just calculate the reactances of the parts and add them all up.? Add the resistor, the inductor and the capacitor like this: Z 3000Ω + 880πj*5H + 1/(880πj*0.4μF) or, after noting that 1/j -j, Z 3000Ω + 880πj*5H - j/(880π*0.4μF) This will give you a complex number for Z, in ohms.?That's (a) The maximum current is the maximum voltage divided by the magnitude of Z.? That's (b). The phase angle is the angle of Z relative to the real axis, where inductive reactance (positive j) is lagging phase and capacitive reactance (negative j) is leading phase.? That's (c). That should get you going.

Q: Hi,I just wanted to clarify something I am struggling to understand. I understand the concepts of AC and DC, but not capacitors and inductors.Why is it that Capacitors block DC current, but accept AC? Also, how do capacitors store energy from AC?Similarly, why do inductors short in DC, and how do they store energy?THANKS!: As a caveat, i might upload that cutting-edge would not circulate. cutting-edge is the circulate of chage, so asserting cutting-edge flows is the right same element as asserting the charge circulate flows. i be attentive to it sounds style of insignificant, yet information the version might help you.

Q: An air-filled cylindrical inductor has 2600 turns. It is 2.4 cm in diameter and 28.5 cm long.(a) What is its inductance? _____________H(b) How many turns would you need to generate the same inductance if the core were filled with a material instead of air? Assume the magnetic permeability of this material is 1700 times that of free space. _________turns: hyperphysics.phy-astr.gsu.edu/hba a) Solenoid length 28.5 cm with N 2600 turns, Coil radius r 1.2 cm gives area A 4.52389 cm2. Relative permeability of the core k 1 (air) Then the inductance of the solenoid is B 0.013484 Henry 13.484 mH. b) Number of turns 2600 / √ 1700 63 turns hyperphysics.phy-astr.gsu.edu/hba Goodbye

Q: A 16.0 mH inductor, with internal resistance of 20.0 ohms, is connected to a 110 V rms source. If the average power dissipated in the circuit is 40.0 W, what is the frequency? (Model the inductor as an ideal inductor in series with a resistor.) ____ HzI keep getting 467 Hz but this is incorrect and have no idea what I am doing wrong. I've tried doing it a bunch of different ways but keep getting lost somewhere along the way.Any suggestions on how to accomplish this problem?: 1 mH 10^(-3) H current power / voltage 40 W / 110 V 0.3636 Amps voltage Henries * current / time 110 V 1.6 * 10 ^ (-2) H * 0.3636 Amps / time Isolate time: time 1.6 * 10^(-2) H * 0.3636 Amps / 110 V 5.2887 * 10^(-5) seconds frequency inverse of time 1/(5.2887 * 10^(-5)) 18908 Hz I probably made a mistake in there somewhere. I don't remember how to factor in internal resistance or if that's even necessary for this problem.

Our products have highest quality and competitive prices.Our well-equipped facilities and excellent quality control throughout all stages of production enable us to guarantee total customer satisfaction. As a result of our high quality products and outstanding customer service, we have gained a global sales network.

1. Manufacturer Overview

Location	Guangdong,China (Mainland)
Year Established	2010
Annual Output Value	US$10 Million - US$50 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe
Company Certifications	ISO 9001:2000

2. Manufacturer Certificates

a) Certification Name
Range
Reference
Validity Period

3. Manufacturer Capability

a) Trade Capacity
Nearest Port
Export Percentage	41% - 50%
No.of Employees in Trade Department
Language Spoken:
b) Factory Information
Factory Size:
No. of Production Lines
Contract Manufacturing	OEM Service Offered Design Service Offered Buyer Label Offered
Product Price Range