wing nut series/building material 5

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Model Number:	10/12 15/17 20/22
Type:	Scaffolding Parts	Scaffolding Part Type:	tie rod wing nut	material:	QT450-10
specs:	15/17	tensile strength:	above450Mpa	percetage elongation:	above10%
surface finish:	electro galvanized	paking:	bags and pallet	payment:	30% in advance, balance against the B/L copy
customizable:	available	MOQ:	1000 pcs

Packaging Detail:	bags and pallet
Delivery Detail:	3 days

wing nut series/building material
high quality reasonable price
process: sand casting
surface :electro galvanized

wing nut series/building material

formwork wing nut, tie rod wing nut

product mechnical properties:

Castings of superior quality produced from electric furnace instead of cupola furnace

most suppliers use,thus ensure the homogeneity and stability of the composition and

reduce the casting defects to minimum.all material properties including composition,

tensile/yield strength,elongation conform to the Chinese Standard GB QT450-10 (DIN

GGG450/NF FGS450-10).

Material: ductile Iron QT450-10

Process: sand casting

Tensile Strength: ≥450Mpa

Percentage Elongation: ≥10%

Surface Finish: electro galvanized

Packing: Bags and Pallet

payment: 30% in advnce ,balance against the B/L copy

MOQ:1000pcs

Q: Erection of scaffolding accessories: When the scaffolding height of more than 20m, should be in the scaffolding outside every 4 steps to set a level of reinforcement bar, and even walls should be in a horizontal layer set pieces; set of longitudinal reinforcement bars should be continuous, and the formation of the level of closed loop; on the bottom step lower door frame scaffolding should be sealed in the mouth bar, door frame and should be located on both sides of long rod should adopt sweeping bar; fastener rack pole fastened by. Construction should pay attention to the door frame and accessories should not be mixed with the same hand rack.

Q: looking for a scaffolding job in dubai can anyone help?: Hi okorder , we are Dubai based scaffolding contractor.

Q: In the U.S.I live in Illinois as well so... yeah :DThank you!: Location Pierced through from the top rim and coming out on the side rim Procedure can be pierced as two separate piercings and then a long barbell fitted when healed , though more successful and comfortable when pierced straight through initially , the barbell then fitting comfortably as guaranteed to line up exactly This can be multiple pierced with barbells sitting parallel to each other, or designed to sit diagonally forming a cross as well as even being placed vertically from Helix to the lobe. These are only possible where the main cartilage shape of the ear does not protrude preventing a straight passage for the jewellery to sit comfortably. Procedure Needle piercing Complications As there are two piercings and each has the potential to swell a barbell at least 4mm larger than the ear is required to allow for swelling

Q: Cells from an animal's muscles are processed with chemicals and they grow. The cells are transferred to a metal scaffold and are stimulated physically. In a few months, you have a big block of meat which can be ground and cooked. What do you have to add? Does this innovation mean the price of meat will become a very minor expense?: Sounds weird. When eaten I wonder how this experiment would affect the human body. It just might turn normal people into Liberals. If that's the case then I don't want anything to do with it.

Q: What is the bowl buckle scaffolding, bowl buckle scaffold what are the characteristics: (1) main componentComponent for forming the main body of a scaffold. The vertical rod and the top rod are respectively provided with two kinds of specifications, and both sides of the rod are welded with a lower bowl buckle with a spacing of 600mm. If the vertical rod and the ejector rod are matched with each other for long use, the utility model can form an arbitrary height scaffold. Take a long pole, the joints should be staggered, the top layer and then leveling rod length two.

Q: Where can I source scaffolding steel/aluminium planks with rubber end caps?I am having much difficultly finding anything, can you assist?Thank you in advance.: Maybe something like a window washers scafolding planks...?

Q: Scaffolding Vertical Standard, Length: 3000mm, Part Number AS1001: Please okorder Type ‘Aluminum Scaffolding+supplier+your location’ into its ‘Search’ panel, and click on ‘Enter’. Several pages of site listings giving details and links of suppliers who offer Aluminum Scaffoldings in, or near, your locality will be presented to you. Contact them, one by one, and then choose the supplier who suits your specific needs best. Happy hunting !

Q: A 520 kg box sits 1.4 m from the left end. What is the tension in the right hand side wire? (g = 9.8 m/s2) ____________ Newtons: Because the scaffold is not moving, we can assume that the net Torque acting on the scaffold equals zero. Net Torque = 0 torque = Force x distance (d) Use the left end of the scaffold as the center point. This will eliminate the Torque caused by the left wire (d = 0, so torque = 0) There are now three forces creating torque on the scaffold. There is the weight (m x g) of the scaffold, at 3.5m from the left end. m1 x g x 3.5m There is the weight of the crate, located 1.4m from the left end: m2 x g x 1.4m These two torques are countered by the torque caused by the Tension (T) of the right wire, located 7m from the left side. T x 7m The sum of these torques is zero. (T x 7m) - (m1 x g x 3.5m) - (m2 x g x 1.4m) = zero solve for T T = ((m1 x g x 3.5m) + (m2 x g x 1.4m)) / 7m T = ((115kg x 9.8m/s^2 x 3.5m) + (520kg x 9.8m/s^2 x 1.4m)) = 1.58 x 10^3 N Hope this helps.

Q: He pushes a can over the scaffold at 15 meters and it takes 3.25 seconds for it to land.I keep doing the problem over and over. the Correct answer is 20.5 m/s, however I keep arriving to the solution of 17 m/s. I solved it by doing Vf^2 = Vi^2 + 2adwhere the initial velocity is zero and the acceleration is -g. I made my coordinate system so that down is negative in which the distance will be negative. This however, did not give me the correct answer. Am I right or is the book right?: The initial velocity is not zero since the scaffold is moving upward when the can gets pushed over. And final velocity, vf, does not represent the speed of the scaffold (if that is what you're trying to solve). y = (vo)(t) - (1/2)gt? 15 m = (vo)(3.25 s) - (1/2)(9.81 m/s?)(3.25 s)? vo = +20.5 m/s

Q: So im a guyAnd I might get oneAnyone had one before/got one?Any advice?How much do they normaly cost?if you answer this i will love you forever :): okay, if you do end up getting it, make sure you get it on the side you DONT sleep on. dont let shampoo get on it. be really careful with it. if you have longer hair dont let your hair get caught in it cause it'll get tangled on it and it'll hurt and tug on the bar. it's usually around 40 dollars for it. this piercing requires a long time to heal and it has a high risk of infection. but if you take good care of it, you'll be good (: hope this helpedd.

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