• Stored Program Repeat Operation Controller Q03UDVCPU CPU Module System 1
  • Stored Program Repeat Operation Controller Q03UDVCPU CPU Module System 2
  • Stored Program Repeat Operation Controller Q03UDVCPU CPU Module System 3
  • Stored Program Repeat Operation Controller Q03UDVCPU CPU Module System 4
  • Stored Program Repeat Operation Controller Q03UDVCPU CPU Module System 5
Stored Program Repeat Operation Controller Q03UDVCPU CPU Module

Stored Program Repeat Operation Controller Q03UDVCPU CPU Module

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Loading Port:
Shanghai
Payment Terms:
TT OR LC
Min Order Qty:
1 kg
Supply Capability:
1000 kg/month

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Specification

function:
stored program
Type:
CPU moudel

Mitsubishi q series universal high speed CPU module q03udvcpu product
specification


[control mode] stored program repeat operation
[input / output control mode] refresh mode (input / output of direct access
mode can be carried out by specifying direct access mode input / output (DX □,
Dy □))
[program language (sequence control program control language)] relay symbol
language, logic symbol language, melsap3 (SFC), melsap-l, function block,
structured text (st)
[processing speed (sequence control program instruction)] LD x0 1.9ns; MOV D0
D1 3.9ns
[constant scanning (function for keeping scanning time constant)] 0.5 ~ 2000ms
(can be set in 0.1ms) (according to parameter setting)
[program capacity] 30K steps (120K bytes)
[memory capacity]
. program memory (drive 0): 120K bytes
. memory card (SD) (drive 2): the capacity of SD memory card (SD / SDHC) that
can be installed (up to 32g bytes)
. standard RAM (drive 3)
When the extended SRAM cartridge is not used: 192K bytes
When using extended SRAM cartridge: capacity when not using extended SRAM
cartridge + capacity of extended SRAM cartridge (maximum 8m bytes of extended
SRAM cartridge)
. standard ROM (drive 4): 1025.5k bytes
. CPU shared memory: 8K bytes
High speed communication area between multiple CPUs: 32K bytes
[maximum number of stored files]
. program memory: 124
. memory card (SD)
SD: 512 root folders and 65534 subdirectories at most
SDHC: 65535 root folders and 65534 subdirectories at most
. standard ram: 323 when using / not using the extended SRAM card box
. standard ROM: 256
[maximum number of intelligent function module parameters] initial setting
4096, 2048 when refreshing
[write times of program memory] 100000 times at most
[number of writes to standard ROM] up to 100000 times
[number of input and output software components (number of points can be used
in the program)] 8192 points (x / Y0 ~ 1fff)
[I / O points (accessible points of actual I / O module)] 4096 points (x / Y0 ~
FFF)
[specification of built-in Ethernet port of CPU]
. data transmission speed: 100 / 10Mbps
. communication mode: full duplex / half duplex
. transmission method: baseband
. maximum distance between hub and node: 100M
. maximum number of nodes / connections: up to 4 levels for 10Base-T series
connection and up to 2 levels for 100base-tx series connection
. number of connections: 16 socket communication, melsoft connection and MC
protocol in total, 1 for FTP
[latch (hold point) range] l0 ~ 8191 (default value: 8192 points) (the latch
range can be set for B, F, V, t, St, C, D and W) (set through parameters)
[run / pause contact] one point of run / pause contact can be set in x0 ~ 1fff
(through parameter setting)
[allowable instantaneous stop time] 0.58a (CPU module body) / 0.6A (when
installing extended SRAM card box)
[overall dimension h * w * D] 98 * 27.4 * 115mm
[weight] 0.2kg

Q: How do you test this transformer with a multi-test meter? It was in a gong style door bell system. The 'clanger' unit has two windings withe the striker arm parallel to the end of the windings. Elaborate please. parts are difficult at my location.
Are you testing the transformer or the door bell solenoid coil? If it's the transformer: 1. ANY transformer has to be AC doesn't it? 2. 16V. x 10A. 160VA. 3. With your multi -tester set for continuity or OHMS: a. test both coils for continuity.(Low resistance) b. test both coils for non-continuity to the frame, (ground). There should be no flow, very high resistance. If it's the chime coils: Test both coils for continuity, (There will probably be a 'common' 'return' connection) and for insulation, (no continuity to ground - the frame.) If the above check out, the unit should work unless there's some mechanical damage. Look for a jammed operating rod etc.
Q: I know that the ratio of primary turns to secondary turns is the multiplying factor in voltage. So if you wanted 100,000 volts from a 10 volt source could you potentially do this:4 transformerseach transformer has 10 coils in primary and 100 in secondaryThe output of each transformer's secondary is connected to the primary of the next transformer so that you get 10*10*10*10 or 10,000 as your multiplying factor.Would this work?or do you have to do it the hard way and wind 10 coils in the primary of a single transformer and wind 100,000 times in the secondary?
Yes, you can cascade transfomers. The efficiency might be lower, but it will work to a point. Note also that the current will be proportionally lower. The main problem will be the insulation strength as the voltages get higher: if the insulation isn't strong enough arcing will happen. That 100kV stage needs to be very, very robust - in fact, it probably isn't even feasible at a 1:10 turns ratio because its primary voltage is too high (10kV) and so will need ridiculously thick insulation and/or a lot of turns - engineering such a beast is certainly beyond the casual experimenter. The smart money says forget it. There's lots of ways to generate high voltage besides cascaded transformers. Techniques using flyback coils and capacitive discharge for example can easily get you to 50kV or more (this is, for example, how a Taser makes its HV.) I've included some links below. And please, be very, very careful this stuff can kill you.
Q: If load loss of a transformer at full load is 100kW, the load loss at 50% load will be a) 50kW b) 75kW c) 25kW d) 100kW. i think its 25kW because load loss is inversely proportional to the square of loading percent. kindly explain . is it right.
I'm guessing load loss is the same as copper loss, which is due to the resistance of the wire in the transformer. This loss is (I^2)(R wire) so the answer is c) 25 KW The current is 50% at 50% load, I^2 0.25
Q: Why is the transformer coil insulation?
It is easy to understand because the transformer is used in different environments, according to different insulation level selection, can extend the life of the transformer
Q: S11-1250kVA transformer oil capacity how much
The total amount of oil in the transformer: the amount of oil supplied by the transformer body transport + (the amount of oil required to be added to the main body) + (the amount of oil added to the oil conservator) + (transformer accessories - such as the amount of oil required for the radiator )Wait. The amount of oil added in parentheses is the transformer factory, and the oil drum is installed and delivered to the customer. So customers receive the transformer, the transformer should be the total amount of oil is acceptable enough
Q: I have a transformer 12v and 12v need to reduce these further to be able to grow or shrink the rotational speed electromotor.Which device or component would be used to reduce the speed of electromotor?I making a mini escalators
A transformer has AC output, so first get DC, which needs a rectifier and capacitor. Following this is a voltage regulator using an LM317 (adjustable 3 terminal regulator). This can delivers ~1 amp. You should know what maximum current your motor draws under load. The first link is an example for 1.25V-15 V with an 18V transformer. Use a 12V transformer, and a 1000 ohm potentiometer as a variable resistor instead of 2000 ohms (R2). This will give voltages from 1.25V to 7.0V DC. Use the formula to calculate other resistors for a different voltage. Get the LM317 in a TO220 package, and you will need a heat sink, at least as big as in the picture. You can probably find a kit of parts for this in an electronics shop.
Q: I have a transformer of 12060 Volts and a transformer of 15000 Volts, both neon-sign types; if I wired them together, would it amplify the output voltage or have a catastrophic effect that would end the world as we know it?But really, can I wire them together for an added effect of some kind?Thanks.
If you connect the output side of one to the input side of the other, the second transformer would output a very high volatage, but a very low amperage. Until the internal insulation failed and possibly started a fire. The very high voltage, low amperage output would not be useful.
Q: hey all , i have 2 phase welding machine fed from 30A 3 phase circuit breaker , at high loads above 40A CB cut off the Supply . the problem is i cant change the CB size bcoz it Contrary to legislation in the country . Can i used scott t transformer to balance the load at the main 3 phase ?
you're starting to be to be meant a single section welding device. This unit includes 2 supply lines. those lines may be linked to any 2 lines of a three-phse ability supply device.only connect one line to L1 and the different line to L2, only examine the line to line voltage of the flexibility supply. It must be the comparable by way of fact the welding device score, say, 380VOLTS, 50 Hz.
Q: I live at an apartment complex and I was just returning from work when the entire complex went completely dark. All 12 buildings went offline at the same time, along with the outside lights and the covered parking lights. Since each building has its own transformer, shouldn't they be independent of the others? Why did all 12 buildings and the outside lighting go out together? Are they all on one line or something?
Are they all on one line or something? Yes. All the transformers likely get power from the same seller. If the transformer are the leaves of a tree then a branch supporting all of them was cut or damaged.
Q: What is the transformer absorption ratio (R60 / R15)
Absorption ratio = R60 〃 / R15 〃 For the same insulating material: the moisture or defective absorption curve will change, so you can determine the insulation curve based on the insulation is good or bad, usually in megger in 15 seconds and 60 seconds of the insulation resistance ratio (This is the absorption ratio, expressed by the K value), because the insulation of the degree of moisture increases, the leakage current increase than the increase in the starting value of the absorption current is much more, expressed in the insulation resistance is: megger in 15 seconds and 60 seconds of the insulation resistance is basically equal, so the K value is close to 1; when the insulating medium is dry, because the leakage current is small, the current absorption is relatively large, so the K value is greater than 1. Experience: When the K value is greater than 1.3, the insulating medium is dry, so that by measuring the absorption ratio of the insulating medium, it is possible to determine whether the insulating medium is damped and K is a ratio which eliminates the geometric dimensions of the insulating structure , And it is the same temperature measured under the value, without going through the temperature conversion, the comparison of measurement results is very convenient.

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