• Hot Dip Galvanized Scaffolding Tube 48.3*1.8*6000mm Q235B Steel  EN39/BS1139 for Sale CNBM System 1
  • Hot Dip Galvanized Scaffolding Tube 48.3*1.8*6000mm Q235B Steel  EN39/BS1139 for Sale CNBM System 2
Hot Dip Galvanized Scaffolding Tube 48.3*1.8*6000mm Q235B Steel  EN39/BS1139 for Sale CNBM

Hot Dip Galvanized Scaffolding Tube 48.3*1.8*6000mm Q235B Steel EN39/BS1139 for Sale CNBM

Ref Price:
get latest price
Loading Port:
Tianjin
Payment Terms:
TT OR LC
Min Order Qty:
50 m.t.
Supply Capability:
30000 m.t./month

Add to My Favorites

Follow us:


OKorder Service Pledge

Quality Product, Order Online Tracking, Timely Delivery

OKorder Financial Service

Credit Rating, Credit Services, Credit Purchasing

  • Quick Details of Galvanized Scaffolding Tube 48.3*1.8*6000mm Q235B Steel EN39/BS1139

  • Material :Q235B/Q345B

  • Size : 48.3*1.8*6000mm

  • Surface treatment :Black/Painted/Galvanized

  • Standard:EN39/BS1139

  • Hot Dip Galvanized Scaffolding Tube 48.3*1.8*6000mm Q235B Steel  EN39/BS1139 for Sale CNBM

  • Hot Dip Galvanized Scaffolding Tube 48.3*1.8*6000mm Q235B Steel  EN39/BS1139 for Sale CNBM

  • Futures of Galvanized Scaffolding Tube 48.3*1.8*6000mm  Q235B Steel EN39/BS1139

  • Galvanized Scaffolding Tubes confirm to BS 1139/BS EN 39 Standard. We have a big factory producing galvanized Scaffolding tubes 25,000 tons each month, and 90% of them are for export. Our scaffolding tubes are widely used in all kinds of construction site such as oil and gas industry, refinery industry and infrastructure in over 20 countries.

  • We have a wide range of round scaffolding tubes. If you require a specific size, such as different thickness or different length, please send us your detail requirements. Our quotation will always base on your requirements.

  • Hot Dipped Galvanized Scaffolding tubes are also known as scaffolding pipes, scaffolding poles, and galvanized steel tubes, round galvanized tubes.

  •  

  • Size: 48.3 X 1.8X 6000mm
    Zinc Thickness: 40 micron
    Surface: hot Dipped Galvanized 
    Water Proof: according to customer requirements.
     


  • FAQ

  • 1. What is considerations of Scaffolding installation?

  • There must be a fire protection measures and specialist care, safety personnel patrol inspection when electricity, gas welding work on the scaffold,

  • (1) scaffold frontage hurtful to prevent falling objects protection is required.

  • (2) During take down the scaffolding, fencing and warning signs should be set up on the ground, prohibit others person besides the operator

  • 2.What are the certifications of your products?

  • Certified by SGS, BS1139, EN74, Local Test Report.

  • 3. How long is the warranty period for your product?

  • Our products warranty is 2 years.

Q: I want to know the classification of scaffolding in the building
Material division according to bar1) single specification steel pipe scaffold. It only uses a steel pipe specifications, such as steel tubular scaffolding, welded steel pipe using only 48 * 3.5.
Q: The role of the external scaffolding and the relevant provisions?
These two functions are often concurrent. With the protection of the role of security, in order to play the role of height operation; can not guarantee the safety of the role, the construction personnel can not operate on the above. These two functions, the protection of human safety is the first. Construction workers in the scaffolding on the construction work, there is a sense of security, construction progress, the quality of the project is sufficient protection, in order to create good economic benefits. Otherwise, once the danger of scaffolding, will cause many casualties, causing significant losses. Therefore, in the development of scaffolding support programs and scaffolding erection, we must firmly grasp the quality.
Q: How to calculate the double wall scaffolding
The adjustment coefficient of the bearing capacity of the foundation: KC = 0.400;The average pressure of the bottom of the vertical rod foundation, P = N/A =84.900 kN/m2;Among them, the superstructure to the top surface of the axial force design value: N = 7.641 kN;Basal area (M2):A = 0.090 m2.P=84.900 = fg=200.000 kN/m2. Calculation of bearing capacity of foundation!
Q: If you have two workers say standing on a scaffolding, their are downward forces from the weight of the workers along with the weight of the scaffold, and upward forces from tension suspending the scaffolding in place. The opposite forces add to zero and thus the scaffolding remains at rest.My question has to do with what would occur if more/less workers were on the scaffolding. It appears to me that the scaffolding would always remain at rest. Would there always be a ΣF=0 regardless of the amount of workers? As the decreases in weight from removing a worker would also cause the tension force to be weaker? And vice versa if there were more workers?I
You are correct so long as the scaffolding is not allowed to move. I.e. the cables suspending it are locked and not unwinding from their spools as more workers get on. More weight added would necessarily increase the tension in this type of case. However, if, when another worker got on and the tension could not increase for what ever reason, a downward acceleration would take place that is proportional to the worker's weight. Hope that clears things up.
Q: I'm trying to understand a problem in my physics book. The problem is this:A person is pulling on a rope, that is connected to a pulley on the ceiling. The rope then goes to a box with a pulley on it, and then up to the ceiling where the rope is connected (to the ceiling).The rope and pulleys are massless and frictionless.The book lists three forces (tension forces) going up and one weight force pulling down.My question is, why isn't there another force pulling against the tension of the rope from the guy pulling the rope?
The force felt by the person pulling is the same as the force in the rope between the two pulleys. It doesn't matter if the person is pulling straight up (without the pulley) or straight down(with the pulley) it's the same. Therefore the weight/force is divided equally between the two ropes.
Q: The latest JGJ130-2011 construction fastener type steel pipe scaffolding safety technical specifications, schedule A.0.2 what role, how to correctly use it?
Schedule A.0.2 role: the calculation of scaffolding, the need to calculate the bearing capacity of the scaffolding
Q: What are the main safety problems when dismantling the scaffold
1, all the rods and fasteners in the demolition of the separation, not on the rod attached fasteners or two rods connected to the ground.2, all the feet of the hand, should be erected from the outside of the handle, in order to prevent the feet and garbage from falling.
Q: I know it's soon, but my piercings swollen and quite sore when knocked slightly.I've only had it three or four days, but there's a swollen round lump right next to one pierced hole and I was worried it could be an early sign of a keloid. But I don't know if it's too soon to tell yet.I know they can take up to 6 months to heal, if not more, but I'm kinda paranoid about it.I've rinsed it after showering, used salt water on it every day and apart from that just washed it with water on a cotton bud.Any advice?
I had my industrial for 13 months and it never healed. I decided to retire it and the piercing sites closed up within 6 hours. Seriously, my advice to you is to just take it out. They are wayyyy more trouble than they are worth.
Q: A 520 kg box sits 1.4 m from the left end. What is the tension in the right hand side wire? (g = 9.8 m/s2) ____________ Newtons
Because the scaffold is not moving, we can assume that the net Torque acting on the scaffold equals zero. Net Torque = 0 torque = Force x distance (d) Use the left end of the scaffold as the center point. This will eliminate the Torque caused by the left wire (d = 0, so torque = 0) There are now three forces creating torque on the scaffold. There is the weight (m x g) of the scaffold, at 3.5m from the left end. m1 x g x 3.5m There is the weight of the crate, located 1.4m from the left end: m2 x g x 1.4m These two torques are countered by the torque caused by the Tension (T) of the right wire, located 7m from the left side. T x 7m The sum of these torques is zero. (T x 7m) - (m1 x g x 3.5m) - (m2 x g x 1.4m) = zero solve for T T = ((m1 x g x 3.5m) + (m2 x g x 1.4m)) / 7m T = ((115kg x 9.8m/s^2 x 3.5m) + (520kg x 9.8m/s^2 x 1.4m)) = 1.58 x 10^3 N Hope this helps.
Q: What could you do with 100,000 jumbo cotton balls, 50 gallons of honey, and three story scaffolding?
ummmm oh i got a good one i hope and that is to build the world's largest bee's hive. plus they make more honey and i would have tons of money, pretty sweet isn't it.

Send your message to us

This is not what you are looking for? Post Buying Request

Similar products

Hot products


Hot Searches

Related keywords