Hoisting Mechanism 70RCS25

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70RCS25 Series Hoisting Mechanism

Introduction

Such production are independently developed and manufactured by our company based on mature technologies of French Potain Company with rated hoisting weight of 8t,10t,12t and 16t.Horizontal and vertical motor mounting types and different rope capacity are available for users. Such products adopt two winding 3-phase asynchronous motors and series excitation speed regulation circuit which realize interactive effects via gear assembly to constitute speed regulating system with features of wide range of speed regulation, high-speeding hoisting, low-speed positioning, stable speed change and high working efficiency. The mechanism adopts L-shap in overall layout and employs winding drum of Lebus grooves with large rope capacity, which can prevent disorder in case of multilayer winding of wirerope and satisfy wide use demands of high-rise building construction, hoisting of large equipment & construction member, etc.

Specification

Model:70RCS25

Rated single rope tension KN:25

Magnification:4

Rated Power of the Motor kW:51.5

Operating Frequency(Hz):50

Hoisting speed(m/min):25/50

Rated lifting capacity(t):10/5

Rope capacity(m):550 (5 layers)

Nominal Diameter of Wire rope (mm):Φ14

Hoisting Mechanism 70RCS25

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Q:(a)What is the power output of the crane. (ignoring losses)?(b)If it takes the cran2 2 minutes to raise the payload to its final height, how far above the ground is this?(c)If the cable were to break as the payload reaches its final height, how fast would it be traveling as it hit the ground?: a) As the crane is lifting at constant speed, there is no acceleration on the payload, therefore the net forces on the payload are equal to 0. Therefore the crane overcomes just the force of gravity = 500*9.81 = 4905 N Power = force * velocity = 4905 * 0.7 = 3433.5 W b) distance = speed * time = 0.7 * (2 * 60) = 84 m c) assuming that the cable breaks while it is still going up at 0.7 m/s, therefore initial velocity upwards = 0.7 m/s. using v? = u? + 2as: v? = 0.7? + 2(-9.8)(-84) = 1646.89 v = √(1646.89) = 40.9 m/s the payload will be travelling at 40.9 m/s when it hit the ground.

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