• Ultra-thin slab copper mould plate used on continuous casting machine System 1
  • Ultra-thin slab copper mould plate used on continuous casting machine System 2
  • Ultra-thin slab copper mould plate used on continuous casting machine System 3
Ultra-thin slab copper mould plate used on continuous casting machine

Ultra-thin slab copper mould plate used on continuous casting machine

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Loading Port:
China main port
Payment Terms:
TT OR LC
Min Order Qty:
5 pc
Supply Capability:
200 pc/month

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Specification

metallurgical machinery:
Metallurgical spare parts
copper products:
plate

 1.      Structure of Description

We  can design and manufacture Ultra-thin slab copper mould plate used on continuous casting machine.

Size Length1530mm Width 1100mm , Material Cr-Zr-Cu, Cu Ag.  Coating  Ni-Co、Cr、Ni-Fe.

We are the leading professional designer and manufacturer for copper mould  plates & tube.

The copper moulds supplied by CNBM adopt advanced European technology. Nowadays, CNBM is one of the largest copper moulds supplier and exporter with more than 30% market share in domestic market and 5% in the world market. 

 2.Main Features

Steady and high quality,

Packing : Strong, export worthy wooden cases. High quality products and excellent service.

Fast shipment; 30-40days for production;

Our products with world-class quality, competitive price, flexible payment terms, speedy delivery and excellent service.

We are supplying Size Length1530mm Width 1100mm , Material Cr-Zr-Cu, Cu Ag.  Coating  Ni-Co、Cr、Ni-Fe.

 

 3. Images

Ultra-thin slab copper mould plate used on continuous casting machine

 

 

Ultra-thin slab copper mould plate used on continuous casting machine

 

4.Specification

Thin slab

We can design as per the customer’s specific requirements.

Length    1200-2000mm

Width 1100-1200 mm

Material Cr-Zr-Cu, Cu Ag.  Coating  Ni-Co、Cr、Ni-Fe.

We can design as per the customer’s specific requirements.

 

Q: I cannot seem to grasp the concept of how to write and solve half-reactions. Here are the questions:In lab you saw an electroplating demonstration involving a penny and a dime; both suspended in a copper sulfate solution.The copper was removed from the penny and plated onto the dime.Okay, so I know I‘ll use Cu and I‘m pretty sure Ag. a. Write the half-reactions for the electroplating demonstration. Reduction:Oxidation:b. Was this a spontaneous redox reaction? I‘m fairly certain that part B I do the cathode - anode to get the answer. If the answer is positive then it was spontaneous. I don‘t know which is the anode or cathode in the solution. Thank you.
The dime acts as the cathode because copper ions reduce onto it. Remember, the cathode is always where reduction occurs. oxidation reaction: Cu(s) --- Cu2+ + 2e- The copper from the penny loses electrons forming copper ions that go into the solution reduction reaction : Cu2+ + 2e- --- Cu(s) The copper ions in the solution gain electrons from the dime forming copper solid. Edit: you're right, there should be a 2 before the e. sorry. electroplating is done using an external power source, which means that the reaction is forced to occur and is therefore non-spontaneous.
Q: Copper plate acid corrosion process
Copper corrosion process, called strict etching process, we are usually the etching selective etching, or incised or carved, rather than the whole plate thinning etching.
Q: and how well do they stand-up against hail and storms?
warranties are meaningless to predict life of anything. In Oklahoma you get a warranty on everything, the warranty goes like this If you buy a product and you walk out the door with it, and that product breaks into two pieces, Your warranty is that you get to keep both pieces. If the solar panel is broken by hail and trust me this happens, its up to YOU to fix. OH, and if you didn't tell your insurance company, they they won't have to pay. Most people carry at least $1000 deductible, so, you break a $1000 panel, it is your loss. PV panels degrade over time. After 20 years you may only get 60 to 80% of the original panels output. If a panel fails within the PV makers 20 year warranty period, you won't get a free one, you'll have to pay for normal wear and tare, shipping, handling, installation, and even worse, their new panel may not work with your old panel. Just figure on replacing the whole electrical system every 10 years and the panels every 20 years.
Q: on a hot day,which would stay cooler longer a sheet of aluminum (specific heat 920 J/kg) or copper (specific heat (380 J/kg K)? Why?
PEX meets code, is used extensively by production home builders and is growing in acceptance in the housing industry. Having said that, I would use copper. I know as a matter of fact copper will last a hundred years, probably much longer but I don't know that as a fact, if not subjected to radically altered water or physical abuse. PEX is usually warranted for 30 years but I have been bitten by several warranties in the past. I just built a 3400 SF home myself and sweated copper for all water supply lines.
Q: I have an old sculpture made of sheet copper. It has some areas where the patina is missing.
Heat the copper sheet until it does black (with copper oxide) and then carefully add ethanoic acid. You will have made verdigris.
Q: What fraction of the air molecules in a house must be pushed outside while the furnace raises the inside temperature from 16.0° C to 27.0° C? The pressure does not change since the house is not 100% airtight.The coefficient of linear expansion of brass is 1.9x10^-5° C^?1. At 21.9° C, a hole in a sheet of brass has an area of 1.00 mm^2. How much larger is the area of the hole at 32.2° C?_____mm^2A system takes in 580 J of heat while performing 920 J of work. What is the change in internal energy of the system?______JA copper rod of length 0.40 m and cross-sectional area 7.00X10^-2 cm^2 is connected to an iron rod with the same cross section and length 0.22 m. One end of the copper is immersed in boiling water and the other end is at the junction with the iron. If the far end of the iron rod is in an ice bath at 0° C, find the rate of heat transfer passing from the boiling water to the ice bath. Assume there is no heat loss to the surrounding air. _______WDon‘t have to solve last problem if ya don‘t know
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