Standard Straight Shaft HG-SR352BJ Mitsubishi Motor For Injection Molding
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- Loading Port:
- China main port
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 kg
- Supply Capability:
- 1000 kg/month
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Specification
Servo motor series: low inertia, medium / high power. Rated output: 20.0kw.
Rated speed: 1000r / min. Electromagnetic brake: none.
Shaft end specification: Standard (straight shaft).
Features: there are three types of low inertia, medium and high speed models,
which are suitable for different applications. As a standard, 30kW and above
servo motors can be installed with flanges or brackets. Yiling Tongfu motor
user manual. IP grade: IP44. Application example:
1. Injection molding machine hg-sr352bj
2. Semiconductor manufacturing equipment.
3. Large material conveying system.
4. Press.
The rich motor product line can optimize the performance of the machine.
It has a rich motor product line including rotary servo motor, linear servo
motor and direct drive motor. Motor series; Medium inertia, medium power.
Rated output power: 2.0kw Mitsubishi servo motor user manual. Rated speed:
2000r / min. With or without brake: attached. Shaft end: Standard (straight
shaft). Protection level: IP65 (p67)
Features: there are three modes of medium inertia from low speed to high speed,
which are suitable for different application ranges. Application examples:
transmission machinery, robot, X-Y worktable. High resolution encoder 131072p /
rev (17 bits).
High resolution encoder is included to ensure excellent performance and
stability at low speed. Mitsubishi Tongfu motor user manual. All motors are the
same size as the previous products and the wiring is compatible. Motor series:
flat type, medium and small power. Rated output power: 1.5kw. Rated speed:
2000r / min. with brake or not: attached. Shaft end: Standard (straight shaft).
Protection level: p65 (p67)
Features: the flat design makes this model more suitable for installation in a
narrow space. Hg-sr352bj user manual. Application examples: robots, food
manufacturing machinery.
High resolution encoder 131072p / rev (17 bits).
High resolution encoder is included to ensure excellent performance and
stability at low speed. All motors are the same size as the previous products
and the wiring is compatible. Motor: ha-uh type, power: 4.5kw.
Speed: 2000r / min
According to the type of working power supply: it can be divided into DC motor
and AC motor hg-sr352bj user manual. DC motor can be divided into brushless DC
motor and brushless DC motor according to structure and working principle..
Brushless DC motor can be divided into permanent magnet DC motor and
electromagnetic DC motor.
Division of electromagnetic DC motor: series excited DC motor, parallel excited
DC motor, separately excited DC motor and compound excited DC motor Hg sr352bj
user manual.
Permanent magnet DC motor is divided into rare earth permanent magnet DC motor,
ferrite permanent magnet DC motor and aluminum nickel cobalt permanent magnet
DC motor. Type: hc-pq type
Output power: 0.4KW. Rated speed: 3000r / min. electromagnetic braking: none.
Key axis: straight axis.
In terms of motor: the material, structure and processing technology of servo
motor are much higher than that of AC motor driven by frequency converter, that
is, when the driver outputs the power supply with rapid changes in current,
voltage and frequency, the same server motor can produce response action
changes according to the changes of power supply.
The response characteristics and anti overload ability are much higher than
those of AC motor driven by frequency converter.
The serious difference in motor is also the fundamental reason for the
different performance of the two. Hg-sr352bj manual. That is to say, it's not
that the frequency converter can't output the power signal that changes so
fast, but that the motor itself can't respond,
Therefore, when setting the internal algorithm of frequency conversion, in
order to protect the motor, the corresponding overload setting is made in the
user manual of Mitsubishi servo motor. Of course, even if the output capacity
of the frequency converter is not set, it is still limited. Some frequency
converters with excellent performance can directly drive the servo motor.
- Q: 1000KVA transformer power loss is how much
- The gap between the various models is also great, but also with the size of the load. To the S9 parameter is the no-load loss is 1.7KW, which is the same, full load loss is 10.3KW, this load-related. If the transformer is fully loaded, then the power loss = (1.7 + 10.3) X1H = 12 degrees 1 hour. S11 of the no-load loss is 1.15KW, full load loss is 10.3KW, full load run loss of power = 1.15 + 10.3 = 11.45 degrees 1 hour
- Q: How many times does a copper wire have to go around the input side of a transformer to get the necessary amount of magnetism from 110 volts?How thick does the wire around the transformer have to be if the input it 110 volts? Can it be one wire as thin as a garbage bag tie, or does it need to be as thick as the original wire, but stripped and coiled around the transformer core?
- As stated in another answer, the basic transformer equation is: E 4.44 X f X N X Ac X B E is the applied RMS voltage f is the frequency (Hz) N is the number of turns Ac is the core area (square meters) B is the maximum flux density (Webers per square meter also kknown as Teslas) If the design is for 120 volts at 60 Hz and 1 Tesla, the required number of turns would be about 0.5 divided by the core area. PS The voltage has nothing to do with the thickness of the wire. Wire thickness is determined by current, the desired internal voltage drop in the wire resistance and the tolerable temperature due to internal losses. Magnet wire is used. It has very thin insulation to use the minimum space and allow heat to be more easily conducted out of the coil. The wire can not be stripped bare.
- Q: I am completing an essay on how to improve the performance of a transformer. Please could someone advise me on the problems incurred in transformers and ways that have been designed to reduce these problems. Thanks in advance
- To improve the performance of a transformer, you have to:- [1] Reduce the copper losses, and [2] reduce the iron losses. Copper losses can be reduced by using copper wire of the highest purity; and by using copper wire that has the thinnest possible layer of insulating material on it. These measures, taken together, reduce the length of the wire and therefore its resistance. Iron losses are reduced by using magnetically soft iron in the laminations. This is the type of iron that has a tall and narrow hysteresis loop. Using copper wire with thin insulation (as mentioned above), keeps the windings close to the iron and so reduces magnetic leakage. A third measure is to use very thin laminations and to insulate them with very thin material as this will reduce eddy currents. It is very expensive to build a 99% efficient 250 MVA transformer. The losses in a 94% efficient version, are often cheaper to manage than the extra cost of making the 99% version.
- Q: I have 13 lights with 12 volts 35 Watts on each light for each tree, the outlet is 120 volts current now. Should I buy 300Watt or 600Watt low volts transformer to supply all lights? Need your advise!
- you need a transformer that will support the 12volts lamps and still connect to the 120volt outlet. the best suggestion is to go to the Radio Shack and talk to the counter dude for help --- or --- go to the garden lighting section at Lowe's etc, for
- Q: Briefly explain how an alternating current transformer works and why they are so important to the world’s electrical power infrastructure.
- Okay. You take a magnet and run it past a coil and you get electricity. You can also simply switch the direction of current (or pulse it) in order to create induction current in a coil. So. if you make a basic AC electromagnet with say. 100 loops of thick copper wiring, and put it next to another coil with say. 10,000 thinner wraps. The coil that gets the juice, will induce a current in the coil next to it. Conveniently, more wraps higher voltage lower amperage, and fewer wraps higher amperage lower voltage. So in the above scenario, under ideal circumstances, we would take a primary voltage off 100 volts 100 amps and turn it in to a stepped-up voltage of 10,000 volts at one amp. The reason this is important is that high voltage travels well over great distances. It is much easier to push the same juice much farther away from its source with very high VOLTAGE and low amps than it is to do it the other way. Amps cause heat, heat causes loss and damage to the carrier wire. Voltage just rides along on the surface of the wire with very little loss. So we step up for transport and back down for use when we are close enough to end-use that the losses are negligible.
- Q: Transformer voltage range of 10.5 ± 2 * 2.5% kV and 10.5 ± 5% kV What is the difference
- Two transformers of the same voltage range, but the tap is not the same, the previous one is 5-speed regulator, select the relatively small, more adaptable. The latter is the third gear regulator, sometimes with the actual time required to have the voltage difference, mainly to see that your load is stable and unstable. These two kinds of voltage regulator for the basic price of the transformer has no effect.
- Q: Can somebody please help me understand this problem and help me do it? I'm having a hard time with it and help would be greatly appreciated.The following test data were obtained from short-circuit and open-circuit tests of a 50-kVA, 2400-600 V, 60Hz transformer.Voc600V Vsc76.4 VIoc3.34 A Isc 20.8 APoc 484 W Psc 754 WDetermine:A) the equivalent high-side parameters;B) RegulationC)efficiency at rated load and .92 power-factor for lagging.
- read material regarding transformers Not just once but say 5 times, till you understand what is said. the transformer has copper loss due resistance of primary and secondary. It has additionally iron loss. The equivalent circuit is a sort of representation that brings in these losses. generally you can apply a low voltage to primary till shorted secondary has a current equal to less than rated current. These measurement details are given. Similarly open circuit measurement details are available. With understanding of how the rest can be calculated using worked examples in texts, you can solve it yourself. attempt this See Lee's book on transformers or schaums series on electrical engg.
- Q: Is the secondary current rating of the transformer line current or phase current?
- For star-wiring products, the line current = phase current For triangular wiring products, the rated current refers to the line current (phase to phase current)
- Q: I can't remember the funny scenes from any the Transformers movies, especially 1 and 2.It's driving me nuts.I saw the third one just last week so I remember a couple of funny scenes, but other than that, no luck.If you can, could you please include a link to a video clip of the scene?Thanks so much! (:
- When the car turns into bumblebee and the guy says to the girl its probably japanese
- Q: I'm an intern at an aluminium smelter and am part of the power plant there. They replaced the 33 kV transformers with the 132 kV ones because of an increase in the demand from the smelter. But what are the advantages of such a replacement, besides the obvious decrease in heat loss?
- The new transformer is connected to the transmission grid at higher voltage level (132 kV) vs the old one (33 kV). This implies the increase in power rating (MVA). The old voltage level 33kV was too low for supplying the increased power demand. In addition, by removing the 33 kV voltage level, one step in the transmission chain has been removed. I am assuming that, in the old configuration, in addition to 11/33 kV transformation there was a 33/132 kV voltage transformer(s) somewhere between the smelter substation and the high voltage transmission grid. Three main benefits are: higher capacity, lower losses and minimization of number of voltage levels in the substation reduced costs of operation and maintenance.
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Standard Straight Shaft HG-SR352BJ Mitsubishi Motor For Injection Molding
- Ref Price:
-
- Loading Port:
- China main port
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 kg
- Supply Capability:
- 1000 kg/month
OKorder Service Pledge
OKorder Financial Service
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