Low Frequency Copper Wire Only Chock Coil
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low frequency chock coil
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3.Radial Fixed Leaded Inductors with Inductance ranging from 0.30uH to 100mH.
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- Q: Current through an inductor is turned on at time t0, as shown in the figure. Vscos(200*pi*t). Calculate the energy delivered to the inductor at t21
- Since V L(di/dt) I (1/L)(∫(VI)dt) I (1/0.038)(1/200π)(sin (200πt)) 1/(7.6π)(sin (200πt)) and E ∫(VI)dt E (1/2)L(I?) 200πt f 100 Hz, T 10 milliseconds, 21 milliseconds 720° +36° at 21 milliseconds, sin (200πt)) sin 36° 0.588 I 0.588/(7.6π) 0.0246 amps E (1/2)(0.038)(0.0246^2) 11.5 u joules
- Q: Ex. Negatively charged vinyl strip touches sphere of an electroscope. What happens to the leaves and positions of charges?
- Then, positive charges interact with the negatively charged inductor Good luck!
- Q: A 265 mH inductor whose windings have a resistance of 6.70 Ω is connected across a 10.5 V battery with an internal resistance of 3.35 Ω. How much energy (in J) is stored in the inductor?Thanks for the help!
- U Potential energy R Resistance 6.7ohms I current V/R (10.5V/6.7ohms) 1.57A L inductance 265mH .265H U (.5)LI^2 (given formula in any physics text book) U (.5)*(.265H)*(1.57A)^2 .33 J
- Q: 6. An inductor opposes an instantaneous change in its own voltage? 7. Xc is the AC opposition to current flow? 8. Xc grows smaller as the frequency is increased in a circuit 9. Inductor and capacitor currents are 360 degrees out of phase? 10. XL is the AC opposition to current flow? 11. The term impedance, applied to a circuit with capacitors and resistance is the phasor sum or result of the resistance and capacitive reactance.12. impedance z is defined as the total opposition to voltage in an AC circuit.13. The current always leads the voltage in a series resistor capacitor circuit by 45 degrees.15. When a sinusoid voltage is applied to an RC circuit, the current and all the voltage drops are also sine waves.16. Total current in an RC circuit always leads the source voltage.
- An inductor opposes an instantaneous change in its own voltage? FALSE 7. Xc is the AC opposition to current flow? not entirely TRUE - Xc is one form of opposition to alternating current flow, but the total opposition to ac current is the impedance which is given the symbol Z. 8. Xc grows smaller as the frequency is increased in a circuit TRUE : Xc 1 / ( 2 π f C ) 9. Inductor and capacitor currents are 360 degrees out of phase? FALSE in a series circuit they are in phase with one another, in a parallel circuit the two currents are (approximately) in antiphase i.e. 180° out of phase 10. XL is the AC opposition to current flow? not entirely TRUE - XL is one form of opposition to alternating current flow, but the total opposition to ac current is the impedance which is given the symbol Z. 11. The term impedance, applied to a circuit with capacitors and resistance is the phasor sum or result of the resistance and capacitive reactance. More or less TRUE. In a series CR circuit the impedance is the phasor sum of capacitive reactance and resistance, but that is not true for a parallel connection. 12. impedance z is defined as the total opposition to voltage in an AC circuit. FALSE. Z is may be described as the total opposition to CURRENT flow, but that description is not really rigorous enough to constitute a formal definition. 13. The current always leads the voltage in a series resistor capacitor circuit by 45 degrees. FALSE It is only true if the resistance is EQUAL TO the capacitive reactance. 15. When a sinusoid voltage is applied to an RC circuit, the current and all the voltage drops are also sine waves. TRUE (provided that the sinusoidal voltage is the only applied voltage and adequate time has elapsed for any transients to decay to a negligible level) 16. Total current in an RC circuit always leads the source voltage. Only true if the source voltage is alternating. Not true if the applied voltage is a constant dc level.
- Q: A 12.6 V battery is in series with a 30.0 mH inductor and 0.150 ohm resistor connected through a switch. When the switch is closed at t o, find time constant of the circuit( ans: 0.2 s) Find the current after 1 time constant has elapsed ( ans: 53.1 A) Find the voltage drop across R after t0 and after one time constant ( ans: 0 volts and 7.97 V ) find rate of change of current after one time constant( ans: 150 A/s)I have the answers, but I need a step by step? I'd appreciate any help.
- Let V_s the voltage of the battery 12.6 V Let i the current through the series circuit Let R the resistance of the resistor 0.150 Ω Let L the inductance of the inductor 0.03 H Let V_r the voltage across the resistor (i)R Let V_l the voltage across the inductor L(di/dt) The source voltage must equal the sum of the voltages across the components: V_s V_r + V_l 12.6 V (i)R + L(di/dt) di/dt + (i)(R/L) (12.6 V)/L The integrating factor for this is e^{∫ (R/L)dt} e^{(R/L)t} e^{(R/L)t}di/dt + e^{(R/L)t}(i)(R/L) e^{(R/L)t}(12.6 V)/L The left side integrates as the reverse of the product rule and the right side integrates with the reciprocal of the coefficient with a constant, C: e^{(R/L)t}(i) e^{(R/L)t}(12.6 V)/R + C Multiply both sides by e^{-(R/L)t}: (i) (12.6 V)/R + Ce^{-(R/L)t} i (12.6 V)/0.150 Ω + Ce^{-(R/L)t} i 84 A + Ce^{-(R/L)t} We find the value of C by knowing that i 0 at t 0 0 84 A + Ce^0 C - 84 A i (84 A)(1 - e^{-(R/L)t}) To find the time constant set (R/L)t 1: t L/R 0.03/0.150 0.2 s One time constant means that -(R/L)t -1 i (84 A)(1 - e^-1) ≈ 53.1 A The current is 0 at t 0 so V_r R(0) 0 The current is 53.1 A at t 0.2 s so V_r (0.150 Ω)(53.1 A) ≈ 7.97 V The charge rate is di/dt and we have an equation involving that: di/dt + (i)(R/L) (12.6 V)/L Solve for di/dt: di/dt (12.6 V)/L - (i)(R/L) di/dt 12.6 V/0.03 H - (53.1 A)(0.150 Ω/0.03 H) di/dt 154.5 A/s
- Q: :)please be as explicit as possible.Thanks!
- A transformer implies that there is no deliberate leakage inductance although this is exactly what a self protecting transformer uses. Transformers rarely specify the winding inductance, which has to be high enough to limit the idle current to a small part of the rated current. Instead the voltage and operating frequency are given. This also covers other core loss issues. Florescent ballasts are transformers with significant leakage inductance to limit the current when the gas ionizes.
- Q: A 12.6-V battery is in series with a resistance of 0.330 Ω and an inductor. I got part a right, but I can't seem to figure out the rest. help please. a) After a long time, what is the current in the circuit?I(tinfinity) 38.1 A(b) What is the current after one time constant?I(tτ) AHow is the time constant defined for an RL series circuit? How does the current change as a function of time in such a circuit (c) What's the voltage drop across the inductor at this time?ΔVL VUse Kirchoff's Loop rule to describe the relative sizes of the potential differences across the battery, inductor, and resistor.(d) Find the inductance if the time constant is 0.110 s.L H
- b) Current is given by i (E/R)*(1 - e^(-t/tL)) where tL is the inductive time constant. If t tL then i (E/R)*(1 - e^(-1)) You can crank that out. In an RL series circuit, tL L/R c) If the current is i, the voltage across it is i*R. The voltage across the circuit is E. So the voltage across the inductor is E - i*R. d) tL L/R 0.110 s Solve for L. The L H threw me at first -- I think it's telling you that the units are henries.
- Q: If the current through the inductor (L 34.8 mH) at 448 Hz has an amplitude of 55 mA, what is the amplitude of the AC voltage?What is the rms value of the AC voltage?
- Inductive Reactance X? 2πfL 98 ohms E I*X 55 mA x 98 ohms 5.39 volts The problem is, what do you mean by amplitude ? Voltages are measured in peak, peak-peak, or RMS. If none are stated, RMS is assumed. So lacking a meaning for amplitude, I have to assume they are in RMS current and voltage. So the RMS answer is 5.39 volts RMS. .
- Q: current of 72.7A is measured, what is the rms voltage (V) of the source?
- in simple terms put in R and -j/wC in the formulation you have (R2 is the output term) and turn the crank to simplify. the respond relies upon upon whether the output is around the resistor or the capacitor.
- Q: Has it something to do with the number of windings? I am not sure?
- They don't oppose current flow with resistance but with an opposed voltage. An ideal inductor has no resistance. And it's not the current itself that is opposed but any change in the current. When an inductor is connected to a battery, the current does not rise instantaneously; it's limited to a certain rise rate because the opposing voltage reduces the net voltage driving the the rise. Increasing current in the windings creates an increasing magnetic field which in turn induces an opposing voltage proportional to the field increase rate. This results in an equilibrium between current increase rate and net voltage across the inductor.
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1. Manufacturer Overview
| Location | Shenzhen, Guangdong, China (Mainland) |
| Year Established | 2006 |
| Annual Output Value | US$2.5 Million - US$5 Million |
| Main Markets | North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market |
| Company Certifications | CE Certificates |
2. Manufacturer Certificates
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| Range | |
| Reference | |
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3. Manufacturer Capability
| a) Trade Capacity | |
| Nearest Port | Shekou,Yantian |
| Export Percentage | 51% - 60% |
| No.of Employees in Trade Department | 3-5 People |
| Language Spoken: | English, Chinese |
| b) Factory Information | |
| Factory Size: | 3,000-5,000 square meters |
| No. of Production Lines | 9 |
| Contract Manufacturing | OEM Service Offered Design Service Offered Buyer Label Offered |
| Product Price Range | Average |
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Low Frequency Copper Wire Only Chock Coil
- Ref Price:
-
- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 3000 Pieces pc
- Supply Capability:
- 300000 Pieces per Month pc/month
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