Low Frequency Copper Wire Only Chock Coil

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low frequency chock coil

1.Good quality and low price

2.deliver the goods on schedule

3.Radial Fixed Leaded Inductors with Inductance ranging from 0.30uH to 100mH.

4.ROHS compliance.

5.Remark:we can produce it according client's requirement

Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on, from internationally powerful authorities. We have got ISO9001 certificate. We promise to offer the best products to our clients. We look forward to cooperating with all friends for more mutual benefits.

Q: 1. how to calculate the resistance of an inductor in a circuit?for example a resistor connected series with an inductor, how to calculate the overall resistance of the inductor and resistor together?2.if inductors make induced e.m.f, why do they behave as short circuits in DC circuits3.if inductors are strong enough what don't they seem to short cicuit like in strong electromagnets?: You may be getting resistance confused with impedance. 1. But taking your question as it stands, the resistance of an inductor can only be calculated if you know the size of wire used and the length of wire. Formula is below. For total resistance of that in series with a discrete resistor, just add them together like any two resistors in series. If you mean impedance or reactance, the inductive reactance of an inductor is XL 2πfL where L is the inductance in henrys and f is the frequency. From that you can calculate the impedance: Impedance Z √(R? + X?) where X XL – Xc 2. Because DC does not induce any voltage. And they are not a short circuit, see #1 above. 3. This question makes no sense, sorry. What do you mean by strong. Resistance of a wire in Ω R ρL/A ρ is resistivity of the material in Ω-m L is length in meters A is cross-sectional area in m? A πr?, r is radius of wire in m resistivity Cu 17.2e-9 Ω-m or 17.2e-6 ohm-mm .

Q: A current of 1.24A in an inductor L results in a stored energy of 0.195J. The current is then changed to 6.47A in the opposite direction. Calculate the change of stored energy.: Situation 1: MPE1 1/2*L*I1^2 Situation 2: MPE2 1/2*L*I2^2 L doesn't change, since it only depends on geometry and core material properties of the inductor. Solve for L in situation 1: L 2*MPE1/I1^2 Substitute: MPE2 MPE1 * I2^2/I1^2 We are interested in MPE2 - MPE1: MPE2 - MPE1 MPE1*(I2^2/I1^2 - 1) Data: MPE1:0.195 J; I1:1.24 A; I2:6.47 A; Result: MPE2 - MPE1 5.1138 Joules

Q: i am making an Am transmitter and i need a 5 mH inductor for the 1MHz oscillator.: 5 Mh Inductor

Q: A 0.070-H inductor is wired across the terminals of a generator that has a voltage of 2.2 V and supplies a current of 0.029 A. Find the frequency of the generator. Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.: The reactance of the inductor is found by dividing the voltage (2.2V) by the current flowing through it, here 29 milliamperes or 0.029 A. The reactance, XL 2.2 / 0.029, or 75.862 inductive ohms. If the generator supplies sinusoidal AC, the inductive reactance (XL) equals 2π times the frequency f times L, the inductance. So XL 2πfL and we are looking for f. Thus f XL / 2πL The inductance L is given as 0.07 henry and we know XL 75.862 and 2π is a constant, 6.2831853. So f 75.862 / (6.2831853)(0.07) 172.483 The frequency is 172.483 hertz, or cycles per second. Hope this answers your question.

Q: An RLC circuit with a capacitance of 0.010 uF is found to resonant with a frequency of 1.30×104 Hz. What is the value of the inductor? Also what are the units of the inductor. Thanks: X ind2TTfL , X cap1/(2TTfC), at resonance,X ind Xcap,2TTfL1/(2TTfC), 4TT^2f^2LC1, L1/(4TT^2 f^2 C)1/[4TT^2 (13000)^2 (0.01 x 10^-6)] L0.014988 henry14.98 mili-henry God bless you.

Q: An inductor of 170 turns has a radius of 8 cm and a length or 30 cm. The permeability of free space is 1.25664 x 10^-6 N/A^2.Find the energy stored in it when the current is 0.6 A.: Inductance of a solenoid, air L ??N?A/Ln Ln is length in meters A is area in meters? N is number of turns ?? is the magnetic constant 1.2566×10?6?H/m (or T·m/A) use the above formula to calculate inductance. Change units to meters. then use E ?LI? Energy in an inductor to get the energy. .

Q: A 215 ? resistor and a 0.2 H inductor are connected in series with an AC source of 234 V and frequency 106 Hz. (a) What is the current in the circuit? (b) Calculate the phase angle between the current and the voltage of the AC source. I have tried every way possible to find the correct answer, which is a) 0.925A and b) 31.8 degrees, couldn't figure it out. Your help will be greatly appreciated. Thank you!: Reactance of inductor (X) is given by X 2πfL X 2 * π * 106 * 0.2 X 133.2 ? Impedance (Z) of circuit: Z √(R? + X?) R 215?; X 133.2 ? Z 252.92 ? Ohm's Law i v/r I 234 / 252.92 I 0.925 A Voltage across R is in phase with the supply voltage, so phase angle arctan(X/R) arctan (133.2 / 215) 31.78°

Q: I have simple rl circuit two resistance in parallel and a inductor - 5 H in parallel. I need to thevenize the circut but I do not know how to handle with the inductor, wich is in value of 5 Hplease help thank you: let's see what we can find :-) (by the way, what does thevenize mean? I've never heard of that before)

Q: 2.Two 0.20-H inductors and one 0.44-H inductor are connected in series across the terminals of a 60.0-Hz ac generator. What is the total inductive reactance of this circuit?3. An ac generator supplies an rms (not peak) voltage of 180 V at 60.0 Hz. The generator is connected in series with a 0.50-H inductor, a 6.0-?F capacitor and a 300-Ω resistor a.What is the capacitive reactance? b.What is the rms current through the resistor? 4.A series RCL circuit is comprised of a 3.00-mH inductor and a 5.00-?F capacitor. What is the resonant frequency of this circuit?5.An ac generator supplies an rms (not peak) voltage of 180 V at 60.0 Hz. The generator is connected in series with a 0.50-H inductor, a 6.0-?F capacitor and a 300-Ω resistor. Determine the peak voltage of the generator.6.An ac generator supplies a peak (not rms) voltage of 150 V at 60.0 Hz. The generator is connected in series with a 35-mH inductor, a 45-?F capacitor and an 85-Ω resistor. What is the impedance of the circuit?: 2.Two 0.20-H inductors and one 0.44-H inductor are connected in series across the terminals of a 60.0-Hz ac generator. What is the total inductive reactance of this circuit? XL ω*L tot 2PI*f*(0.20*2+0.44) 377*0.84 316.67 3. An ac generator supplies an rms (not peak) voltage of 180 V at 60.0 Hz. The generator is connected in series with a 0.50-H inductor, a 6.0-?F capacitor and a 300-Ω resistor a.What is the capacitive reactance? Xc 10^6/(ω*C) 10^6/(377*6) 442 ohm XL ω*L 0.50*377 188.50 ohm R 300 ohm X Xc-XL 253.6 ohm b.What is the rms current through the resistor? Z √300^2+253.6^2 393 ohm I V/Z 180/393 0.458 A 4.A series RCL circuit is comprised of a 3.00-mH inductor and a 5.00-?F capacitor. What is the resonant frequency of this circuit? Resonance condition : XL XC ωL 1/ωC ω^2L*C 1 4*PI^2*f^2*3*10^-3*5*10^-6 1 f √10^3*10^6/(4*3.14^2*3*5) 1300 Hz 5.An ac generator supplies an rms (not peak) voltage of 180 V at 60.0 Hz. The generator is connected in series with a 0.50-H inductor, a 6.0-?F capacitor and a 300-Ω resistor. Determine the peak voltage of the generator. Peak voltage 180√2 6.An ac generator supplies a peak (not rms) voltage of 150 V at 60.0 Hz. The generator is connected in series with a 35-mH inductor, a 45-?F capacitor and an 85-Ω resistor. What is the impedance of the circuit? Xc 10^6/(ω*C) 10^6/(377*45) 58.95 ohm XL ω*L 35*10^-3*377 13.20 ohm R 85 ohm X Xc-XL 45.75 ohm Z √85^2+45.75^2 96.53 ohm

Q: A circuit consists of a 17 ? resistor and a 510 mH inductor connected in series to a 16 V battery. What is the value of the current when the current is increasing at the rate of 8 A/s?Answer in units of A.: hyperphysics.phy-astr.gsu.edu/hba the equation for I is given. dI / dt V/L e^(-tR/L) calculate dI / dt 8, you will find a value for t, plug is value for t into the equation for I

Our goods sell very well and gain a good reputation from the clients with our production scale, environmentally friendly products, excellent product quality, first-class enterprise management, the most competitive price and perfect service.Our products have gained the international certifications, such as CQC, CE, RoHS, UL and so on.

1. Manufacturer Overview

Location	Shenzhen, Guangdong, China (Mainland)
Year Established	2006
Annual Output Value	US$2.5 Million - US$5 Million
Main Markets	North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe; Central America; Northern Europe; Southern Europe; South Asia; Domestic Market
Company Certifications	CE Certificates

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3. Manufacturer Capability

a) Trade Capacity
Nearest Port	Shekou,Yantian
Export Percentage	51% - 60%
No.of Employees in Trade Department	3-5 People
Language Spoken:	English, Chinese
b) Factory Information
Factory Size:	3,000-5,000 square meters
No. of Production Lines	9
Contract Manufacturing	OEM Service Offered Design Service Offered Buyer Label Offered
Product Price Range	Average