Amaco Artemboss Mill Finished Aluminum Coils for Secondary Pass
- Loading Port:
- Shanghai
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 5 m.t.
- Supply Capability:
- 50000 m.t./month
OKorder Service Pledge
OKorder Financial Service
You Might Also Like
Specification
1.Structure of Mill Finished Aluminium Coils for Secondary Pass
Mill Finished Aluminium Coils for Secondary Pass is one semi-finished aluminium material. This strip can be rolled down to aluminium coil,sheet,circle ect. The alloy AA1050 is widly used in building, industry ect. Its weight is much lower than steel. So many customers choosed aluminium material instead of steel.
2. Main features of Mill Finished Aluminium Coils for Secondary Pass
a.Competitive price---We have our own mills and can produce mill finished aluminium coils, so we can control the production cost better.
b.Professional after-sale service---We have more than 15 years exportation experience and you need not worry about the exporation problems.
c.Fast delivery time---We can control the delivery time within 35 days.
3. Image of Mill Finished Aluminium Coils for Secondary Pass
4. Product Specification of Mill Finished Aluminium Coils for Secondary Pass
ALLOY | TEMPER | THICKNESS | FINAL THICKNESS | WEIGHT |
AA5052 | F | 3-8MM | 0.2MM-3MM | 5-10 TONS |
5.FAQ:
What is the quality standard?
---Usually our standard is GB3880-2006
What is the largest width?
---It is 2300mm
What is the MOQ?
---Usually we can accept 80 tons.
- Q:the coil is wrapped around the aluminium pipe will it effect the efficiency of the coil gun ?
- Yes, it absorbs most magnetic force generate by coil and turns it into useless current .
- Q:A 0.250-g sample of a magnesium-aluminum alloy dissolves completely in an excess of HCl (aq). When the liberated H2 is collected over water at 29 C and 752 torr, the volume is found to be 311 mL. The vapor pressure of water at 29 C is 30.0 torr. What is the mass percentage of aluminum in this alloy?
- P_H2 = 0.950 atm (Dalton's Law of partial pressures) n=Pv/RT = (0.950 atm)(0.311 L) / (0.08206 (L*atm)/(mol*K))(302.15 K) n_H2 = 0.011915983 mol Balanced equations: Al + 3HCl -- 3/2H2 + AlCl3 Mg + 2HCl -- H2 + MgCl2 By these equations, we know that every mole of Al will give us 1.5 moles of H2, and every mole of Mg will give 1 mole of H2. We can therefore set up an equation for the mass of Al like this: *Let a = the mass of MAGNESIUM* Al = 0.250 g - a With this equation in mind, we can setup two equations solving for 'n' of each element by dividing by its molar mass and multiplying by the molar ratio: n_Mg = a / 24.30 (1:1 ratio, so we don't have to multiply) -- number of moles of H2 produced by the reaction of Mg (now written as n_H') = a / 24.30 n_Al = (0.250 g - a) / (26.98 g/mol) Because of the molar ratio shown above, we must multiply n_Al by 1.5 in order to get n_H2 produced by the reaction of aluminum, hereafter known as n_H2 Since we know the number of moles produced by the sum of the reactions, we can add these equations together and solve for n_H2. (**note that your value will be different because you have a different volume**) Set up the equation like this: n_H2' + n_H2 = n_H2 = 0.011915983 mol Sub in your individual equations for n_H2' and n_H2: (a/24.3) + 1.5[(0.250-a)/26.98] = 0.011915983 mol Rearrange and solve for a (mass of MAGNESIUM): (26.98a + 9.1125 - 36.45a) / (24.3)(26.98) = 0.011915983 0.011915983 = 9.47a a = 0.137298281 g Once you have your 'a' value, divide it by the total mass (0.250 g) and multiply by 100%. This gives you the percentage of Mg. (0.137298281 g / 0.250 g) * 100% = 54.9193 % Since you want ALUMINUM, you must subtract the percentage of Mg from 100. 100 - 54.9193 = 45.08% So, the mass percentage of aluminum is 45.08%. I hope this is helpful!
- Q:A solid aluminum sphere has a mass of 83 g.Use the density of aluminum to find the radius of the sphere in inchesExpress your answer using two significant figures.I can't figure this out :(
- Aluminum's density is about 2.7 grams per cubic centimeter. So a sphere with a mass of 84grams has a volume of about 31.111 cubic centimeters. You get this by dividing 84 by 2.7. Now that you know the volume, you can calculate the radius of the sphere. for a sphere, volume = 4/3 pi * radius to the third power. So 31.111 = 4/3 * (3.14...) * r^3. Divide both sides by 4/3 then divide both sides by pi and you get something like r^3 is 7.427. Then find the cube root of this to find your radius. I don't have a calculator, so someone should check the numbers.
- Q:why could aluminum pot be repaired by knocking the aluminum sheet into the pot but not being bonded by glue?
- the oxidation rate of aluminum's surface is very quick, so we cann't use the method of tin welding, and the cost of argon arc welding is very high,so aluminum pot's repair usually uses riveting. aluminum has low hardness and good ductility, so it can be repaired by tightly knocking, without the bonding of glue. general glue will decomposed in open fire, if we bond pot by glue, the pot after repair won't be able to endure high temperature.
- Q:What are the different grades of aluminum sheets?
- The different grades of aluminum sheets include 1100, 3003, 5052, 6061, and 7075.
- Q:What is the melting point of aluminum sheets?
- Aluminum sheets melt at around 660 degrees Celsius or 1220 degrees Fahrenheit.
- Q:Can aluminum sheets be used in construction?
- Yes, aluminum sheets can be used in construction. They are commonly used for roofing, siding, and structural applications due to their lightweight, corrosion-resistant, and durable properties.
- Q:I wish to purchase an 8' step ladder as well as a medium length extension ladder. What are the pros and cons of aluminum vs. fiberglass?
- The main advantage of fiberglass ladders is the reduction of electric shock from contact with electric wires. A disadvantage of fiberglass ladders is the tendency of fiberglass to crack. The inverse of this applies to aluminum. I bought a Little Giant ladder; it is a 300lb rated aluminum ladder with great stability and can function as a 12' step ladder and a 21' extension ladder. It cost me over $400, but after using it for over a year I would not buy any other kind regardless of the price. This is a solid, well-made ladder with great versatility. It also comes in smaller versions; I think the smallest one collapsed takes up only about 5 feet of space.
- Q:The idea that you can adequately protect yourself from the Alien and government thought transmissions with a 'tin-foil / aluminum hat is just a myth. The correct and real thing to use is an aluminum construction site type of hard-hat. That is why the government and all major defense contractors wore aluminum hard-hats back in the 1950's. The plastic and fiber glass hard-hats that they use now is only because the Aliens got wise to the old aluminum hard-hat trick and outlawed them after the Aliens and their Illuminati minions took over after President Truman got out of office. Everyone knows that.So does any company anywhere in the world currently defy the Alien’s production ban on aluminum hard hats? Or is e-bay and garage sales the only source of aluminum construction site hard hats?
- what's ENMOD we ask with baited breath ... lets find out ... Excluded from the Copenhagen Agenda: Environmental Modification Techniques (ENMOD) and Climate Change The manipulation of climate for military use ... man I could be a great nutter ...I missed my calling ...
- Q:What's the difference between laser cutting aluminum plate and stainless steel plate?
- Aluminum plate reflectivity high, viscous strong, general 3mm above will hang slag, but very easy to peel off, stainless steel cutting ability and thickness and equipment power relationship more.Wire cutting: wire cutting refers to WEDM. It is developed on the basis of electric spark piercing and forming. In some ways, WEDM has been replaced by edm. Need to use the electric spark line cutting machine operation line cutting, the basic physical principle is free of positive ions and electrons in the presence of accumulation, a conductive channel ionized quickly formed, current formed between two plates, caused numerous collisions between particles, the formation of a plasma, and quickly rises to the high temperature of 8000 to 12000 the moment in the two conductor surface melting materials.
1. Manufacturer Overview |
|
---|---|
Location | |
Year Established | |
Annual Output Value | |
Main Markets | |
Company Certifications |
2. Manufacturer Certificates |
|
---|---|
a) Certification Name | |
Range | |
Reference | |
Validity Period |
3. Manufacturer Capability |
|
---|---|
a)Trade Capacity | |
Nearest Port | |
Export Percentage | |
No.of Employees in Trade Department | |
Language Spoken: | |
b)Factory Information | |
Factory Size: | |
No. of Production Lines | |
Contract Manufacturing | |
Product Price Range |
Send your message to us
Amaco Artemboss Mill Finished Aluminum Coils for Secondary Pass
- Loading Port:
- Shanghai
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 5 m.t.
- Supply Capability:
- 50000 m.t./month
OKorder Service Pledge
OKorder Financial Service
Similar products
Hot products
Hot Searches
Related keywords