Cantilever Formwork with Durable Using Time and Trustful Quality
- Loading Port:
- Tianjin
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 200 pc
- Supply Capability:
- 3000000 pc/month
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1. Structure of Cantilever Formwork Description
Cantilever Formwork is mainly used in the concrete pouring of pier, high buildings, and so on. The concrete lateral pressure is entirely supported by anchor system and the wall-through tie-rods, additional reinforcement is not needed. The construction is easy, rapid and economical. A single pouring height is high and the finished concrete surface is perfect. Cantilever formwork has several types, the structure is similar, and has its own different characteristic. Can use them according to actual demand.
Main cantilever Formwork:PJ200 & PJ240,CB-240 etc.
2. Main Features of Cantilever Formwork
-easy to assemble
-simple structure.
-easy, rapid and economical.
3. Cantilever Formwork Images
4. Cantilever Formwork Specifications
Anchor system
Anchor system is the most important supporting part. The system is made of five parts shown below. There into, tensile bolt, anchor shoe and bowl-climbing cone can be taken out for reusing after the concrete pouring.
① Tensile bolt M30/L= 110
② Anchor shoe
③ Bowl-climbing cone M30/D15
④ High-strength rod D15
⑤Ancor plate D15
5.FAQ of Cantilever Formwork
1) What about of our after-sale services?
. Response will be carried out in 24hours after receiving any complain or request.
. Any formwork cost can be refund after order is confirmed.
. If the products are not based on the requirements, there will be the relevant compensations made for you.
2) What about of our after-sale service?
. Response will be carried out in 24hours after receiving any complain or request.
. Steel Frame Formwork GK120 cost can be refund after order is confirmed.
. If the products are not based on the requirements, there will be the relevant compensations made for you.
4) What about the package and shipping time?
.Packing: wood package and adhesive tape
.Shipping: by sea
Shipping time: Normally small orders, it just1week business days to arrive your hand; When comes to the customs declaration,
it may need 2weeks.
- Q: From the book quot; The Scarlet Letterquot;
- He says no. ---- They're, Their, There - Three Different Words. Careful or you may wind up in my next novel. Pax - C
- Q: The amount of bowl buckle scaffolding, know the area of 50000m2, height 6m, how to calculate the number of posts with the root, the number of bowl buckle on the number of how many?
- Unable to determine pitch and step reference 0.6m and 1.0m
- Q: I'm not worried about the pain and whatever, but I've been told that it deforms your ear. I really like the piercing and want it pierced, but not if it's going to deform my ear. Will it?
- It can collapse your cartilage, if you get it done with a gun. If you go to a professional, and they do it with a needle, you'll be fine.
- Q: Construction of the bowl button steel scaffolding and fastener type scaffolding which cost high
- A scaffold now is not how to use, is a relatively high cost, two is a scaffolding no disc Scaffolding Safety, but compared with the disc scaffolding fastener steel pipe scaffold is relatively cheaper, currently used more is fastener scaffolding, disc with a more foreign words.
- Q: A window washer is standing on a scaffoldsupported by a vertical rope at each end. Thescaffold weighs 145 N and is 3.02 m long.Assume the 675 N worker stands 1.28 m fromone end of the scaffold.What is the force on the rope farther fromthe worker?Answer in units of NWhat is the force on the closer rope?Answer in units of N.
- Force from scaffold alone = (145/2) = 72.5N. on each rope. 675/ ((3.02/1.28)) + 1) = 200.93N. on the further rope, and (675 - 200.93) = 474.07N. on the nearer. Total tension further rope = (200.93 + 72.5) = 273.43N. Total tension nearer rope = (474.07 + 72.5) = 546.57N.
- Q: Bowl buckle type steel pipe scaffold and full fastener type scaffolding are long what kind of? What is the difference
- Fastener type scaffolding is composed of shelves and fasteners, and the bowl buckle scaffold is made up of the bowl buckle, the lower bowl buckle, cross bar joints, vertical rods, beams and other components, the method of building some differences.
- Q: Hey, ive just had the scaffolding piercing ( think thats how you spell it :P ) and i just wanted to know, is there any special way to look after it? any special way to clean it? or is it just like any other piercing?How often should i clean it? and is it wise to wear gloves when cleaning it? to keep any bacteria off it? Or what?Thankssssss :)
- You don't need to wear gloves when you're cleaning it, just make sure you wash your hands before you clean it. You should be cleaning it 1-2 times a day with a saline solution, such as H2Ocean, or a salt soak that should last 5-10 minutes. Salt soaks draw out bacteria/infections, so they are highly recommended.
- Q: How to calculate the amount of steel pipe in the bowl buckle scaffold formwork system? What is the good software or experience of the eldest brother?
- According to the bearing capacity of the vertical bar, according to the gravity of the beam and slab, the stress analysis of the horizontal member is carried out
- Q: A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 190 N and is 3.30 m long. What is the tension in each rope when the 710 N worker stands 2.30 m from one end?smaller tensionN?larger tensionN?
- think of statics (in terms of forces and torques): because of fact the gadget is in equilibrium, the sum of the forces = 0 and the sum of the torques = 0 on the grounds that sum of forces = 0, then: ft(left) + ft(suitable) - Fg(scaffold) - Fg(employee) = 0 on the grounds that sum of torques = 0, then: -Set some element as your axis of rotation. for my area, I set between the ft as my axis. to that end, my torque equation will become ft(suitable)(2.ninety m) – Fg(scaffold)(a million.40 5 m) – Fg(employee)(a million.ninety m) = 0 you already know Fg(scaffold), Fg(employee), so resolve for ft(suitable). Plug this value into the tension equation and resolve for ft(left).
- Q: A scaffold is constructed by placing two supports under a 18 ft, 4 in (a) board weighing 77 lbs. The supports are each 2 ft, 6 in (b) from their respective ends. Two painters stand on the board; one weighs 153 lbs and stands 2 ft, 6 in (c) from the left end of the board. Where must the 202 lbs painter stand so that each support carries the same weight? (express your distance in feet from the right end of the board (d).)
- I know where he should stand, but where he is standing is by the lunch truck when he should be getting his fat-*** back to work.
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Cantilever Formwork with Durable Using Time and Trustful Quality
- Loading Port:
- Tianjin
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 200 pc
- Supply Capability:
- 3000000 pc/month
OKorder Service Pledge
OKorder Financial Service
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