Tower Crane of TC5015 with Max Load 6 Ton and Span of 50M
- Ref Price:
-
- Loading Port:
- Shanghai
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 unit
- Supply Capability:
- 20 unit/month
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TC5015 Description
Feature: Tower Crane Condition: New
Application: urban construction Rated Loading Capacity: 6T
Rated Lifting Moment: 630MT Max. Lifting Load: 6T
Max. Lifting Height: 200M Span: 50M
Model Number: TC5015
Certification: ISO9001:2000; CE;Ukraine & Belarus Certificate
Colour: Orange/ Yellow
After-sales Service Provided: Overseas third-party support available
TC5015 Features
1. Advanced painting process
2. Potain masts designed with dismountable panels, making teansport easier and cheaper.
3. New designed mast, can be used to Internal and external climbing tower crane
4. Famous brand mechanism system, Schneider Electronic control system, jiangte and jiuhe motor
5. Engineers available to service machinery overseas.
6. For warranty, it is 12 months from the B/L date.What's more, some free easy worn spare parts are provided together with the crane.
TC5015 Specification
TC5015 Pictures
TC5015 FAQ
Q: What is tower crane?
A: Tower crane is a modern form of balance crane that consist of the same basic parts. Fixed to the ground on a concrete foundation (and sometimes attached to the sides of structures as well), tower cranes often give the best combination of height and lifting capacity and are used in the construction site.
Q: Your tower crane is similar to Potain or Liebherr type?
A: It could develop any type of tower crane as per clients’ requirements if the clear information is provided. Originally, our tower crane design is based on Liebherr; but now, we not only introduced Potain design; but also developed special tower crane according to the market needs such as TC5013A with panel mast section. In addition, we also produce some models same as Potain original model, such as F0/23B, H3/36B and etc.
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- f = 1/P, where f is the frequency and P is the period P = 2π/(2πb) = 1/b, so P = b Let v = velocity v = ds/dt = -A sin (2πbt) ? 2πb = -2πAb sin (2πbt) Let f* = 2/b, so P* = 2π/(2/b) = bπ v* = -2πAb sin (πbt) The amplitude of the new velocity is 2πb times the original amplitude. Let a = acceleration a = dv/dt = -4π^2Ab^2 cos (2πbt) Let j = jerk j = da/dt = 8π^3Ab^3 sin (2πbt) a* = 8π^3Ab^3 sin (πbt) The amplitude of the new jerk is 8π^3b^3 times the original amplitude. An increased jerk means the machinery is subjected to greater stress, which causes it to break down.
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- You over-constrained the problem. Why take it from earth at all? A recent probe has found that there is plenty of water ice inches under the surface of the polar regions. Drill a well, set off an explosion at the bottom to fracture the rocks, lower an electric heater, and pump out the water. In addition to providing drinking water, it can be electrolysized to make hydrogen and oxygen for rocket fuel. This can all be done with robotics and stockpiled for future human visitors.
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Tower Crane of TC5015 with Max Load 6 Ton and Span of 50M
- Ref Price:
-
- Loading Port:
- Shanghai
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 unit
- Supply Capability:
- 20 unit/month
OKorder Service Pledge
OKorder Financial Service
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