SZ9-400-20000-35 three-phase oil-immersed on-load voltage-regulating power transformer

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Loading Port:: Shanghai

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Supply Capability:: 1000sets set/month

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Production introduction

The product conforms to the technical parameters and requirements of China National Standard GB1094 and GB/T6451,and a series of significant innovation is applied in aspects of material,design and structure.It has the features of high efficiency and low loss.It can save a lot of operation cost,and the social benefits are very significant.In conclusion,it is a nationally promoted new product and it is deeply favored by customers.

Installation type:indoor/outdoor type
Altitude:≤1000m
Installation site:in places without corrosive gases and obvious dusts.

Applicable standards

GB1094.1-2-1996 Power Transformer
GB1094.3-5-2003 Power Transformer
GB/T6451-1999 Technical parameters and requirements for three-phase oil-immersed power transformer

Model designation

Performance characteristics

1.The features of this product are high efficiency and low loss.It can save a lot of operation cost,and the social benefits are very significant.

2.The iron cores are made of the imported high-conduction magnetism,cold-roll,and grain-oriented silicon-steel sheets.The iron cores and windings adopt the vacuum drying and vacuum oil-filling processes,which make the internal moisture down to the very low level.

3.The conservator is hermetically sealed,which make the internal running oil to insolate with oxygen and moisture efficiently.

4.The above features guarantee the transformer does not need do replace the oil during the normal operation,greatly decrease the maintenance cost,and prolong the service life.

Notes for placing orders

Transformer type:rated capacity kVA
Number of phases:three-phase single-phase
High voltage:KV/Low voltage:KV
Frequency:50HZ 60HZ
Tapping range:±4×2.5% ±3×2.5% other
Connection group:Yyn0 Dyn11 other
Impedance voltage:normal other

Main technical parameters of SZ9-M-400~20000/10 series of transformers

Rated capacity(KVA)	Voltage combination(KV)			Connecting groupid	No-load lossess(W)	Load-loss(W)(75^oC)	Short circuit impedance(%)	No-load current(%)	Weight(kg)			Overal dimension(mm)	Gauge(mm)
Rated capacity(KVA)	High voltage(KV)	Tapping(%)	Low voltage(KV)	Connecting groupid	No-load lossess(W)	Load-loss(W)(75^oC)	Short circuit impedance(%)	No-load current(%)	Body	Oil	Gross weight	Length×width×height	Gauge(mm)
400	6 6.3 10	±4×2.5	0.4	Yyno or Dynll	815	4360	4.0	1.0	925	320	1610	1810×930×1250	660×660
500					970	5180	4.0	1.0	1150	400	1980	1890×1010×1350	660×660
630					1260	6380	4.5	0.9	1360	460	2320	1980×1040×1400	820×820
800					1500	7800		0.8	1560	520	2670	2030×1100×1425	820×820
1000					1740	10720		0.7	1730	620	3000	2100×1160×1500	820×820
1250					2120	12750		0.6	2020	715	3520	2180×1180×1600	820×820
1600					2700	15200		0.6	2445	890	4345	2280×1260×1720	1070×1070
2000					2790	19170	5.5	0.6	2780	1050	5010	2360×1350×1800	1070×1070

Note:
1.Please contact us for the performance parameters,outline dimensions and other importans data for 35kv transformers with bigger capacity.
2.For 8000ka and above,we can also supply transformers with air cooling device according to customer's requirements(SFZ9).
3.The weight and dimensions in table above are only for reference.

Main technical parameters of SZ9-M-2000~20000/35 series of transformers

Rated capacity(KVA)	Voltage combination(KV)			Connecting groupid	No-load lossess(W)	Load-loss(W)(75^oC)	Short circuit impedance(%)	No-load current(%)	Weight(kg)			Overal dimension(mm)	Gauge(mm)
Rated capacity(KVA)	High voltage(KV)	Tapping(%)	Low voltage(KV)	Connecting groupid	No-load lossess(W)	Load-loss(W)(75^oC)	Short circuit impedance(%)	No-load current(%)	Body	Oil	Gross weight	Length×width×height	Gauge(mm)
2000	35 38.5	±3×2.5	6.3 6.6 10.5	Yd11	2850	20000	6.5	1.00	2780	1650	6140	2750×1410×2800	1070×1070
2500					3300	21700	6.5	1.00	3300	1800	7080	2800×1430×2850	1070×1070
3150					4000	26000	7.0	0.90	3700	1910	7300	2690×2020×2940	1070×1070
4000					4900	30500		0.90	4350	2170	8550	3180×2380×3100	1070×1070
5000					5800	35000		0.85	5200	2450	9950	3250×2500×3150	1070×1070
6300				YNd11	7000	38500	7.5	0.85	6500	2740	11800	3370×2600×3290	1070×1070
8000					9900	42700		0.75	7770	3320	14500	3420×2740×3350	1475×1360
10000					11700	50500		0.75	9100	3850	16810	3350×2830×3400	1475×1360
12500					13770	59800	8.0	0.70	10630	4640	19800	3680×2950×3500	1475×1475
16000					16570	72000		0.70	13300	5360	23300	3800×3080×600	1475×1475
20000					19580	85000		0.60	17450	7100	30800	4000×3250×3800	1475×1475

Q: A transformer is a two coil component that uses electromagnetic induction to pass an AC signal from its input to its output.?How and why are transformers used on electric wires? What would be their purpose??Why do we hear that these transformers break at times?: 1. Transformers are used to step up (or step down) AC voltage/current. Further, they can provide electrical isolation from two circuits (There is no physical connection between the two sides of a transformer). 2. Transformers can break for a lot of reasons, i.e. excessive heat, too large of a load, environmental breakdown, faulty manufacturing, etc

Q: Devices that convert the car battery's 12 V DC into 110 V AC are easily available. The conversion from 12 V DC into 110 V AC is done in 2 steps. One circuit in the device changes DC into AC and transformer changes the voltage. Does it matter which step is done first and why?Any help would be awesome! Thanks!: transformers do not change DC values. Do not hook a transformer to DC. Depending on how the connections are made, it may be a short circuit.

Q: Transformers of the three transformations are the three?: Do not know you specifically refers to the meaning, in general, the transformer can change the voltage, variable current, variable phase

Q: Transformers are divided into several. What is the role of each? To be specific!: Types and characteristics of commonly used transformers ?????Commonly used transformer classification can be summarized as follows: ?????1, according to the number of points: ?????(1) single-phase transformer: for single-phase load and three-phase transformer group. ?????(2) three-phase transformer: for three-phase system of the rise and fall voltage. ?????2, according to the cooling method points: ?????(1) dry-type transformers: rely on air convection cooling, generally used for local lighting, electronic circuits and other small-capacity transformers. ?????(2) oil-immersed transformers: rely on oil as a cooling medium, such as oil from the cold, oil-cooled air-cooled, oil-soaked water, forced oil circulation. ?????3, according to the use of points: ????(1) power transformer: for the transmission and distribution system of the rise and fall voltage. ?????(2) instrument with transformers: such as voltage transformers, current transformers, for measuring instruments and relay protection devices. ?????(3) test transformer: to produce high pressure, the electrical equipment for high-pressure test. ?????(4) special transformers: such as electric furnace transformers, rectifier transformers, adjust the transformer and so on. ?????4, according to the winding form points: ?????(1) Double winding transformer: Used to connect two voltage levels in the power system. ?????(2) three-winding transformer: generally used in power system area substation, connecting three voltage levels. ?????(3) Autotransformer: Power system for connecting different voltages. Can also be used as a normal step-up or down transformer. ?????5, according to the core form points: ?????(1) core transformer: for high voltage power transformers. ?????(2) shell transformers: special transformers for high current, such as electric furnace transformers, welding transformers; or for electronic equipment and television, radio and other power transformers.

Q: What is the principle of the conversion of the transformer? How to restore the secondary side to the primary side?: 1. The principle of the return is the balance of the magnetic potential before and after the countdown. The various energy relations should remain unchanged. 2. Potential and voltage of the count: the transformer once the number of turns W1, the number of turns on the secondary side W2, W1 / W2 = k ??? There is a return after: E2 '= k * E2 ????????????????????????????? U2 '= k * U2

Q: Branch circuit cables are rated for 75?C and feeder cables are rated for90°C. This will be a 3-phase, 575-volt system with four induction motors, specified asfollows:Motor 1: 60 hp 0.90 p.f. squirrel cage motorMotor 2: 60 hp 0.90 p.f. squirrel cage motorMotor 3: 40 hp 0.85 p.f. wound rotor motorMotor 4: 7-1/2 hp 0.80 p.f. wound rotor motorA) Assuming no line losses, find the capacity of the transformer required to supplypower to this system.B) Assume that it is desired to improve the overall power factor for this system to 0.95lagging. Determine, in kVAR, the required capacitance for this power factorcorrection.C) Assume these motors have their windings connected in a delta configuration. Whatwould be the line voltage if they were connected in wye?: I would look in the NEC for the full load amperes of these motor sizes. These are: 7.5 HP9 amps 40 HP.41 amps 60 HP.62 amps The 7.5 HP motor KVA will be KVA 575 * 9 * 1.732 8.9631 The 7.5 HP motor KW will be KW 575 * 9 * 1.732 * 0.8 7.17048 The KVAR of this motor is Sqrt(8.9631^2 - 7.1705^2) 5.3778 The 40 HP motor KVA will be KVA 575 * 41 * 1.732 40.8319 The 40 HP motor KW will be KW 575 *41 * 1.732 * 0.8 5 34.707115 The KVAR for this motor is Sqrt(40.8319^2 - 34.7071^2) 21.5095 The 60 HP motor KVA will be KVA 575 * 62 * 1.732 61.7458 The 60 HP motor KW will be KW 575 *62 * 1.732 * 0.8 5 55.5712 The KVAR for this motor is Sqrt(61.7458^2 - 55.5712^2) 26.9141 The total KVA requirement for all motors running at once is 8.9631 + 40.8319 + 61.7458 + 61.7458, which is 173.2866 KVA (note this is the requirement from a transformer, not the size of the transformer The total KW of all the motors is 7.1701 + 34.7071 + 55.5712 + 55.5712 153.0196 KW The total KVAR of all the motors is 5.3778 + 21,5095 + 26,9141 + 26.9141 80.7145 KVAR The power factor for all the motor is KW / KVA 153.0196 / 173.2866 0.883 I took a short cut at this point and used an application i wrote to calculate the required capacitor KVAR. The results follows: At 0.95 power factor, the motors' KVA will be 161.065 The motors' KW will be the same. The motors' KVAR will be 50.2926 The required capacitor's KVAR will be 53.988 The reactance of the capacitor will be 10.65 ohms The capacitance will be 3.49059248 E -4 Farads You can calculate these values as I did above, if you want to. EDIT Forgot the last answer. The line voltage is the same for both delta and wye. The leg voltage for the wye motor will be 575 / 1.732 331.98 volts TexMav

Q: Hi:I found a 10,000 WATTS STEP UP TRANSFORMER.Following are its characteristics: 1- 10,000 Watt Maximum Capacity Heavy-Duty Continuous Use Transformer. 2- Converts 110/120V upto 220/240 VoltsWhat will be its input?I means which battery or Generator i have to use for its input?Is it good idea to use that transformer to supply electricity to 1 house?: If you live in USA or Canada,electricity voltage is 115v. You may connect the two wire that mark with 120v into the house electric main power panel,use a 10 amperes breaker to protect your house power source if the transformer that you found is defective. The output shall produce 240v,it is good to run a stove or dryer,because they need 240v. Some country house does not have 240v source. If you live in other country that using 240v power source. You may use this tranformer to produce 120v to run some electronic device that buy from USA. Or you may join the 120v coil with the 240v coil in series to produce 360v .

Q: I wa watching the films and was wondering how the transformers just spawn more and more. For example soundwave made the panther thing then it made the thin robot and all those construction guys too, then they made the huge robot with the balls.: Haha, well from what I remember, the bodies were assembled on cybertron. But that wasnt it. In order to create actual life the transformer needed The Matrix, an orb (or in the live action movies, a slender metal thingy?) which would allow a spark from the Allspark (which is essentially transformer heaven if I remember correctly) to enter the body and give it life. This can also reanimate deceased Transformers. The only other times I remember transformers coming to life in the show, is when the autobots found the Dinobots and somehow brought them back to life? Then there was the world eater, Unicron, who was able to upgrade other transformers. An example would be the transformation of Megatron into Galvatron made possible by Unicron.

Q: Three-phase transformer how to calculate the current, ah, the formula is?: Calculation formula and empirical formula of transformer secondary current Three-phase transformer current calculation formula I = S / (root number 3 * U), where U is the transformer line voltage, KV Transformer Current Experience Port Algorithm: Primary Current I ≈ S * 0.06 Secondary Current I ≈ S * 1.5 For example: a 500KVA transformer to calculate the current and secondary current, with the current formula I = S / (root 3 * U) I = 500 / root 3 * 10 = 500 / 17.32 ≈ 28.8AI = 500 / root 3 * 0.4 = 500 / 0.69 = 724.6A with the transformer current experience calculation formula: I = 500 * 0.06 ≈ 30A I = 500 * 1.5 = 750A Transformer operating load requirements For example: a 800KVA10 / 0.4KV transformer, according to the first and second current calculation, a variety of load current is how much? Solution: Primary current I = S * 0.06 = 800 * 0.06 = 48A Secondary current I = S * 1.5 = 800 * 1.5 = 1200A Low load: Primary current I = 48 * 15% = 7.2A Secondary current I = 1200 * 15% = 180A Reasonable load: primary current I = 48 * 50% = 24A Secondary current I = 1200 * 50% = 600A Full load: primary current I = 48 * 75% = 12A Secondary current I = 1200 * 75% = 900A

Q: i have fuses and everything that i can use to test my primary but should i add more turns on the primary side? yes i know line voltage is dangerous. yes i have worked with it before and know how to work around it.: A bit confused, but it seems you want a power supply of 12 volts DC at 5 amps, and this has nothing to do directly with the schematic you reference. The primary is connected to 120 VAC? The power is 60 watts plus, call it 100 watts, which is 0.8 amps in the primary. 500 turns should be more than enough. It could be as low as 120 turns, but that depends on the core material and construction. .

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