• Square Steel Billet, Square Bar, Mild Steel Billet From China Manufacturer System 1
  • Square Steel Billet, Square Bar, Mild Steel Billet From China Manufacturer System 2
Square Steel Billet, Square Bar, Mild Steel Billet From China Manufacturer

Square Steel Billet, Square Bar, Mild Steel Billet From China Manufacturer

Ref Price:
get latest price
Loading Port:
China main port
Payment Terms:
TT OR LC
Min Order Qty:
1000 m.t.
Supply Capability:
50000 m.t./month

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Specification

Standard:
GB
Technique:
Hot Rolled
Shape:
Square
Surface Treatment:
Dry
Steel Grade:
Q195,Q215,Q235
Certification:
ISO,SGS,CE
Thickness:
60mm-150mm
Width:
60mm-150mm
Length:
6-12m
Net Weight:
24
Packaging:
Bare Packing



Square steel billet, square bar, mild steel billet best price from China manufacturer

Square Steel Billet, Square Bar, Mild Steel Billet From China Manufacturer 

Name:Square bar
LENGTH:6 meter to 12 meter (+ 50mm)
Size:100*100, 120*120, 150*150, 200*200
Grade:3SP,5SP,Q235,20MnSi.
Shape:Square, Round
Technique:Hot-Rolled
Standard:ASTM/GB
BENDINGNo more than 5mm in 1 meter
No more than 30mm in 6 meter
No more than 60mm in 12 meter
ANGULAR TWISTNo more than 1 degree per meter and not more than 6 degree over 12 meter length.
Chemical compositionC, Si, Mn, P, S, N, etc

 
 Product Description

Chemical Properties

Size60*60/90*90/100*100/120*120/150*150
Length6000mm-12000mm
StandardGB
ApplicationTo produce bars or other applications
GradeQ195/Q235/Q275/3SP/5SP/20MnSi
Packing termsTT/LC
PackageMill's standard packing or as client's requirement
Delivery timeWithin 10-30 days after receiving the deposit or LC

 
Chemical Composition

StandardC(%)Mn(%)S(%)P(%)Si(%)
Q195≤0.12≤0.50≤0.040≤0.035≤0.30
Q235≤0.20≤1.40≤0.045 ≤0.045≤0.35 
Q275≤0.22≤1.50≤0.045≤0.045≤0.35
20MnSi0.17-0.251.2-1.6≤ 0.050≤ 0.0500.40-0.80
3SP0.14-0.220.40-0.85≤ 0.050≤ 0.0400.05-0.15
5SP0.28-0.370.50-1.00≤ 0.050≤ 0.0400.15-0.30


FAQ

1. Q: Where is your company located? How can I visit there? 

A: Our company is located in Beijing, China. Welcome to visit us.

2. Q: Can I get sample and how long will it take?

A:Yes.  We can supply sample.  And you need to pay for courier.  

3. Q: What's the MOQ?

A: Our MOQ is 1000mt.  

4. Q: What's the delivery time?

A: It will take about 30-45 days after TT or L/C.  

5. Q: What is the payment terms?

A: T/T, L/C at sight

6. Q: How does your factory carry out quality control?

A: We attach great importance to quality control.Every part of our products has its own QC.

7. Q: What certificate do you have?

A: We have SGS, ISO9001 etc. Also we can apply any certificate if you need if the qty is OK.


Q: Can steel coils be coated with silicon?
Yes, steel coils can be coated with silicon.
Q: What are the different methods of tempering steel coils?
There are several methods of tempering steel coils, including air tempering, oil tempering, salt bath tempering, and induction tempering. Each method involves heating the steel coils to a specific temperature and then allowing them to cool slowly to achieve the desired level of hardness and toughness. Air tempering involves exposing the steel coils to ambient air for gradual cooling, while oil tempering involves immersing them in heated oil. Salt bath tempering involves placing the coils in a bath of molten salt, and induction tempering uses electromagnetic induction to heat the coils. The choice of tempering method depends on the specific requirements of the steel and the desired properties of the final product.
Q: I live in Dubai. I want to make a damascus steel sword and have no idea where to get the steel or what sort of steel I should get.First to adress the access of my steel...I need to get some low carbon and high carbon steel for the Damascus....what sort of steel is recommended for this? Also where would I be able to get my hands on it (Internet options e.g websites or locations)THANKS
Damascus Steel Swords For Sale
Q: I know that mild steel is more brittle than cast iron....but that is all.......please help??Thank you in advance......Ruby:D
Mild steel is iron that has had most of the carbon removed in an open hearth furnace or a Bessemer converter. It is mainly the carbon content that makes iron brittle (iron is brittle, not steel).
Q: engineering sloutions related to steel fabrication
not okorder /
Q: How are steel coils used in the production of pipes and tubes?
Steel coils are an essential component in the production of pipes and tubes. They are used as the raw material to create the cylindrical shape of the pipes and tubes. The coils are unrolled and fed into a machine called a pipe or tube mill, where they undergo a series of manufacturing processes. First, the steel coils are unwound and straightened to remove any bends or twists. Then, the edges of the coils are trimmed to ensure they are smooth and even. This process is known as slitting. Next, the coils are passed through a forming machine, where they are bent into the desired shape. For pipes, the coils are bent into a circular shape, while for tubes, they can be formed into various shapes, including square, rectangular, or oval. Once the coils have been formed, they are welded together along the length to create a continuous pipe or tube. This welding process can be done using various techniques, such as high-frequency induction welding, electric resistance welding, or submerged arc welding. After the welding is complete, the pipes or tubes may undergo additional processes to improve their properties. These processes can include heat treatment, such as annealing or quenching, to enhance their strength or hardness. Finally, the pipes or tubes are cut to the desired length and may undergo further finishing processes, such as straightening, polishing, or coating, depending on their intended application. In summary, steel coils are used in the production of pipes and tubes as the starting material. They are unrolled, straightened, and formed into the desired shape before being welded together to create a continuous pipe or tube. These products can then undergo various additional processes to improve their properties and meet specific requirements.
Q: What are the common methods of slitting or shearing steel coils?
The common methods of slitting or shearing steel coils include rotary shear, guillotine shear, and laser cutting.
Q: what is the difference between metal and steel
well, steel is a type of metal. It's sort of like asking the difference between a bug and an ant, an ant is a bug, but not every bug is an ant. Likewise, steel is metal, but not all metal is steel. Gold is metal, Silver is metal, Iron is metal, Steel is metal.
Q: steel welding with ms steel iron
Welding austenitic stainless steels to carbon and low alloy steels are established methods in the process and construction industries. Dissimilar metal welds involving stainless steels can be done using most full fusion weld methods, including TIG (Tungsten Inert Gas) and MIG (Metal Inert Gas). Weld procedures using filler (consumable) enable better control of joint corrosion resistance and mechanical properties. In selecting the weld filler, the joint is considered as being stainless, rather than the carbon steel. Over-alloyed fillers are used to avoid dilution of the alloying elements in the fusion zone of the parent stainless steel.
Q: A 100 kg solid steel ball with a radius of 5 m is being spun on ice with an angular velocity of 5 rev/s pointed into the ice (clockwise rotation when viewed from above).A student shoots a 10 kg marble at the steel ball. The marble hits the ball along its side as shown with an initial velocity of 5 m/s to the left. If, right after the collision, the final velocity of the marble is 2.5 m/s to the left, what is the angular velocity of the steel ball after the collision?
You need to do conservation of angular momentum about the steel ball's axis. Angular momentum = I.ω The steel ball's initial ω = 5 rev/s = 5*2pi rad/s = 31.4 rad/s The steel ball's moment of inertia I = (2/5)*m*r^2 = 40*25 kg.m^2 = 1000 kg.m^2 The marble's initial ω = v / r where r is the perpendicular distance from the steel ball's axis You need to look at the diagram for this. The marble's I about the steel ball's axis is I = m*r^2 where r is the same as above. (marble is treated as a point mass). Then work out the total initial ang. momentum = final ang. momentum and solve for ω...

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