• scaffolding steel pipe support shoring props nuts System 1
  • scaffolding steel pipe support shoring props nuts System 2
scaffolding steel pipe support shoring props nuts

scaffolding steel pipe support shoring props nuts

Ref Price:
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Loading Port:
Tianjin
Payment Terms:
TT OR LC
Min Order Qty:
-
Supply Capability:
5万 m.t./month

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Quick Details

Type:
Scaffolding Parts
Scaffolding Part Type:
Scaffolding Props,Formwork
Thread:
Machine tap
surface treatment:
galvanized
painted:
powerd coated
diameter:
10,12,14mm
thickness:
2.0mm-3.5mm
Packaging Detail:
Bag or Pallets
Delivery Detail:
Meet customer needs

Packaging & Delivery

Packaging Detail:Loose, in bundle, plastic film, or as your request. shippment in container
Delivery Detail:20-40days

Specifications

scaffolding prop nut
1.Ductile iron,casted or machine tap thread
2.Pitch:10.0 or 6.35mm
3.Pin: Dia.10.12, 14 or 16mm

scaffolding prop nut

1. Material: Ductile Iron

2. Nut Size: Dia 60 mm, Pin : dia.12,14 or 16 mm

3. Pitch: 6.0mm or 6.35mm

4. Nut weight: different weights

5. Surface: Electro galvanized

6. Thread: Casted thread or machine tap thread

7. Type: all types of Wing nuts, jack nuts,prop nut

8.Quality Control for Large amount production to Ensure  Good Quality Products

9. Packing: Bags or pallets.


Adjustable

Outer pipe

inner pipe

Theoretical

20 ft Container

length(m)

tube(mm)

tube(mm)

Weight(kgs)

can load(pcs/bulk)

0.8-1.4

48×1.6×765

40×1.8×835

4.74

3500

1.6-3.0

48×1.6×1600

40×1.8×1600

7.57

2200

2.0-3.5

48×1.6×1710

40×1.8×2000

8.45

2000

2.2-4.0

48×1.6×2000

40×1.8×2200

9.32

1750

1.6-2.9

56×1.6×1510

48×1.8×1600

8.95

2200

1.8-3.1

56×1.6×1510

48×1.8×1800

9.36

2100

2.0-3.6

56×1.6×1750

48×1.8×2000

10.29

2000

2.2-4.0

56×1.6×2010

48×1.8×2200

11.26

1750

1.4-2.7

60×2.0×1340

48×2.0×1400

9.45

2300

2.0-3.5

60×2.0×1540

48×2.0×2000

11.38

2000

2.2-4.0

60×2.0×1840

48×2.0×2200

12.7

1750

3.0-5.5

60×2.0×2540

48×2.0×3000

16.51

1500(40ft/in bulk)



Q: Method for inspection of foot hand frame fittings
Or "low pressure fluid delivery welded steel pipe" GBT 3092
Q: Write a scaffold method for 743,425 divided by 365EASY 10 points
use a calculator you punk, nobody writes out division anymore, grab your ti-84 and type it out... there's your scaffold method jerk.
Q: What are the requirements for the sampling inspection of scaffolding?
Quality specification for the cantilever support1 the material of the suspension bearing frame should have the certificate of quality and quality inspection report;2 the height and length of the weld shall meet the design requirements, and shall not have any defects such as welding cracks, structural deformation, corrosion and so on;3 the production quality of the suspension frame shall be in conformity with the provisions of appendix D table D.1.
Q: What does scaffold one's days mean? kill time?
In 60 years of using English in Britain I have not come across that expression, so it is probably rare. Scaffolding is put up to help build or repair tall buildings, so possibly that expression means 'to do something useful with one's time.' But a scaffold is also, historically, a place of execution (legal killing of prisoner), so the expression could mean indeed 'wasting time'. I have a faint feeling that 'scaffold one's days' was written by a non-native speaker of British English. It may be more common in the USA.
Q: Fastener type steel pipe scaffold accessories
Wall pieceEven the wall piece the upright rod is connected with the main structure together, available steel tube, fastener or embedded part. Rigid wall, also can be used as a flexible reinforced wall connecting piece of the tie bar.
Q: Can you identify Scaffold Grade Aluminum tubing by looking at it.?
The grade or type of Aluminum Alloy materials can not be identified visually because they are almost all the same in appearance. Normally these materials are marked with there Alloy number or designation like, 6061- T6, at certain intervals so that users can distinguish them.
Q: i have some ?'s on the scarlett letterWhat effect has the 7=year interval had on Dimmesdale ?
you can see how weak morally dimmesdale is, because he keeps his hand over his heart all the time, and is constantly beating himself up over his crime. he whips himself in the closet, and brands himself with a scarlett a to match hesters. hester... when she first walks out on the scaffold she can be seen as defiant, as if she isn't ashamed of the embellished letter a she wears. the cottage she lives in is on the edge of the town, bordering the forest. towards the end of the 7 years, her actions can be seen as repent maybe for her crime: she is a self ordained sister of mercy, helps the poor and homeless, sews... and the a turns from adultery to able
Q: Scaffold removal should comply with those requirements......
Preparation of scaffold safety demolition before demolition1 check the scaffold fastener connection, the wall, the support system is in line with safety requirements.2 according to the inspection results, supplement and improve the design of the demolition process, and after the implementation of the approval.
Q: what do you think?pain wise? i know it's going to hurt as it's a peircing (duh) but will it hurt especially as it's two thick pieces of cartilage?
I think industrial (or scaffold) piercings look pretty damn cool. It will obv hurt, but nothing out of the ordinary. Also, remember its just painful for a sec and then you got an awesome piercing for as long as you want!
Q: A 520 kg box sits 1.4 m from the left end. What is the tension in the right hand side wire? (g = 9.8 m/s2) ____________ Newtons
Because the scaffold is not moving, we can assume that the net Torque acting on the scaffold equals zero. Net Torque = 0 torque = Force x distance (d) Use the left end of the scaffold as the center point. This will eliminate the Torque caused by the left wire (d = 0, so torque = 0) There are now three forces creating torque on the scaffold. There is the weight (m x g) of the scaffold, at 3.5m from the left end. m1 x g x 3.5m There is the weight of the crate, located 1.4m from the left end: m2 x g x 1.4m These two torques are countered by the torque caused by the Tension (T) of the right wire, located 7m from the left side. T x 7m The sum of these torques is zero. (T x 7m) - (m1 x g x 3.5m) - (m2 x g x 1.4m) = zero solve for T T = ((m1 x g x 3.5m) + (m2 x g x 1.4m)) / 7m T = ((115kg x 9.8m/s^2 x 3.5m) + (520kg x 9.8m/s^2 x 1.4m)) = 1.58 x 10^3 N Hope this helps.

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