S-Stage (Quick Stage) Systems, Standards

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Loading Port:: Tianjin

Payment Terms:: TT OR LC

Min Order Qty:: 10000 PCS

Supply Capability:: 10000 PCS/month

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Quick Details

Place of Origin:	Maharashtra India	Brand Name:	UE	Model Number:	04-01
As per the clients requirements:	Exporting Products

Specifications

Made from 48.3OD x 4mm thick Steel Tubes with housings at four directions at right angles. Standards have spigot welded to them.

S-STAGE (QUICK STAGE) SYSTEM

Consist of Standards with wedge housing welded to them at 500mm centers in four directions at right angles. Ledgers and Transoms with banana end brackets connect to the verticals with positive locking wedges fit in the wedge housings of standards. The Diagonals have a swiveling bracket with positive wedge locking to the standards. Standards are erected on adjustable Base Jack to cope with variation in Ground level.

Made from 48.3 OD x 4 mm thick Steel Tubes with housings at four directions at right angles. Standards have spigot welded to them to connect one above the other. Standard sizes are 9ft.9in, 6ft. 6in & 3ft3in.
Conforms to BS Standards.
Dip painted to give protection inside the tubes

The elements constituting the system:

§ Vertical element

§ Horizontal element

§ Lower universal jack and jack nut

§ Upper universal jack and jack nut

§ Connection tool for vertical elements

§ Beam supporting element

§ Console

§ Base jack

Q: What is the composition of the scaffolding tubes?: The okorder /

Q: Where can I find safety standards for Scaffolding?: ANSI A10.8-2001 Safety Requirements for Scaffolding Scope: Establishes safety requirements for the construction, operation, maintenance, and use of scaffolds used in the construc- tion, demolition and maintenance of build- ings and structures.

Q: i got my scaffolding pierced yesterday and my mum told me to clean it 2-3 times a day but im not sure if this will be healthy for my piercing?can anyone tell me how often is healthy please?many thanks ^^: i havent got that piercing yet, but i do have a friend who has it. your mom is right clean it atleast 2-3 times a day. once in the moring - once when you come back from school [ if you dont go to school ] at 4:00 - 5:00 - and once when your about to go to bed. if you dont feel like cleaning it 3 times just make sure you do it atleast twice, or instead of doing the full cleaning - with the soap and stuff just clean it fully twice and remove the crusties in the afternoon - youll get alot of those ;P and that would be itt . . . (: GOODLUCK ! :)

Q: I've had it for 3 months, and a keloid has just formed. I was told to put hydrogen peroxide on it with the regular 2x salt and hot water a day... but the piercing keeps healing and scabbing over the bar (inside), and i need to twist it so it doesn't get stuck.it is SO painful and happens after like 5 minutes of twisting the bar.I can't stand the pain anymore, is there any way to prevent this?: DONT TWIST IT. DONT USE PEROXIDE. If you twist it, itll drag the crust and any germ on the outside of it, INTO the piercing. Your best bet is to continue with the sea salt soaks, and if its infected, i advise seeing a physician to get antibiotics to kill the infection. Whatever you do, if it IS infected, do NOT take out the jewelery, no matter what the circumstances. It will cause thew holes to close, trapping the infection inside your ear. If it isnt infected, and the keloid gets any larger than it is now, REMOVE THE JEWELERY. Keeping it will only cause the keloid to swell and grow. If you remove it, it will reduce the pressure on the area and the keloid might shrink and dissapear.

Q: I've had it for roughly five weeks, I've never had one and the piercer didn't really mention a rough time scale to leave it in, I really want to change my piercing jewelry because at the moment its a plastic jewelry piece. so can anyone answer please?? thanks: No you should at least wait 3 months or so. -J

Q: So i got my peircing yesterday and it was swollen and now its bruised. I know thats normal but today is day 2 and it still is very sore and is throbbing. I cleaned it twice yesterday and 4 times today by soaking my ear in salt water. But the ear that i got pierced looks very different from the other ear that i didnt pierce. My right ear is swollen even outside of the area i got pierce, in between the fistulas. And on the back of my ear. This is the first piercing ive gotten outside of my first lobe piercing 8 years ago. I didnt sleep on it. If someone can tell me if its infected I'd appreciate it.: you got the piercing yesterday, swelling pain and bleeding are all normal and expected. It is not infected unless it is oozing yellow or green puss, is very red, very painful, and radiating heat. If this isn't happening, then it isn't infected. Over cleaning it can cause an infection, so you should only clean it 2 - 3 times a day with sea salt soaks. It looks normal, it looks a bit swollen, but that is very normal because it is a fresh piercing. it takes 6 - 12 months for this type of piercing to heal.

Q: A scaffold of mass 51 kg and length 6.0 m is supported in a horizontal position by a vertical cable at each end. A window washer of mass 87 kg stands at a point 1.8 m from one end.(a) What is the tension in the cable closer to the painter? (b) What is the tension in the cable further from the painter?: m? = mass of the scaffold = 51 kg m? = mass of the painter = 87 kg L = length of the scaffold = 6 m d = distance between the painter and end of the scaffold = 1.8 m g = acceleration by gravity = 9.8 m/s? Using the end of the scaffold that is the furthest away from the painter as pivot point, you can find the tension in the cable that is closest to the painter. m?×g×L/2 + m?×g×(L - d) = Tclose×L Tclose = 846.72 N < - - - - - - - - - - - - - - - - - answer a Using the end of the scaffold that is closest to the painter as pivot point, you can find the tension in the cable that is the furthest away from the painter. m?×g×L/2 + m?×g×d = Tfar×L Tfar = 505.68 N < - - - - - - - - - - - - - - - - - - - answer b Check: Tclose + Tfar = (m? + m?)×g (846.72 N) + (505.68) = ((51 kg) + (87 kg))×(9.8 m/s?) . . . . ? 1352.4 N = 1352.4 N . . . . . . . . . . . . . . . . . . . . . . . . . . . .! Seems OK

Q: I've been looking through a bunch of songs, but none of them seem to fit how Hester would feel when she's being ridiculed by everyone at the marketplace. I though of Boston by Augustana, Lights by Ellie Goulding, but then I didn't think they fit: who says by selena gomez. HAHA not really. what about regina spektor, the call or maybe dream by priscilla ahn i dunno... or maybe try the lonely by christina perri. blah. i feel like i was no help

Q: the methods early scientists used to measure sizes and distances within the solar system, explain the technique Eratosthenes used to measure the circumference of the Earth more than 2,000 years ago. how do all these discoveries demonstrate the scaffolding of knowledge? and there are other parts i have already im just stuck on this!!: Each generation build it's knowledge or the previous one. In simple words your father teaches you. You make it better Then you teach the better method to your son We learned to take cover in caves, then we learned to build huts and then we learned to build houses and then build skyscrapers. Hope this is what you wanted.

Q: A 100 kg scaffold is 7 m long. It is hanging with two wires, one from each end. A 600 kg box sits 1.8 m from the left end. What is the tension in the left hand side wire?(g = 9.8 m/s2)answer in newtons: This question can be solved by first drawing a free-body diagram and then summing the moments (torques) around the right end of the scaffold. We'll designate the tension in the left hand wire with T. So after making our free-body diagram we find the sum of the moments around the right end of the scaffold (where each moment = force x distance from point we are taking it about), setting it to zero because the system experiences no angular motion 0 = 7m * -T + 600kg * 9.8m/s^2*(7m - 1.8m) + 100kg * 9.8m/s^2 * 3.5m (Notice that T is negative because it would produce a clockwise rotation about the right end of the scaffold, and the weights are positive because their rotation would be counter-clockwise) Now we just solve for T, which comes out to be T = 4858N

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