Mill-Finished Aluminum Coils 1xxx - Aluminum Coil Ontario
- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 3 m.t.
- Supply Capability:
- 100000 m.t./month
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1.Structure of Mill-finished Aluminum Coils 1XXX Description
Mill-finished Aluminum Coils 1XXX has great ductility, heat conductivity, anti-corrosion and moisture resistance properties.
Mill-finished Aluminum Coils 1XXX is free from Oil Stain, Dent, Inclusion, Scratches, Stain, Oxide Dicoloration, Breaks,
Corrosion, Roll Marks, Dirt Streaks and other defect which will interfere with use
2.Main Features of Mill-finished Aluminum Coils 1XXX
• Superior quality of raw material
• Reasonable and stable chemical composition
• Accurate tolerance
• Goode mechanical property
3.Mill-finished Aluminum Coils 1XXX Images
4.Mill-finished Aluminum Coils 1XXX Specification
Alloy | AA1xxx (AA1050, AA1060, AA1070, AA1100 etc. |
Temper | H14, H16, H18, H22, H24, H26, H32, O/F |
Thickness | 0.2mm -- 100mm |
Width | 30mm -- 1700mm |
Standard | GB/T 3880-2006,EN,ASTM,JIS |
5. FAQ of Mill-finished Aluminum Coils 1XXX
A.What is the package?
It is wooden pallet
B.Where is your mill located.
The mill is in Henan province.
- Q: The temperature of the water drops from 93.0°C to 78.0°C. What quantity of heat energy did the piece of aluminum absorb?
- The specific heat of Aluminum is 0.215 cal/g-°C. The calories absorbed (q) would be q = m * c * (T2 -T1) = 22.0 g * 0.215 cal/g-°C * (78.0 °C - 0.3 °C) If you have a different value for the Specific heat of Aluminum, use it in the formula for your calculations. If you knew the mass of the water, you could check your calculations because the heat gained by the Al would be equal to the heat lost by the water, using q = m * c * (T2 -T1), where m is the mass of the water, c = 1.00 calorie/gram °C, T2 = 78.0 °C and T1 = 93.0 °C. The sign of q will be negative.
- Q: Can aluminum coils be used for food processing conveyor systems?
- Yes, aluminum coils can be used for food processing conveyor systems. Aluminum is a durable and lightweight material that is resistant to corrosion, making it suitable for food processing environments. Additionally, aluminum is non-toxic and does not react with food, ensuring the safety and quality of the processed products.
- Q: How long do aluminum coils last?
- The lifespan of aluminum coils can vary depending on various factors such as usage, maintenance, and environmental conditions. However, on average, well-maintained aluminum coils can last anywhere between 15 to 20 years.
- Q: What are the typical lead times for ordering aluminum coils?
- The typical lead times for ordering aluminum coils can vary depending on various factors such as the supplier, quantity, customization requirements, and current market conditions. However, on average, lead times can range from a few weeks to a couple of months. It is advisable to contact the specific supplier for accurate information regarding their lead times.
- Q: Can the displacement sensor be used for real-time measurement of the aluminum coil thickness?
- Yes, you can use two sensors to measure thickness, either contact sensor or laser sensor
- Q: if the resistivity of aluminium is 2.7×10-8 Ωm
- Let ρ be the resistivity of the aluminum cable, A the cross sectional area of the cable and l the cable's length. The resistance R of the aluminum cable is now given by: R = ρ·l / A = 2.7·10^-8·(10·10^3) / (π·r?) = 2.7·10^-8·(10·10^3) / (π·(1·10^-3)?) = 85.9 Ω I guess the tricky part is remembering: R = ρ·l / A but when you realize how intuitive this equation is you don't have to memorize it. The resistance R is proportional to the resistivity ρ, so we must have the following in our equation: R = ρ·k , where k is some value governed by the dimensions of the cable! It is logical that the resistance is also proportional to the wires length l. This is logical when you realize that the longer the wire the more obstacles the electrons will have to pass by! Now we have that: R = ρ·l·c , where c is another value governed now by the cross sectional area (only dimensional property left). If we think of the wire as a highway with cars instead of electrons we realize that there is less resistance (higher speed) when the highway has many lanes and is very broad. From this we realize that the greater the cross sectional area the smaller the resistance. R must therefore be inversely proportional to A. We now have: R = ρ·l / A I hope there are no mistakes here :P
- Q: What does 1060 stand for in 1060 aluminum rolling?
- Aluminum coils can be divided into 9 categories, among which 1060 series is one kind, standing for 1050, 1060. Series 1000 is called pure aluminum plate which contents most aluminum with purity above 99.00% and is most common in general industries. As no other technical elements are involved, the production process is simple and the price is relatively cheap. The majority in the current market are series 1050 and 1060. The last two digits in series 1000 indicate the required aluminum content. For example, the last two digits series 1050 is 50. According to International Grades Naming Principle and Chinese Aluminum Alloy Technical Standard (gB/T3880-2006), the aluminum content of qualified series 1050 must reaches 99.5%.
- Q: what is the final temperature of 250g of water whose initial Temperature is 25 C if 80-g of aluminum initially at 70 C is dropped into the water? The specific heat of aluminum is 0.215 cal/C g how do you do it? our teacher did not show us how and it is not in the book
- Given Data :-- Mass : Aluminium m(a) = 80 g, Water m(w) = 250 g Initial Temperature : Aluminium t? = 70 C and Water t?' = 25 C Final Temperature of both ( aluminium and water ) = T C (assume) Since Aluminium is initially at a temperature higher than that of water, it (aluminium) will lose heat to water . Heat lost by Al = Q = mass of Aluminium x sp.heat capacity of Aluminium x Temp. change = Q = 80 x 0.215 x ( 70 - T ) cal Heat gained by water = Q' = mass of water x sp.heat capacity of water x Temp. change = Q' = 250 x 1 x ( T - 25 ) According to principle of calorimetery . = Heat lost by aluminium = heat gained by water. = 250 x 1 x ( T - 25 ) = 80 x 0.215 x ( 70 - T ) = T = 27.9 C .... ( Rounded to one decimal place )...... Answer Answer .
- Q: How are aluminum coils protected from corrosion?
- Aluminum coils are protected from corrosion through various methods, including the application of protective coatings such as paint or anodizing, using corrosion-resistant alloys, and applying a layer of zinc through a process called galvanizing. These protective measures create a barrier between the aluminum surface and external elements, preventing corrosion and extending the lifespan of the coils.
- Q: How are aluminum coils used in the production of marine vessels?
- Aluminum coils are used in the production of marine vessels primarily for constructing the hulls and superstructures. These coils are transformed into various shapes and sizes through processes like rolling, cutting, and welding to form the frames, panels, and other structural components of the boats. Aluminum's lightweight yet strong nature makes it an ideal material for marine vessels as it ensures fuel efficiency, corrosion resistance, and durability, ultimately enhancing the vessel's overall performance and longevity.
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Mill-Finished Aluminum Coils 1xxx - Aluminum Coil Ontario
- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 3 m.t.
- Supply Capability:
- 100000 m.t./month
OKorder Service Pledge
OKorder Financial Service
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