• Cutting and Transporting Equipment---Automatic System for Cutting Strips and Bricks System 1
  • Cutting and Transporting Equipment---Automatic System for Cutting Strips and Bricks System 2
  • Cutting and Transporting Equipment---Automatic System for Cutting Strips and Bricks System 3
Cutting and Transporting Equipment---Automatic System for Cutting Strips and Bricks

Cutting and Transporting Equipment---Automatic System for Cutting Strips and Bricks

Supplier:
Xi'an Research and Design Institute of Wall & Roof Materials Co,.Ltd.
Ref Price:
get latest price
Loading Port:
China main port
Payment Terms:
TT OR LC
Min Order Qty:
1 unit
Supply Capability:
50 unit/month

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Model

ZWQT

ZWQPDsingle

ZWQPDdouble

Maximum section of columnwidth x height

Match with extruder

Strip length

950mm

1280-3050mmAccording to different models

maximum cutting speed

40m/mindistance of run 350

24m/mindistance of run 600

20 times/minAccording to different models

17 times/minAccording to different models

Cutting table height

800mm

Device Dimensions

2120x1320x1600mm

2450-3850x2600x1560mm

2450-3850x3050x1560mm

total power

2kw

9-16.5kwAccording to different models

9-16.5kwAccording to different models

Note: Use with extruder.

 

Product description:

It consists of automatic vertical slitting machine, automatic vertical brick cutting machine, grouping conveyor, pusher and servo bricking machine. All use servo motor as power source and PLC control to realize automatic production of the whole line. New integrated wire hanging device, fast adjustment, reduce wire breakage, short spring automatic brake, clutch system, no motor frequent start, extended service life, quick transition between primary and secondary pushing modes (some accessories need to be replaced). Feeding belt and roller table are optional. The belt tabletop feeds the billet to reduce the damage of the billet bottom and the impact deformation of the mud head. The servo motor can be selected to push the billet, and the intermediate stop of the billet is simpler, and the power is strong and no impact.


Q: Bq: have you read elfen liedBq2: favorite quote from a book
Kyrie- Mr. Mister Bq: No. Bq2: And in its sky was such a sun as no opium eater could have imagined in his wildest dreams. Too hot to be white, it was a searing ghost at the frontiers of the ultraviolet. (Childhood's End-Arthur C. Clarke-Chapter 16-The Last Generation)
Q: Jan. 1 Retired a piece of machinery that was purchased on January 1, 2001.The machine cost$62,000 on that date. It had a useful life of 10 years with no salvage value.June 30 Sold a computer that was purchased on January 1, 2008.The computer cost $40,000. Ithad a useful life of 5 years with no salvage value.The computer was sold for $14,000.Dec. 31 Discarded a delivery truck that was purchased on January 1, 2007. The truck cost$39,000. It was depreciated based on a 6-year useful life with a $3,000 salvage value.InstructionsJournalize all entries required on the above dates, including entries to update depreciation,where applicable, on assets disposed of. Ingles Company uses straight-line depreciation. (Assumedepreciation is up to date as of December 31, 2010.)
You didn't state the year in which these transactions occurred. I'm assuming 2011. Jan. 1, 2011 Retired a piece of machinery that was purchased on January 1, 2001.The machine cost $62,000 on that date. It had a useful life of 10 years with no salvage value. Annual depreciation = $62,000/10 = $$6,200 By December 31, 2010, the machinery would be fully depreciated. Dr Accumulated depreciation $62,000 Cr Machinery $62,000 June 30, 2011 Sold a computer that was purchased on January 1, 2008.The computer cost $40,000. It had a useful life of 5 years with no salvage value.The computer was sold for $14,000. Annual depreciation = $40,000/5 = $8,000 By December 31, 2010, the accumulated depr account would have a balance of $24,000 (3 yrs) You need to depreciate another 6 mths to June 30, 2011 Dr Depreciation expense $4,000 Cr Accumulated depreciation $4,000 after which the accum. depr. would be $28,000, and the carrying amount $12,000. If it was sold for $14,000, there would be a gain of $2,000 Dr Accum depr $28,000 Dr Cash $14,000 Cr Computer $40,000 Cr Gain on disposal of computer $2,000 Dec. 31, 2011 Discarded a delivery truck that was purchased on January 1, 2007. The truck cost $39,000. It was depreciated based on a 6-year useful life with a $3,000 salvage value. Annual depr = ($39,000 - $3,000)/6 = $6,000 By December 31, 2010, the accum. depr. = $24,000 (4 yrs) You need to update depreciation by 1 yr Dr Depreciation $6,000 Cr Accum depr - Truck $6,000 after which the accum depr = $30,000, and the carrying amount = $9,000 Dr Accum depr $30,000 Dr Loss on scrapping of vehicle $9,000 Cr Vehicle $39,000
Q: Is machinery still being built?
yes it is
Q: Shouldn't insurance companies start considering this when insuring businesses?
yes, as long as the imaginary friend doesn't give them drugs and alcohol on the job.
Q: I am going to be an interveiwer interveiwing either a Boatswain Mate or a Machinery Technician. I need links to websites with information about these types of people and their jobs because I need some information. Thank you.
Boatswain okorder
Q: Please introduce a link that explain these functions in a list or categorical. I would prefer new and interesting functions.Thank you
Fluid okorder /
Q: I have tried so many things, but I cannot figure out how to do this. I need to wrap one fabric around a different fabric. My problem is that it not only wraps the fabric, but it gets stuck on the bar and wraps around it as well. Are there any machines that can wrap fabrics together?
sewing machine
Q: This is really our project to investigate, what's the significance of this and how it is done attractively? Yah, were going to defend it by the questions from the judges. What could be the possible questions? Does anyone have an idea? If you give me a detail answers, I will not refuse to give you 10 points.
the significance would be it makes the farmer's easy for their work about that, you better study it
Q: He plans to invest $20 000 every six months in an investment account with a view to replacing machinery. What interest rate will he need to meet his goal?(either use present formula A= P *(1-(1+i)^(-n))/ i or future formulaS = P *( (1+i)^(n) - 1)/ i, im not sure wich formula to use)PLEASE SHOW ALL WORKING OUTplease help me ITS URGENT
use S = P((1+i)^n-1)/i 275000 = 20000((1+i)^12 -1)/i ((1+i)^12-1)/i = 275000/20000 = 13.75 this can't be solved analytically as it is a polynomial of degree 12 feeding into wolfram alpha, i ≈ 0.0244147= 2.4415% now remember that this is the rate adjusted for periodicity, so interest rate needed = 4.883% <-------- check: --------- 20,000((1+0.04883/2)^12-1) /(0.04883/2) = $275000.48
Q: Where can I find supplier of Agriculture Miniature machinery?
TRADE POST CATALOG THEY ARE ONE OF THE LARGEST SUPPLY OF MINIATURES DONT MISTAKE THEM FOR ORENINTAL TRADING POST THEY ARE ON THE WEB

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