Black or Galvanized U -head Scaffolding Jack Base
- Loading Port:
- Tianjin
- Payment Terms:
- TT OR LC
- Min Order Qty:
- -
- Supply Capability:
- 500000根 pc/month
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Scaffolding Jack Base
1.Steel material: Q235
2.Length:Customized.
3.Hollow .
4.Shpae of base: U head, plain head.
5.Surface treatment: Oiled Color painted, Hot dip galvanized, Electro galvanized
6.Usage:Scaffolding part, adjusts the balance of scaffolding frame.
Adjustable Scaffolding Base jack
Size: 35/38x4mm, 143x143x5/6mm, 600,914,1524mm
Material: Q235
Surface finish:painted,galvanized
Type: base jack, top jack
Diameter: 30mm, 32mm, 34mm, 36mm, 37mm, 38mm, 40mm
Length: 400mm, 600mm
Base plate: 140*140*5mm
OEM service provided
Screw Jack Base
Dimensions: Diameter 35/38mm, Base plate 143x143x5/6mm, length 600,914,1524mm
Item | Screw Jack Base |
Material | Q235 |
Dimensions | 35/38mm, 100x150mm, 600,914,1524mm |
Surface | Hot-dip galvanization, electro galvanization ,or as your request |
Standard | EN74 |
Note | OEM service is available |
MOQ | 1000pieces |
Package | in steel pallet, or as your request |
Payment Terms | TT,L/C, we can contact in detail |
Delivery Time | 20-30days |
Feature of screw jack base:
1) Base plates provide extra stability.
2) Enables safe use on uneven ground.
3) Galvanization for long lasting protection.
4) Elements safely connected.
Type: base jack, top jack
Diameter: 32mm, 34mm, 38mm
Length: 400mm, 600mm
Base plate: 120*120*5mm, 140*140*5mm, 150*150*6mm
OEM service provided
- Q: Will the scaffolding steel pipe specifications are generally how much ah? What are the specifications?
- Scaffolding erection specifications are as follows, if you want to do more understanding, then please look carefully Oh, a lot of content, looks a bit boring
- Q: Two window washers, Bob and Joe, are on a 3.00 m long, 380 N scaffold supported by two cables attached to its?
- Oh, Ashley, you can't fit more than an intro in the what would you like to ask. More room in details.
- Q: A man of mass 60.3 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 21.5 kg and is 2.3 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope? Left Rope?Can someone please explain HOW you do this question!? Thanks!
- this is a 2d concern. The moments approximately any component interior the gadget could desire to stability, in any different case the gadget (scaffold) might rotate. additionally, the vertical forces could desire to stability, or the gadget (scaffold) might translate. it style of feels to me that to the spectacular from the middle of the scaffold this is a distance one 6th of the dimensions of the scaffold is the comparable as announcing 2-thirds from the left-edge of the scaffold. The moments could be summed approximately any component. i will evaluate the left edge of the scaffold, the place the 2d produced by utilising the left rope is 0. finished M = 0 = scaffold M + guy M + spectacular rope M 0 = 23.7kg*9.8m/s^2*(3.1m/2) + 60.1kg*9.8m/s^2*(2*3.1m/3) - F*3.1m wherein: the scaffold is assumed to be a component mass placed at its middle the tension F acts opposite to the load of the guy and the scaffolding, and subsequently has -ve sign sparkling up for F. To get the tension in the different rope, you may basically evaluate the vertical forces interior the gadget. besides the fact that, you're able to desire to sum the moments approximately another component (say, the spectacular rope). desire this enables.
- Q: How to do a good job in typhoon prevention work in rural areas?
- Close the doors and windows, so as not to be strong wind blowing, check and tightly easy to be the wind to the objects, such as windows
- Q: Two painters are standing on a 5.0 mg long scaffold. Each painter weighs 833 N. 1 painter is standing 2.0 mg from the left end and 1 is standing .50 mg from the right end. The scaffold weighs 285 N. What is the tension in the 2 cables supporting the scaffold?
- Summing torques at the left cable T2*5-833*2-285*2.5-833*4.5=0 T2=1225 N Summing torques at the right cable T1*5-833*3-285*2.5-833*.5=0 T1=726 N Check 833*2+285-(1225+726)=0 It checks j
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- Q: There is a 6.0-kg pail of paint to one side.How close to the left end can he approach safely? How close to the right end can he approach safely? Can someone help me with this problem, I keep working and reworking it and coming to the same answer. I must be consistently making the same mistake. If someone can help me work through it I would really appreciate it. The answers I got were:Left: dmin, left = .54mRight: dmin, right = .77m
- At the threshold of danger, the tension on the far rope reaches zero. (a) Distance from left edge = x; then summing moments about the left rope gives ΣM = 0 = 71.0kg * g * (1m - x) - 22.0kg * g * 2.0m - 6.0kg * g * 1m The g term cancels, and the rest solves to x = 0.296 m ? (b) Distance from right edge is X; summing about the right rope, and knowing the g terms will cancel, ΣM = 0 = 22.0kg * 2m + 6.0kg * 3m - 71.0kg * (1m - X) leads to X = 0.127 m ? Hope this helps!
- Q: Will the concrete cloth machine and the tower crane is different, long quite like Please explain the structure of the application, 3Q
- Oh, that love what the lay it? Concrete is the end of the concrete pumping equipment, the role is to pump the concrete through the pipeline to be poured to pour (to say that the "building" is the word is also lay it, huh, huh) components within the template
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Black or Galvanized U -head Scaffolding Jack Base
- Loading Port:
- Tianjin
- Payment Terms:
- TT OR LC
- Min Order Qty:
- -
- Supply Capability:
- 500000根 pc/month
OKorder Service Pledge
OKorder Financial Service
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