Three-Phase Or Single-Phase Universal Type MR-J4-20B Servo Amplifier
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- Loading Port:
- Shanghai
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 kg
- Supply Capability:
- 2000 kg/month
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Specification
Specification of sscnetiii / h mr-j4-20b for Mitsubishi servo amplifier 200W:
[output]
. rated voltage: three-phase ac170v
. rated current: 1.5A
[main circuit power input]
. power frequency: three-phase or single-phase ac200v ~ 240V 50Hz / 60Hz
. rated current: 1.5A
. allowable voltage variation: three-phase or single-phase ac170v ~ 264v
. allowable frequency variation: ± 5%
. capacity of power supply equipment: 0.5kva
. surge current: 30A (reduced to about 3A after 20ms)
[control circuit power input]
. power frequency: single phase ac200v ~ 240V 50Hz / 60Hz
. rated current: 0.2A
. allowable voltage variation: three-phase or single-phase ac170v ~ 264v
. allowable frequency variation: ± 5%
. power consumption: 30
. surge current: 20 ~ 30A
[power supply for interface]
. voltage? Frequency: DC24V ± 10%
. power capacity: 0.3A (including CN8 connector signal)
[control mode] sine wave PWM control current control mode
[dynamic brake] built in
[communication function]
. USB: connection with personal computer, etc. (corresponding to Mr
configurator2)
[position control mode]
. maximum input pulse frequency: 4mpps (differential input), 200kpps (open
collector input)
. positioning feedback pulse: encoder resolution (resolution of servo motor per
revolution) 22 bits
. command pulse magnification: electronic gear A / b times a = 1 ~ 16777216, B
= 1 ~ 16777216, 1 / 10 < A / b < 4000
. positioning completion pulse width setting: 0pulse ~ ± 65535pulse (command
pulse unit)
. excessive error: ± 3 Revolutions
. torque limit: set through parameter setting or external analog input (dc0v ~
+ 10V / maximum torque)
[speed control mode]
. speed control range: analog speed command 1:2000, internal speed command
1:5000
. analog speed command input: dc0v ~ ± 10V / rated speed (the speed at 10V can
be changed through [pr.pc12])
. speed change rate: ± 0.01% (load change: 0% ~ 100%), 0% (power change: ±
10%) ± 0.2% (ambient temperature: 25 ± 10 ℃). Only when analog speed command
is available
. torque limit: set through parameter setting or external analog input (dc0v ~
+ 10V / maximum torque)
[torque control mode]
. analog torque command input: dc0v ~ ± 8V / maximum torque (input impedance:
10K? ~ 12K?)
. speed limit: set through parameter setting or external analog input (dc0v ~
± 10V / rated speed)
[protection function]
Overcurrent protection, regenerative overvoltage protection, overload
protection (electronic thermal relay), servo motor overheating protection
Encoder abnormal protection, regeneration abnormal protection, insufficient
voltage protection, instantaneous power failure protection
Overspeed protection and excessive error protection
[safety function] sto (IEC / en 61800-5-2)
[safety performance]
. third party certification specification: EN ISO 13849-1 type 3 PL D, en 61508
SIL 2,
EN 62061 SIL CL2，EN 61800-5-2 SIL 2
. response performance: less than 8ms (STO input off → energy cut-off)
. test pulse input (STO): test pulse cycle: 1Hz ~ 25Hz test pulse off time:
max. 1ms
[structure (protection level)] self cooling open (IP20)
[compact installation] adjustable
[weight] 0.8kg
- Q: What is the meaning of the transformer capacity unit KVA?
- KVA for apparent power, its size and power factor! For example: power factor cosΦ = 0.8 active power P = 1Kw Then tgΦ = 0.75, so the square of the apparent power S = the square of P + the square of P * tgΦ When the power factor is 1, 1KVA = 1KW
- Q: I have 13 lights with 12 volts 35 Watts on each light for each tree, the outlet is 120 volts current now. Should I buy 300Watt or 600Watt low volts transformer to supply all lights? Need your advise!
- 600 W.
- Q: 440 kv(Primary side) and then at the receving station its step down from 440kv(primary side of the step down transformer) 33 kv.in the tranmission line,between both the primary side of the transformers the voltage is 440kv.then how the power flows in tranmission lines?
- Gawd I don't know where people go to school to make up rubbish about the power being too high for use in homes. Just get a few facts and make the rest up. Ok When electricity is generated in a central power station the electricity needs to be transmitted many miles. The most efficient way of doing this is to use as high a voltage as possible. So at the power station a transformer is used to convert the generated voltage into a high voltage for transmission. When the electricity arrives at the destination it is transformed back down to whatever voltage the end user requires. The reason for using the high transmission voltage is to reduce resistive losses in the cables. I'll give an example Suppose we need to go 100 miles and have a resistive load of 1 ohm/mile We need to deliver 1MW down to the end of the line and the end voltage required is 100V We'll ignore the voltage drop for the example, but you can do homework to take it into account. If we transmit at 100 volts then applying W VI we need I 10^6/10^2 10^4 amps We have 10 ohms in the transmission path so resistive losses are I^2 . R (10^4)^2 . 10 10^9 Watts That is one heck of a loss! Now, if we transmit as 100kV 10^5V then our current is now 10^6/10^5 10 amps Applying I^2 . R for our resistive losses we now get 10^2 . 10 10^3 watts You can see the VAST difference that stepping up the voltage for transmission does now for the transmission loss.
- Q: I will vote for the best answer based on the use of simple vocabulary, I don't know much about transformers so try to keep it as understandable as possible. I know it's not a simple subject, thanks!
- Transformers are made with laminated plates for reasons of magnetic flux, reluctance and heat dissipation. They have been designed by very qualified engineers, more so than I, and have stood the test of time. Try the site below.
- Q: A transformer consists of 250 primary windings and 838 secondary windings. If the potential difference across the primary coil is 25.5V , what is the voltage across the secondary coil ? If the potential difference across the primary coil is 25.5V , what is the effective load resistance of the secondary coil if it is connected across a 135Ω resistor?
- Transformer equation, N_pV_pN_sV_s V_s (N_p V_p)/N_s, plug in the numbers and calculate. N_p/N_s sqrt(Z_p/Zs)
- Q: Transformer if the boost and buck current will change? According to the power of the same should be high voltage side of the current point is also the opposite? Boost and buck can be specified?
- According to the formula P = √3IVcosφ ,, in the case of P unchanged, V increases, I on the drop, V down, I on the rise in the case of the transformer load is constant, increase the voltage and current drop, reduce the voltage and current rise; The
- Q: The total power of 590kw, this transformer can bear it? It is best to give a formula, do not copy the.
- 600KVA box can generally increase the number of households with electricity
- Q: Can somebody please help me understand this problem and help me do it? I'm having a hard time with it and help would be greatly appreciated.The following test data were obtained from short-circuit and open-circuit tests of a 50-kVA, 2400-600 V, 60Hz transformer.Voc600V Vsc76.4 VIoc3.34 A Isc 20.8 APoc 484 W Psc 754 WDetermine:A) the equivalent high-side parameters;B) RegulationC)efficiency at rated load and .92 power-factor for lagging.
- read material regarding transformers Not just once but say 5 times, till you understand what is said. the transformer has copper loss due resistance of primary and secondary. It has additionally iron loss. The equivalent circuit is a sort of representation that brings in these losses. generally you can apply a low voltage to primary till shorted secondary has a current equal to less than rated current. These measurement details are given. Similarly open circuit measurement details are available. With understanding of how the rest can be calculated using worked examples in texts, you can solve it yourself. attempt this See Lee's book on transformers or schaums series on electrical engg.
- Q: If a transformer is rated for a maximum winding current of 10A, would it be permissible to operate it with 10A of input current when the secondary voltage to the load is 40V? Can you explain to me why?The information on the auto transformer plate wasInput 240V/ 50/60 cy 3HPoutput 0-240/280V 20 ampsThe parallel load resistance is 34.5 ohms
- fr76ftfyt
- Q: i have a bunch of transformers and they have the dates like i have optimus prime it says takara hasbro 1980-1982 and all the other toys say hasbro or takara! and most are made from 1982 -1985 also i have jet fire but the stamp doesn't say hasbro or takara but it does say bandai 1984!
- this is defined in the action picture, which occurs between Season 2 and Season 3. additionally, word that new characters ensue in particularly some episodes devoid of rationalization, and not in easy terms in Season 3.
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Three-Phase Or Single-Phase Universal Type MR-J4-20B Servo Amplifier
- Ref Price:
-
- Loading Port:
- Shanghai
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 kg
- Supply Capability:
- 2000 kg/month
OKorder Service Pledge
OKorder Financial Service
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