• Scaffolding Single Putlog Coupler System 1
  • Scaffolding Single Putlog Coupler System 2
Scaffolding Single Putlog Coupler

Scaffolding Single Putlog Coupler

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Loading Port:
China Main Port
Payment Terms:
TT OR LC
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Quick Details

Place of Origin:
Shandong China (Mainland)


Model Number:
SD-3017B
Type:
Scaffolding Parts
Scaffolding Part Type:
Scaffolding Couplers
Material:
Q235
Size:
48.3mm
Weight:
0.65kg
Surface:
Electroplate
Standard:
BS1139
Bolt:
Split Ball Bolt
Name:
Putlog Coupler

Packaging & Delivery

Packaging Detail:Putlog Coupler packed with woven bags+steel pallet
Delivery Detail:20-30 days

Specifications

Putlog Coupler
Material:Q235
Size:48.3mm
Weight:0.65kg
Surface: Electroplate

BS1139 Scaffolding Single Putlog Coupler

Product Detail:

  1. Name: Putlog Coupler

  2. Size:48.3mm

  3. Weight:0.65kg

  4. Surface: Electroplate

  5. Standard: BS1139

  6. Packing: woven bags +steel pallet

  7. Shipping Term: FOB, CIF, CFR

  8. Payment Term: T/T, L/C, Western Union


Q: I'm trying to understand a problem in my physics book. The problem is this:A person is pulling on a rope, that is connected to a pulley on the ceiling. The rope then goes to a box with a pulley on it, and then up to the ceiling where the rope is connected (to the ceiling).The rope and pulleys are massless and frictionless.The book lists three forces (tension forces) going up and one weight force pulling down.My question is, why isn't there another force pulling against the tension of the rope from the guy pulling the rope?
a million. pass to: study your answer on your question internet site. 2. form in: Newton/2nd regulation of action/guidance/info? 3. pass to: Newton's 2nd regulation of action, an get admission to on internet site considered one of headings provided. examine the precis on the precise of the internet site and something you prefer/prefer under the crimson field interior the middle of the internet site.
Q: I think that'd be extremely entertaining.
new jack dont want to work with wwe
Q: For the current stage of China's construction should not strengthen the specific meaning of scaffolding and support by way of the scaffolding and support the specific distinction and significance
In order not to be involved in the whole system due to local errors, the scaffold must be separated from the formwork support, forming a stable system.
Q: A scaffold is constructed by placing two supports under a 13 ft, 9 in (a) board weighing 84 lbs. The supports are each 2 ft, 8 in (b) from their respective ends. Two painters stand on the board; one weighs 158 lbs and stands 4 ft, 11 in (c) from the left end of the board. Where must the 222 lbs painter stand so that each support carries the same weight? (express your distance in feet from the right end of the board (d).)please help!! thanks(:
Total weight = 222 + 158 + 84 = 464 lb So, each support must carry 232 lbs Working in inches: Take moment about Right hand end Board is assumed to be uniform - CG is at the center (232 x 32) + (232 x 133) = (158 x 106) + ( 84 x 82.5 ) +(222 x d)7424 + 30856 = 16748 + 6930 + 222d 222d = 14602 d = 65.77 inches Distance of 222 lb painter should be 5ft 5.77inches from Right end
Q: I had my scaffold done on friday, and it's still very sore and swollen. My boyfriend's accidentally caught it a couple of times but not badly and i was wondering if the pain and swelling is normal and if there's anything i can do for it. I've been cleaning it with savlon and have been careful with it x
If it gets worse you should swear loudly at yourself for being so stupid.
Q: i have some ?'s on the scarlett letterWhat effect has the 7=year interval had on Dimmesdale ?
you can see how weak morally dimmesdale is, because he keeps his hand over his heart all the time, and is constantly beating himself up over his crime. he whips himself in the closet, and brands himself with a scarlett a to match hesters. hester... when she first walks out on the scaffold she can be seen as defiant, as if she isn't ashamed of the embellished letter a she wears. the cottage she lives in is on the edge of the town, bordering the forest. towards the end of the 7 years, her actions can be seen as repent maybe for her crime: she is a self ordained sister of mercy, helps the poor and homeless, sews... and the a turns from adultery to able
Q: I know its between chapters one and two, duh. Haha, but yeah, I needa do this thing on Edmodo for school, but i accidentally left my book in my locker.):I tried looking at online versions, but you know it's so hard, right? Looking and seeing all these different versions and I cant find the place...I need where she entered the scaffold because I need to cite where she thinks about how she's accepted her quot;sinquot;. So yeah~ PLEASE HELP! ( gt; . lt; )
i'm no longer completely constructive of the answer to this actual question, yet I only finished a unit in this novel and could like to help with any extra questions...be satisfied to invite -Alice
Q: I know it's soon, but my piercings swollen and quite sore when knocked slightly.I've only had it three or four days, but there's a swollen round lump right next to one pierced hole and I was worried it could be an early sign of a keloid. But I don't know if it's too soon to tell yet.I know they can take up to 6 months to heal, if not more, but I'm kinda paranoid about it.I've rinsed it after showering, used salt water on it every day and apart from that just washed it with water on a cotton bud.Any advice?
I had my industrial for 13 months and it never healed. I decided to retire it and the piercing sites closed up within 6 hours. Seriously, my advice to you is to just take it out. They are wayyyy more trouble than they are worth.
Q: A 520 kg box sits 1.4 m from the left end. What is the tension in the right hand side wire? (g = 9.8 m/s2) ____________ Newtons
Because the scaffold is not moving, we can assume that the net Torque acting on the scaffold equals zero. Net Torque = 0 torque = Force x distance (d) Use the left end of the scaffold as the center point. This will eliminate the Torque caused by the left wire (d = 0, so torque = 0) There are now three forces creating torque on the scaffold. There is the weight (m x g) of the scaffold, at 3.5m from the left end. m1 x g x 3.5m There is the weight of the crate, located 1.4m from the left end: m2 x g x 1.4m These two torques are countered by the torque caused by the Tension (T) of the right wire, located 7m from the left side. T x 7m The sum of these torques is zero. (T x 7m) - (m1 x g x 3.5m) - (m2 x g x 1.4m) = zero solve for T T = ((m1 x g x 3.5m) + (m2 x g x 1.4m)) / 7m T = ((115kg x 9.8m/s^2 x 3.5m) + (520kg x 9.8m/s^2 x 1.4m)) = 1.58 x 10^3 N Hope this helps.
Q: Hi(: My names Tasha, and I love piercings. (I have 8) And I want to get an industrial piercing(Some call it a scaffold). But my ear doesn't have a bend like most people do.I got my first four piercings done by a professional. But felt I was much more comfortable having my brother(22) do it. Since he's someone I know, and hes done piercings and stuff before.
person above me obviously didnt read LOL. anyways as to your problem you might have to bend your ear a bit while you are piercing it but this mite cause the jewlry to pull forward, you could also go higher up, change the angles or you could do a vertical industrial which would look gud with ur other pericings

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