• Cuplock system ledger / Scaffolding System / Horizontal / Runner System 1
  • Cuplock system ledger / Scaffolding System / Horizontal / Runner System 2
  • Cuplock system ledger / Scaffolding System / Horizontal / Runner System 3
Cuplock system ledger / Scaffolding System / Horizontal / Runner

Cuplock system ledger / Scaffolding System / Horizontal / Runner

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Loading Port:
China main port
Payment Terms:
TT OR LC
Min Order Qty:
100 pc
Supply Capability:
10000 pc/month

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Cuplock system ledger / Horizontal / Runner


Structure of cup lock Description

cup lock system is one of the most popular used scaffolding system in the world.It is consisted of cup lock,vertical,ledger,limit pins,blades and base etc.


Use

Ledgers are the horizontal members of ringlock scaffolding, they provide horizontal support for loads and planks.


Product description:

1.suitable for buildings like bridges, tunnels, large-scale construction projects, water conservancy project ,ship buildings, and so on.

2.latest wedge lock system is easy assembly and time saving. Due to its high stability and bearing capacity ringlock scaffolding is popular in the world.

3.made by high-strength welded pipe (48X3.0-3.5mm).


Surface finishing: 

Hot Dipped Galvanized ( HDG)


Main Features of cup lock

1) Using less pipes

2) Easy to install

3) It can be used again and again for nearly 20years

 

Cup lock product pictures

Cuplock system ledger / Scaffolding System / Horizontal / Runner

Cuplock system ledger / Scaffolding System / Horizontal / Runner

 

Cup lock Product Description

Type:

ringlock scaffolding   diagonal Brace

specification

Ø48.3×3.20

material:

steel Q235

Finished

Hot DIP galvanized,   painted

Diagonal length(m)

Weight(kg)

0.9m * 1.25m

6.28

1.25m * 1.8m

8.6

1.25m * 2.7m

11.45

Q: There is a 5.0 kg pail of paint to one side, as shown. How close to the end can he approach safely? Express your answer using two significant figures. If there is more than one answer, separate them by commas.
I am looking for as shown, as I am not psychic.
Q: - Construction safety and quality control report for the depth of construction quality and construction safety production, to ensure the safety and use of structural features to prevent the fall, collapse, mechanical injuries and other multiple accidents,
How is offshore oil mining?The method of lifting the oil from the bottom of the hole to the ground by the energy of the reservoir itself or by the artificial supply
Q: Why the height increase of ten centimeters increase in housing ten percent
Jian'an cost is the cost of housing construction and housing equipment installation costs for short
Q: Please advise the construction industry experts: residential full scaffolding inside the frame how to calculate the number of steel pipe needs, pay attention, I asked how many meters! Or tell me how many meters per square meter of steel pipe? And then attached to the high requirements, thank you For example: now a layer of 1000 square meters area, a total of 10 standard layer of residential buildings, 3 meters high! How to calculate the amount of steel required to do a layer? The amount of steel pipe in meters, or tonnage units.
Look at how many holes are needed with a few meters of steel pipe
Q: On the issue of compensation after the event of force majeure
The cleaning and repair costs of the works do not include scaffolding
Q: There is a 6.0-kg pail of paint to one side.How close to the left end can he approach safely? How close to the right end can he approach safely? Can someone help me with this problem, I keep working and reworking it and coming to the same answer. I must be consistently making the same mistake. If someone can help me work through it I would really appreciate it. The answers I got were:Left: dmin, left = .54mRight: dmin, right = .77m
At the threshold of danger, the tension on the far rope reaches zero. (a) Distance from left edge = x; then summing moments about the left rope gives ΣM = 0 = 71.0kg * g * (1m - x) - 22.0kg * g * 2.0m - 6.0kg * g * 1m The g term cancels, and the rest solves to x = 0.296 m ? (b) Distance from right edge is X; summing about the right rope, and knowing the g terms will cancel, ΣM = 0 = 22.0kg * 2m + 6.0kg * 3m - 71.0kg * (1m - X) leads to X = 0.127 m ? Hope this helps!
Q: for 10 sq. meters = ? h/sq. m. and how many person need to do the job?
It depend upon availability sorting of ledger to be used.If prop ledger has been transported sorted then three person can do 10 sqm in maximum 3/4 hour .i.e.0.075 h/sqm
Q: 2009 and 2010 construction of secondary construction division of the exam questions and answers, Jiqiu ~!
(Construction project) single multiple choice questions (a total of 20 questions, each question 1 points
Q: Will the concrete cloth machine and the tower crane is different, long quite like Please explain the structure of the application, 3Q
Forearm (long horizontal part) with more than 125mm of the pipe, and there is drooping hose (a bit like elephant nose, huh)
Q: A man of mass 74.4 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 21.9 kg and is 3.9 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope? b) What is the tension in the left rope? thanks in advance.
this could be a 2d concern. The moments approximately any factor interior the gadget would desire to stability, in the different case the gadget (scaffold) would rotate. additionally, the vertical forces would desire to stability, or the gadget (scaffold) would translate. it form of feels to me that to the superb from the middle of the scaffold it somewhat is a distance one 6th of the dimensions of the scaffold is comparable to saying 2-thirds from the left-edge of the scaffold. The moments could be summed approximately any factor. i will evaluate the left facet of the scaffold, the place the 2d produced by the left rope is 0. comprehensive M = 0 = scaffold M + guy M + suited rope M 0 = 23.7kg*9.8m/s^2*(3.1m/2) + 60.1kg*9.8m/s^2*(2*3.1m/3) - F*3.1m wherein: the scaffold is considered a factor mass located at its center the strain F acts opposite to the load of the guy and the scaffolding, and subsequently has -ve sign remedy for F. To get the strain in the different rope, you are able to basically evaluate the vertical forces interior the gadget. on the different hand, you should sum the moments approximately another factor (say, the superb rope). wish this permits.

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