• Carbon Black N330 Granluar System 1
  • Carbon Black N330 Granluar System 2
  • Carbon Black N330 Granluar System 3
Carbon Black N330 Granluar

Carbon Black N330 Granluar

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Loading Port:
Tianjin
Payment Terms:
TT OR LC
Min Order Qty:
-
Supply Capability:
10000MT m.t./month

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Carbon Black N330 (Granule)

Product Description:

carbon black N330:
1.Usage Rubber Auxiliary Agents;
2.Product Status:Black powder or granular;
3.Standard: ISO 9001:2000

Suggest for Use:


(1) Uses for the tire tread, cord rubber, tires and various rubber industrial products inside.
(2) Usage, and the FDA is a kind of reinforcement for good performance of carbon black, can give a good strong rubber elongation, tear resistance, abrasion resistance and flexibility. So that the FDA's passenger tire rolling loss (hysteresis loss) only in the N300 series carbon black is greater than N351, than the other varieties are small, dispersed in the rubber compound and pressure out of the performance is also good for all kinds of synthetic rubber and natural rubber.

TDS of the Carbon Black N330

Product Varieties

N330

Pouring density(kg/m3)

340~420

Iodine absorption Value(g/kg)

77~87

300%modulus(Mpa)

-1.9~0.1

DBP absorption Value (10-5m2/kg)

97~107

Ash content

≤0.7%

24Mn DBP(10-5m2/kg)

83~93

45um sieve residue

≤0.05%

CTAB surface area(103m2/kg)

76~88

500um sieve residue

≤0.001%

STSA/(103m2/kg)

70~80

Impurity

NO

Nsa surface area(103m2/kg)

73~83

Fine content

≤10%

Tint strength(%)

99~109

Tensile strength(Mpa )

≥-5.0

Heatloss(%)

2.5

Elongation at failure

≥-20%

Safety:

As a matter of good industrial hygiene, gloves and safety glasses with side shields or better eye protection should be worn when handing Carbon Black ,For more information, refer to the MSDS.




Q:Chemical production of iodine and magnesium with water as catalyst!
In the 250mL three bottles were equipped with spherical condenser and constant pressure dropping funnel, in the condensate tube connected to the anhydrous calcium chloride drying tube. The flask was placed with 1.5 g of magnesium chip and a small tablet of iodine, 10 g of bromobenzene and 30 mL of anhydrous ether were mixed in a constant pressure dropping funnel. First 1/4 of the mixture into the flask, a few minutes later see the magnesium surface of the bubble generated, the solution was slightly cloudy, iodine color began to disappear. If no reaction occurs, use a hot water bath. After the start of the reaction, stir, slowly dropping the remaining bromophene ether solution, dropping the rate to keep the solution was slightly boiling state, after adding, in the water bath to continue reflow 0.5h, magnesium tablets full effect.
Q:What is a catalyst in a chemical reaction?
A catalyst provides an alternative reaction pathway with a lower activation energy. So it speeds up the rate of reaciton because the energy of the particles/reactants doesnt have to be that high to OVERCOME the activation energy so it can therefore react. The activation energy is the minimum amount of energy required for particles to react, so the lower it is, the more faster a rate of reaction will be.
Q:Does increasing the amount of catalyst added to, say, a solution of Hydrogen Peroxide, make the rate of reaction go faster. Is the rate of reaction directly proportional to the amount of catalyst added to the solution? Or does the experiment go at the same rate regardless of how much catalyst there is? Thanks would really appreciate some answers. - Sarah
Catalyst do not participate in the reaction but it speeds up the reaction. If you increase the amount of catalyst from the required amount, it would somehow negates its positive response or it would result in producing another product.
Q:Just something I've always wondered about...
activation energy has got nothing to do with this. the main reason that the transition metal oxides are catalysts is that they have vacant d orbitals. the reagents are adsorbed on the metal surface and the d orbitals serve as a sort of clamp between the substrates and reagents. for example if you consider the hydrogenation of ethylene in palladium catalyst here the d orbitals lead to syn addition of hydrogen by clamping the pi electron cloud . this is a sort of chemisorption.
Q:And hydrogen peroxide
Yes, as long as it is copper ions and iron ions on the line, such as FeCI can
Q:Why does the chemical and chemical properties change before and after the reaction?
A catalyst that accelerates the chemical reaction, called a positive catalyst; a catalyst that slows the chemical reaction, called a negative catalyst. For example, the hydrolysis of esters and polysaccharides, commonly used inorganic acid as a positive catalyst; sulfur dioxide oxidation of sulfur trioxide, commonly used vanadium pentoxide as a positive catalyst, this catalyst is solid, the reactants for the gas, the formation of multi-phase catalytic, , Vanadium pentoxide is also called catalyst or contact agent; edible oil by adding 0.01% to 0.02% gallate n-propyl ester,
Q:Can chemical reaction limits be changed by catalyst or other methods?
No, the catalyst can only speed up the chemical reaction, but can not change the chemical limit.
Q:What is the difference between biological enzymes and chemical catalysts?
The biological enzyme is a class of molecules with moderate molecular weight in the living cells. It is a natural macromolecule catalyst in nature because the enzyme and the reactants are more specific than the reaction of the catalyst with the chemical synthesis of the catalyst (1) High efficiency (2) selectivity good by-product less (3) mild reaction conditions and so on
Q:Who knows hydrogen and nitrogen in the high temperature, high pressure and catalyst conditions for the synthesis of ammonia chemical equation ah? Urgent! The SOS
3H2 + N2 ===== 2NH3
Q:Cl + O3 ---> ClO + O2O + ClO ---> Cl + O2= O + O3 ----> 2O2What is the catalyst? The intermediate?How do you know which is which? If the rate law is rate=k [O3] [Cl]determine:a) the overall order.b) unit for k.c) the rate determining step, justify your answer.
Cl is the catalyst. ClO the intermediate. The catalyst is the component which does not change in overall reaction. He forms some intermediate component(s) with the reactants. In the later reaction steps the intermediate(s) react forming the catalyst in its original state. (a) The overall order is the sum of the orders with respect to the components: n = 1 +1 = 2 (b) the unit of the rate of reaction is r [=] mol/ (Ls) (more general mol per unit time and volume) compare dimensions mol / (Ls) [=] k · mo/L · mol/L =k [=] L/(s mol) (more general unit volume per unit time and mole) (c) First reaction For elementary reaction steps the order of the reaction rate with respect to a reactant is equal to stoichiometric coefficient. Hence the rate of first reaction is: r? = k?·[Cl]·[O?] Overall rate is given by the rate determining step, while other reaction steps are in equilibrium: r = r? = k?·[Cl]·[O?] If second reaction is the rate determine step r? = k?·[O]·[ClO] while reaction 1 is at equilibrium K? = ( [ClO]·[O?] ) / ( [Cl]·[O?] ) =[ClO] = K?·( [Cl]·[O?] ) / [O?] the overall rate would be: r = r? = k?·[O]·[ClO] = K?·k?·[O]·[Cl]·[O?] / [O?] = k·[O]·[Cl]·[O?] / [O?] That doesn't match the observed rate law

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