SVC LED Automatic Voltage Stabilizer

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Loading Port:: Shanghai

Payment Terms:: TT OR LC

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Supply Capability:: 10000pcs pc/month

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1.Application
SVC(LED) automatic voltage stabilizer consists of contact voltage regulator,sampling control cir-cuit and servomotor as well.It has excellent features,such as small waveform distortion,highefficiency,high power factor,free from the effect or frequency variation of supply.It can bewidely used in most situations where the voltage stabilization is required.
2. Specification

Input voltage	150V-250V
Output voltage	220V±3%, 110V±3%
Frequency	50H/60Hz
Response time	<1sec.(against 10% input voltage deviation)
Efficiency	>90%
Ambient temperature	-10^oC~±40^oC
Relative humidity	<90%
Waveform distortion	Non-lack fidelity waveform
Power factor cos∮	0.8
Insutalion resistance	>5MΩ

3. Outline and packing

Type	Outline(cm)			Weight(Kg)	Qty/CTN
Type	L	W	H	Weight(Kg)	Qty/CTN
SVC-D500VA	18.5	15	12.5	17	4PCS
SVC-D1000VA	21	18	14.5	20	4PCS
SVC-D1500VA	21	18	14.5	25	4PCS
SVC-D2000VA	27.5	23.5	18.5	7.8	1PC
SVC-D3000VA	29	23	22	9.8	1PC
SVC-D5000VA	45	24	18.5	14	1PC
SVC-D7500VA	47	26	22	19.5	1PC
SVC-D10000VA	47	26	22	24.5	1PC
SVC-D15000VA	42	38	73	35	1PC
SVC-D20000VA	42	38	73	68.5	1PC
SVC-D30000VA	42	38	83	80	1PC
SVC-D5000VA	28	30	46	19	1PC (Cabinet)
SVC-D10000VA	44	32	56	31	1PC (Cabinet)

Q:A want to know what happens to transformer when it is overloaded. Where i can get information about this: Yes the transformer will burn and blast if overloaded.It results due to heating effect

Q:chemical transformer.: A transformer can only work efficiently if it use a SOFT-IRON CORE. In chemistry any matter is considered a chemical. SO, the chemical' we're talking about is the soft-iron core.

Q:50kva transformer price: You have a problem is the voltage level and model do not know, can not set the price. The capacity is 50 kVA. If it is 10000 volts change 400 volts S11 50 kVA is about 9,000 yuan, S9 7500-8000, S7 is about 7000.

Q:I took apart a wall transformer before and soldered a single AA battery to the outputs and touched the what was before inputs and it gave me a shock. This is because it stepped up the power to something like 113v. Could I instead of a AA battery use 110 from the wall. Would it do the same thing. Or would it just overheat the transformer. And what would the amps be. I’m trying to make like a 20amp welder for just screwing around with.: To answer your basic question I’m trying to make like a 20amp welder for just screwing around with. Look at the rating on the transformer, most wall transformers will tell you what wattage and voltage the transformer is rated. If it says 9 watts at 1.5 volts that is all it will do no matter what you do. You can put a chopped DC on the 1.5 volt secondary and get 115 volts on the primary but at a greatly reduced current (about .075 amps max). That is the best that transformer will do but because you are using a square wave you will be a less than an optimum power transfer. If you want 20 amps at 110 volts that is some substantial power and dangerous. D.bumstead

Q:A 120 kVA, 7000/277 V (What does this rating mean) distribution transformer has the following resistances and reactances: Rp 5.5 ohms Xp 6.5 ohms Rs 0.007 ohms Xs 0.008 ohms Rc 55 kohms Xm 15 kohms The excitation branch impedance are given referred to the low voltage side of the transformer: a) What's the equivalent circuit of the transformer referred to the low voltage side b) What's the the per unit equivalent circuit c) Assume that this is supplying rated load at 277V and 0.89 lagging power factor, What is the transformer input: 120 kVA, 7000/277 V (What does this rating mean) Primary voltage rating: 7000 V, secondary voltage rating: 277 V, rated load: 120 kVA It is unclear whether this is a single-phase or three-phase transformer. You probably need to assume it is single-phase. The equivalent circuit of a 3-phase transformer is analyzed as one of three single-phase transformers that could be connected to make the equivalent Y-Y three-phase transformer. The secondary voltage, 277 V, is the line to neutral voltage for a 480 V, wye distribution system. That is a USA standard system voltage. The primary would be 12,124 V L-L, 7000 V L-N. That would a reasonable primary distribution system voltage. Referring the circuit to the low side means changing the primary component values to the equivalent secondary values and moving the ideal transformer to the primary side of the circuit as shown below. To change the primary impedance values, multiply by (Sec V/Pri V)^2.

Q:I can find them at Wal-Mart, but the smallest size they have is a 4/5 and that is too big. I am looking for 3T or 4T sizes.I saw a Transformers jacket in size 3T and 4T at Wal-Mart, but they didn't have any shirts.Thanks!: You can buy those Transformers or Ben 10 clothing in Kmart,Big W, some chinese shops and OKorder.

Q:A speaker with resistance R is rated at 16Ω. What ratio of NP:NSof the transformer is required so that the stereo thinks that the speaker is 8: The impedance ratio is the square of the turns ratio, so to transform a load resistance of 16Ω to one of 8Ω you need a turns ratio of NP/NS sqrt(8/16) 0.707:1 This relationship arises as follows - In the ideal case, the flux in the transformer core can be taken to be the same in the primary and the secondary, so by Faraday's law of electromagnetic induction VP/NP VS/NS where VP and VS are primary and secondary induced voltages. For conservation of energy, the power in the secondary circuit must be the same as the power in the primary circuit (assuming no losses in the ideal case) , so (VP^2)/RP (VS^2)/RS, leading to - VP^2/VS^2 (NP/NS)^2 RP/RS Note that stereo systems are incapable of thought, so the question, as asked, is meaningless, or at best fanciful; the appropriate language to use is 'what transformer ratio is required to present a resistance of 8Ω at the primary terminals when a resistance of 16Ω is connected to the secondary ?'. This draws attention to the fact that the transformer/load combination will behave in the same way whatever it is connected to - the 'thoughts' of the stereo are irrelevant .

Q:I have a question can someone explain why transformers get hot in use and why must they not be allowed to get too hot: They get hot because like pretty much everything, they are not 100% efficient. When a transformer is powered on, even if there is no load on it there is something called iron losses - this is the amount of energy which is used to magentise the iron core of the transformer. These losses end up as heat. When the transformer has to start delivering power to the load, there are also copper losses to consider, this is because as more power flows through the windings, because the wire is not a perfect conductor, some heating of the copper winding occurs ( these losses are sometimes known as I squared R - meaning current x current x resistance) Iron losses are fixed, copper losses increase as the amount of power taken from the transformer increases. As for why you must not let them get to hot, from a functional point of view, above a certain temperature (varies according to insulation used) the enamel and other insulativbe properties will break down and you then get a shorted transfomer. Not helpful A second reason is for safety, some transformers will reach temperatures EXCEEDING the ignition temperature of flammable material - so in simple terms, a fire risk. Usually a transfomer has a thermal fuse fitted so that under overload conditions, it will rupture the fuse rather than get dangerously hot. Mark

Q:If I have a primary coil and secondary coil each with 400 turns that acts as a transformer, and the primary potential difference is 2.988 V, and the secondary potential difference is 0.0551 V.I need to find the efficiency. Ideally, it would be 100%, but this is the real world. So I did N(turns) and Volts and used the equation [N(p)V(s)/N(s)V(p) ] *100%p primarys secondaryNturns of coilV potential differenceI had an answer of 1.84% which seems awfully low. Help please. Thanks!: You are right. The efficiency is that low. Take a look at it another way: Pin Pout if 100% efficient. Since we know a 1:1 turns ratio will produce the same voltage from one side of the transformer to the other, the current produced on the secondary is extremely low to pull the voltage down to .0551V. It makes this transformer extremely inefficient! I can't even think of how you would design a transformer that was this inefficient. I think even a large OD iron nail with a lot of eddy currents at 7.5k Hz I believe would be more efficient. The next worst way I can think of how to produce an isolated output is with a TEC using the Seabeck effect that is about 6% efficient.

Q:The main transformer is chosen in principle: Transformer selection, you can refer to the following, but still according to the actual production needs! 1, the number of transformers to determine ???(1), the number of main transformer to determine the principle is to ensure the reliability of power supply. When one of the following conditions is met, two or more transformers shall be installed. ???①, there are a lot of first-class load and although the secondary load but need to set from the security (such as fire, etc.). ???②, when the seasonal load changes greatly. ???③, when the load is large. ???For large-scale hub substation, according to the specific circumstances of the project can be installed 2 to 4 main transformer. ???When installing multiple transformers, it is appropriate to group the transformer according to the characteristics and changes of the load in order to flexibly switch the corresponding transformer group. Transformers should be operated in the sorted manner. Transformer low-voltage outlet of the neutral and neutral ground wire should be laid separately. For the convenience of testing, in the ground circuit, close to the transformer to do a removable connection device. ???(2), the general three-level load or capacity is not too much power and lighting should be a load with only one transformer. ???(3), when any of the following circumstances, can be dedicated transformer ???①, when the lighting load is large or power and lighting using a common transformer seriously affect the lighting quality and lamp life, can be set for lighting special transformer. ???②, single single-phase load is large, should be set single-phase transformer. ???③, the impact of a larger load, seriously affect the power quality, can be set for shock load special transformer. ???④, when the seasonal load (such as air conditioning equipment, etc.) about the total load of the project 1/3 and above, it is appropriate to configure a dedicated transformer.

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