TX-0010 pure copper bar

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Loading Port:: China Main Port

Payment Terms:: TT OR LC

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Packaging & Delivery

Packaging Detail:	standard export seaworthy package ,suit for all kinds of transport,or as required
Delivery Detail:	7-15 days after receiving deposit

Specifications

pure copper bar
1.material:T1 T2 c2600
2.OD:3-800mm
3.length:as requirement
4.quality first,service

Product Description

Item	Copper bar ,copper rod ,Brass bar,brass rod
Material	C10100,C10200,C10300,C10400,C10500,C10700,C10800,C10910,C10920, C10930,C11000,C11300,C11400,C11500,C11600,C12000,C12200,C12300, C12500,C14200,C14420,C14500,C14510,C14520,C14530,C17200,C19200, C21000,C23000,C26000,C27000,C27400,C28000,C33000,C33200,C37000, C44300,C44400,C44500,C60800,C63020,C65500,C68700,C70400,C70620, C71000,C71500,C71520,C71640,C72200,etc
Standard	ASTMB152,B187,B133,B301,B196,B441,B465,JISH3250-2006, GB/T4423-2007,etc
Diameter	3mm~800mm
Length	5.8m,6m,or as required
Export to	Singapore,India,Iran,Indonesia,Ukraine,Spain,Korea,Thailand,Canada,USA, Ireland,Saudi Arabia,Viet Nam,England,Egypt,Oman,etc
Package	Standard export seaworthy package,suit for all kinds of transport,or as required.
Container Size	20ft GP:5898mm(Length)x2352mm(Width)x2393mm(High) 40ft GP:12032mm(Length)x2352mm(Width)x2393mm(High) 40ft HC:12032mm(Length)x2352mm(Width)x2698mm(High)
Price term	Ex-Work,FOB,,CFR,CIF
Application	Copper bar is widely used in boat building,War industry, Car industry and communication industry where the components need good wear proof and great corrosion resistance
Contact	If you have any question,please feel free to contact me .

Q: suposse that the thermal conductivity of copper is twice that of the aluminium y four times that of brass. Three metal rods, made of copper, aluminium and brass respectively, have 6 inches of lenght and 1inch of diameter.The rods are matched side by side of their ends, with the aluminium rod in the middle. The free ends of the copper and brass rods are at 100?C and 0?C respectively. Calculate the temperatures of equilibrium of the union between copper and aluminium rods, and of the aluminium and brass ones.: The heat conduction equation is: heat flux q - k * (dT/dx) The three rods (equal cross-section (R 0.5 inch), equal length (L 6 inches): - Copper: kc 4a - Aluminium: ka 2a - Brass: kb a - The heat transferred along each rod is the cross-sectional area (pi*(0.5)^2) multiplied by the heat flux. - Since heat is provided/taken out only at the end points (T_h 100 ?C, T_c 0 ?C), the heat transfer must be the same at each junction: nothing goes missing. - Since the cross-sectional areas are all the same, the heat-flux values must also be the same. - The heat flux depends on the temperature gradient over each bar: but since the length of each bar is the same, the temperature gradient depends only on the temperature drop over each bar: q -k * dT/dx -k * ΔT/L So if T(0) T_h at the left end of the copper rod T(L) temperature at the copper/aluminium junction T(2L) temperature at the aluminium/brass junction T(3L) T_c at the right end of the brass rod we conclude that if all the q's are equal, (eqn 1): kc * (T(L) - T(0)) ka * (T(2L) - T(L)) 4a * (T(L) - T(0)) 2a * (T(2L) - T(L)) 2*T(L) - 2*T(0) T(2L) - T(L) (eqn a): T(2L) 3*T(L) - 2*T(0) and (eqn 2): ka * (T(2L) - T(L)) kb * (T(3L) - T(2L) 2a * (T(2L) - T(L)) a * (T(3L) - T(2L) 2*T(2L) - 2*T(L) T(3L) - T(2L) (eqn b): 3*T(2L) T(3L) + 2*T(L) (eqn a) and (eqn b) imply: T(3L) + 2*T(L) 3*T(2L) 3*( 3*T(L) - 2*T(0)) 9*T(L) - 6*T(0) T(3L) + 6*T(0) 7*T(L) T(L) (T(3L) + 6*T(0))/7 and T(2L) 3*T(L) - 2*T(0) (3/7)*(T(3L) + 6*T(0)) - 2*T(0) (3/7)*T(3L) + ((18-14)/7)*T(0) (9*T(3L) + 4*T(0))/7 Therefore: T(0) T_h 100?C T(L) (T_c + 6*T_h)/7 (6/7)*100 85.7?C T(2L) (9*T_c +4*T_h)/7 (4/7)*100 57.1?C T(3L) T_c 0?C T(L) is the temperature of the copper/aluminium junction, T(2L) is the temperature of the aluminium/brass junction.

Q: I have a 150A Federal Pacific Stab-Lok breaker panel. I am looking to replace it because most of the breakers have gone bad and it is cheaper to replace it than replace every breaker. What is the best type for a residential home with some appliance use? I want 150-200Amps and at least 30 breaker slots. Cuttler-Hammer, Square D, GE?: They are all about the same I agree. I have installed thousands through the years as a contractor and cannot say one is so much better then the other. Copper bus bars do hold up better under heavier loads that would be one suggestion as what to look for. The second thing is to use a brand that has compatibility breakers (meaning one brand will fit many breaker brands) This may be a good thing for future use as far as needing breakers that will fit. My preferences are SQ D type QO and Cutler - Hammer.

Q: I am an electrical contractor, but nobody knows everything. I know how to use the NEC to properly size wires. Never had an inspector compliain out BARE (and unprotected) #4 being used for a 200 amp service. #4 is fairly robust, and hard to accidently damage. But what about a 125 amp service? The NEC requires #8, but dose the thiner #8 need the protection of a conduit? Is it required by code?Is this information in the NEC?THANKSCharlie: If the ground wire is in a spot where it might be hooked , pulled or caught on or by something, it would be advisable to put the ground wire thru some sort of conduit. I use #6 on all residential services, no matter what size the mains are. It's always better to bigger. Inspectors will never complain about ground wires that are bigger than code

Q: Electrical contacts, alkanes and the brass to black spot it: That depends on the platform, and some are not, but some things black platform, see you choose, verification approval, custodian bank, etc..

Q: I used some of the bars leak that works when mixed with antifreeze. It stop the smoke but the engine still runs bad and confirmed bubbles in the radiator while the engine was running. I know there is different types of engine block sealant. which is the best to use that will work the longest. I wont to know if the liquid glass type , copper type or ceramic type would be best to use.: Nicky, you have brought up two different issues and points. as a temporary fix till the head gasket is replaced a head gasket sealant or in correct term stop leak is used. bars leak is just such a product. I recommend on that point Allumaseal its a powder based product that you pour into the radiator and start and drive the car for at least an hour. the powder gets trapped in the leaking spots and clogs the spot for a while. now head gasket sealer, this is a product you coat the new head gasket with to insure a good tight seal when it is all installed. if the head gasket is a fiber type gasket like a thick cardboard I recommend coating the top and bottom of the gasket with a thick layer of copper coat. this comes in a spray or brush on and is applied just seconds before lowering the head in place. it seals well and helps keep the gasket in place as well. many newer head gaskets can be offered in a perma-seal design that require no additional sealers. I am a firm believer in adding insurance to any area's water passes through. a light film of sealer to those area's. One important point, if a head gasket is the question be sure, really sure that the head is not warped. this is when it is no longer totally flat and is caused by a combination of possible reasons. usually stretched head bolts and cylinder hydraulic lock from fluid entering the firing cylinder.

Q: How to connect between copper and copper: Press copper wire with wire ear, turn the hole on copper plate, and connect with screw. Wired ear and wire matching

Q: 1At what temperature of 0^C steel rod copper rod have length of 80.1cm and 99.9cm respectively. At what temperature will the 2 rods have the same length. Coefficients of linear expansion (per °C) copper rod----.000017 steel rod-------.000012 2.The length of a brass bar increase from 4.001m into 4.0030 m. find the final temperature of the bar if the initial temperature was 0 Celsius. Coefficients of linear expansion (per °C) brass----- .000019: 1) Copper: L Loc(1 + λc T) Steel: L Los(1 + λs T) At same length L: Loc(1 + λc T) Los(1 + λs T) T (Los - Loc)/(λcLoc - λsLos) (80.1 - 99.9)/(.000017x 99.9 - .000012x80.1) -26862°C The result is totally absurd (no such a temperature can exist), and there is no wonder because the difference in length is too big, and no change in temperature can compensate for it. 2) L Lo(1 + λ T), so T (L - Lo)/λ (4.0030 - 4.001)/.000019 105°C

Q: I‘m going to smith 1k bars of bronze. So to do that I need 1k tin and 1k copper. I have a mining level of 52 and currently using a rune pickaxe. How long should it take me to mine the 1k tin and 1k copper?: On the kick stand. You want the weight of the bike on the tire. Weight of the bike will increase pressure slightly.

Q: wood a high end designer be able to make some burglar bars on my home make me look like a movie star? do they really keep burglars and murdereers out your home: First of all locks and bars only keep honest people out of anything. Second if your house catches fire those bars could be your doom. and thirdly why would you live in a place where you need that kind of stuff to begin with. Its time to move.

Q: The mechanical properties of the copper bar test should be done the test sample: This GB should have standards, if you do tensile test, you will check the national standard of tensile experiments, bending experiments and stability experiments can be done, you can check the national standard.Pure hand, hope to adopt, thank you!

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