• Color Loop Inductor System 1
Color Loop Inductor

Color Loop Inductor

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Q:A series circuit consists of a 0.45 H inductor with internalresistance 6.0 ohms connected in series with a 8.0 ohm resistor, aswitch, and a 12 volt battery. Twenty milliseconds after the switch isclosed, how much energy is stored by the inductor?I understand that energy 1/2LI^2 Lmagnetic flux/I energy1/2 (magnetic flux)*Iand that’s as far as I can get. Any help?
The charging time constant T? L ? R (0.45 H) ? (14 ?) 32.1 msec ?мax (12 V) ? (14 ?) 0.857 Amps ???i (?мax) ? [1 ? e^ˉ(t ? T?)] ???i (0,857) ? [1 ? e^ˉ(0.020 ? 0.0321)] ???i 0.4 Amps ???????????????Energy (?) ? L ? i? ???????????????Energy (?) ? (0.45) ? (0.4)? ???????????????Energy 0.036 Joules
Q:A 100-turn, air-core inductor has an area of 200 square micro-meters and is 200 milli-meters long. What is its inductance?A. 12.6 micro-henrysB. 1.26 milli-henrysC. 12.6 milli-henrysD. 126 micro-henrys
Lmuo N^2 area/length where muo4 pi*10^(-7) and area is in meters squared and length is in meters. You can do the math.
Q:An inductor is formed by winding a coil on a limb of a ferromagnetic core. What would the core losses be in a coil-core assembly excited by a DC current? Explain why.
Core losses are a function of frequency raised to about 1.8. There is no core loss at DC.
Q:Current through an inductor is turned on at time t0, as shown in the figure. Vscos(200*pi*t). Calculate the energy delivered to the inductor at t21 ms.
At t0, switch closed and a advantage got here throughout the inductor. So it is sort of a Alternating current for a moment. That alternating current makes inductor to behave like in AC circuit. That affects cut down consistently after t+ time on the grounds that of dc voltage. There'll a opposing electromagnetic subject in the inductor due to sudden voltage. To be able to discontinue current to waft by means of the inductor
Q:how to calculate SRF of a inductor?
In electronics, capacitors and inductors have parasitic inductance and capacitance, respectively. For a capacitor, the inductance is primarily due to the physical dimensions including the leads. The lead inductance can be calculated using the equation Ldc 2L[ln(2L/r) - 0.75]nH where Ldc is the low-frequency or DC inductance in nano-henries, L is the wire length in cm, and r is the wire radius in cm.[1] Since a capacitor and inductor in series creates an oscillating circuit, all capacitors and inductors will oscillate when stimulated with a step impulse. The frequency of this oscillation is the self-resonant frequency (SRF). A capacitor or inductor behaves ideally only when its working frequency is well below the self-resonant frequency. As its working frequency increases, the effects of the parasitic inductance or capacitance became more pronounced until its self-resonant frequency, when the effective capacitance or inductance is zero since it is canceled by its counterpart. This number is commonly published for each capacitor or inductor by the manufacturer.
Q:A voltage of 100V RMS at 50Hz is connected to a 45ohm resistor in parallel with an inductance of 150mH. Calculate the inductor current.This is a question i have to work out, I just don't understand the formula for working out current through an inductor Vl di/dt, any help??
Inductive reactance magnitude under ac is X ω.L 2.π.50 100.π ohms With 100 v applied this would give a current in the inductor of i 100/X 1/π amps. Note: When V is sinusoidal (i.e. ac) V L.di/dt becomes v.sin(ωt) L.di/dt therefore di/dt V/L (v/L)sin(ωt) so that i -v/(ωL) s(ωt) or in terms of magnitudes i V/(ωL) ωL is the reactance of L. The resistor's current is irrelevant here.
Q:Explain the difference between the two quantities.
Impedance can have both resistive and either inductive or capacitive components (in electrical engineering-speak, we give the impedance as a complex number for a given frequency).
Q:a dc voltage source is connected to an inductor through a switch and then the switch is closed . at t 0 the inductor will behave as an open circuit . no current will flow and all the source voltage will be across the inductor. why is that? why the inductor has such behaviour. why no current can pass through the inductor at t0.
The voltage across an inductor is found from V L(di/dt) When the switch is turned on, the current i can't instantly increase, to do so di/dt would have to be infinite (∞), this would require the voltage across the inductor to be ∞. Therefore current can not change instantaneously in an inductor
Q:An inductor is connected to a sinusoidal voltage with an amplitude of 120v. A peak current 3.0A appears in the inductor.a) What is the maximum current if the frequency of the applied voltage is doubled?b) What is the inductive reactance at each of the two frequencies?I started it but can't calculate the frequency or know what formal to use to get max Currentthanks Jack
You do not need the actual frequencies to solve this problem. You can use the frequency ratios. Since the current is given as 3.0 Amps peak I will assume the 120 Volts is peak also. (b1) XL at original frequency .(707 x 120V) / (.707 x 3A) 40 Ohms XL at (2) x (original frequency) 2pi x 2f x L (b2) But 2pi and L are both constant therefore XL at 2f 80 Ohms (a) Maximum current when frequency is doubled V / XL 120V / 80 Ohm 1.5 Amps
Q:I meant the shock literally, it's one of the question I need to answer.
An ideal capacitor, when charged has a voltage built up in it. It searches for path to discharge. When a person gets in contact with it, its contacts are closed and hence closed path is formed through human body resulting in an electric shock. Where as in an inductor,its property is to oppose sudden change in current. But an inductor can not store the energy when no current is passing through it. So the severity of shock depends on the current flowing through inductor when connected in an electric circuit and in the same way in case of a capacitor severity depends on voltage rating of the capacitor. So severity of both cannot be compared.
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Location Shenzhen, Guangdong, China (Mainland)
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