• Low Frequency High Quality Coil/Inductor System 1
Low Frequency High Quality Coil/Inductor

Low Frequency High Quality Coil/Inductor

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Specifications

1.Radial Fixed Leaded Inductors with Inductance ranging from 0.30uH to 100mH.

2.ROHS compliance.

3.Good quality and low price

4.low loose

 

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Q:A current of 1.29 A in an inductor L results in a stored energy of 0.135 J. The current is then changed to 5.52 A in the opposite direction. Calculate the change in the stored energy.
It depends on the rate at which the current changes.
Q:an ideal current source is connected in series with an ideal inductor of 50 milliHenriesthe current source is not constant but a time varying sinusoid. the following formula describes the current in the units of Amperes : i(t) 10cos(500t)derive a formula for the voltage across the inductor, in the units of Volts, as a function of time.note that the units of Amperes per second time Henries yields Volts.I KNOW THIS IS A ODE PROBLEM, Im nor sure how to work the problem any help is welcome, thanks in advance.
You use the definition of inductance (L) V L*di/dt where V is the induced voltage, and di/dt is the rate of change of current in the inductor. i(t) 10 cos(500*t) di/dt -500*10*sin(500*t) V -25*sin(500*t) note that the current function is not a sinusoid but is a cos function.
Q:An RLC circuit has a 400 ohm resistance a 2.5 mH inductor and a capacitor. If the circuit is in resonance at 30kHz and is attached to a 20mVrms power supply, what is the power dissipated by the circuit?
At resonance +jXL -jXC, therefore Z R +jXL -jXC R 400 ohms, since the reactances canel out. The power is only disspiated in the 400 ohm resistor, so P V^2 / R P (0.020V)^2 / 400 P 1E-6 Watt P 1 microWatt ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ EXTRA CREDIT The capacitor value for resonance with the 2.5 mH inductor at the frequency of 30 KHz will be f 1 / (2 * pi * SQRT (L * C) ) 30E3 Hz 1 / (2 * 3.1415 * SQRT (2.5E-3 H * C) ) 2 * 3.1415 * SQRT (2.5E-3 H * C) 1 / 30E3 Hz SQRT (2.5E-3 H * C) 5.3052E-6 (2.5E-3 H * C) (5.3052E-6)^2 2.5E-3 H * C 28.1448E-12 C 11.2579E-9 F C 0.0112579 microFarads (uF) 11.2579 nanoFarads (nF) 11,257.9 picoFarads (pF)
Q:i am an engineer and i want to know what an inductor does because they look really intresting
Gary's answer is excellent, but it more layman's terms, essentially, while a capacitor's purpose is to store voltage, an inductor's purpose is to store current. At steady state (time infinity), an inductor acts like a short circuit.
Q:Here is the diagram
Just to supplement the first guys answer. at tinfinity, the circuit has reached steady state. In a steady state DC circuit, the inductors magnetic field is no longer changing so there is no induced emf. Therefore the inductor basically behaves as a short circuit so all the voltage Vb is across the resistor.
Q:An inductor is connected to an AC generator.As the generator's frequency is increased, what happens to the current in the inductor?The current increases.The current decreases.The current does not change.Don't just choose one, explain why you choose it.
The frequency of the generator is given via here equation, Frequency(velocity*form of poles)/a hundred and twenty So the two boost the fee or the form of poles to get bigger frequencies.
Q:A battery is connected in series with a 3.0 ohm resistor and a 12 mH inductor, the max current in the circuit is 150 mA. What is the time constant of this circuit, and what is the EMF of the battery?If the time constant (T) is equal to the time required to reach 63.2 % of the max current, I calculated it to be the time required to reach 0.0948 Amps. T (0.632)(0.00150 A) 0.0948 A. But this is as far as I got. The equation I found that I think I should use is I E/R (1-e ^(-t/T) Please help - thank you
The time constant is simply L/R. That's a standard result (Like RC is the time constant for a resistor/capacitor). Time constant 12x10^-3H / 3.0ohm 4 x10^-3s 4ms When the current is steady, the inductor - if it's perfect - behaves like a short-circuit - i.e. zero resistance. This is because the magnetic field inside it isn't changing so there is no induced emf. The toal circuit resistance is 3.0 ohms and the current is 150mA. So cell's emf IR 150x10^-3A x 3.0ohm 450x10^-3V 0.45V
Q:how does the energy gets stored in the inductor if we are connecting it to an rlc circuit either in parallel or in seriesi also wanted to ask about the phenomena of resonance ocuring in this circiut in details,i know that when the inductor has potential energy the capacitor doesnt have and vice versa,thats why its called electrical resonance,but i want someone to tell me the reason of this phenomena,an athountic answer please.thank u buddy
Energy is stored in the inductance as a magnetic field and at any time E (1/2)Li^2. In a series circuit the impedance is Z R + j(wL - 1/(wC)) ?Z? SQRT[R^2 + (wL - 1/(wC))^2] Resonance occurs when wL 1/wC w^2 LC w SQRT(LC) where w is angular frequency and j^2 -1
Q:Here is the question:Two ideal inductors (.10 H, .50 H) are connected in series to an ac voltage source with amplitude 5.0V and frequency 126 Hz.a) What are the peak voltages across each inductor?b) What is the peak current that flows in the circuit?I know that you use V IXL *L is subscript*.I don't know if you are supposed to use rms in the equation like Vrms Vpeak/1.4 (square root of 2).Any help would be greatly appreciated and showing me the work/equation you are using. I am just generally confused lt;. Thanks a lot.
The question ask for peak voltages and peak current. So I don`t think you have to worry about RMS values especially since the source voltage was not specified to be peak or RMS. The voltage across the .1H coil .1H / ( .1H + .5H ) x 5V .83V The voltage across the .5H coil .5H / ( .1H + .5H ) x 5V 4.17V Assuming the 5 volt ac source is sinusoidal then X of L (2 PI) x (frequency) x (inductance). The total impedance 6.28 x 126 x .6 475 ohm The current Voltage / impedance The circuit current 5V / 475 ohm 10.5 miliamps
Q:does it slow down the current or stops the current into the coil?
An inductor delays a change in current (so to speak). If an inductor is connected to a d.c. source through an open switch; at the instant the switch closes, full votage is applied across the inductor, but current does not flow due to a phenomon referred to as reverse electromotive force or reverse voltage. As a magnetic field builds in the inductor, current begins to flow, with the magnitude of current gradually increasing until the magnetic field builds completely. The inductor then acts as a short circuit. The time delay is a function of circuit resistance multiplied by inductance. At the instant the switch opens, the current in the inductor continues to flow until the field begins to collapse, at which point the current gradually reduces to zero.
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Location Shenzhen, Guangdong, China (Mainland)
Year Established 2006
Annual Output Value US$2.5 Million - US$5 Million
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