Immersible Pump, Solar Pumping System, Popular
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- 300000 unit/month
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DC Solar Pumping System can be applied to daily use (ground water), agricultural irrigation, forestry irrigation, desert control, pasture animal husbandry, water supply for islands, wastewater treatment engineering, and so on. Solar water pump System is dispensed with energy storing devices, and stores water instead of electricity. It improves the reliability of the device, at the same time, it lowers the construction and maintenance costs of the irrigation system dramatically.
In recent years, with the promotion of the utilization of new energy resources, Solar Pumping System is more and more used in municipal engineering, city centre squares, parks, tourist sites, resorts and hotels, the landscapes and fountain irrigation systems in the residential areas.
Technical Features
Optimization of Single Pump System
A single solar irrigation system consists of only one pump, a power -matched solar array and an inverter . The aim of optimization is to reduce the amount of PV modules as much as possible on the premise of filling the requirement of head and capacity. The rotational speed of pump is regulated according to the irradiation on the solar array; when the sunlight reaches its peak, the pump runs at the rated speed, and the output approaches the peak power of the solar array; when the sunlight is less abundant, the speed of pump varies bellow the range of the rated speed; when the speed as low as the capacity becomes zero, the solar pumping system stops working. So, there are big differences between solar irriation systems and traditional pumping systems in system design, and the system should be optimized according to the requirements of head, capacity, and local conditions of sunlight.
•Determine the optimal average daily operating time and the range of speed governing.
•Choose the optimal head and capacity of the pump.
•Determine the maximum power of PV modules, the best working voltage and method of connection.
Optimization of Multi-pump Systems：
There are several pumps in a multi-pump system. The pumps can be driven either by only one high-power inverter, or by several matching inverters. In the case of large capacity demand, the operation of the multi-pump system is more flexible. By switching solar arrays and pumps, all of the pumps run in MPPT mode when the sunlight is abundant, while some pumps will be shut down and all solar arrays supply power intensively for the rest running pumps when irradiation is weak. Based on the optimization of single pump system, the range of speed can be further optimized, and the photovoltaic(PV) pumping system always works with high efficiency.
Product Specifications
Model | Rated Power | Max. Flow | Max. Lift | Daily Water Supply | Outlet Dia. | Pump Dia. |
PSD600C | 600W | 4.5 m3/h | 30 m | 10 - 20 m3 | 1"1/4 | 4" |
PSD600H | 600W | 2 m3/h | 100 m | 5 - 10 m3 | 1"1/4 | 4" |
Solar Array Configuration
Max. Input Power | Max. Input Current | Max. Open Circuit Voltage | Recommended MPP Voltage |
1000W | 15A | 150VDC | 60 - 120VDC |
Recommended Design | Solar Panel | Connection | Total Power |
Configuration 1 | 190W / 35Vmp | 2 pcs x 2 strings | 760W |
Configuration 2 | 250W / 30Vmp | 3 pcs x 1 string | 750 |
Performance Curve
- Q:How can I be sure the water pump is the problem before spending $ on repairs. 97 civic overheating.?
- Check the thermostat, if that's the problem you'll be looking at a 5 or 10 dollar bill if you do the work yourself.
- Q:Could this be a result of a bad water pump.
- Possible head gasket or warped head. The water is getting out to the water jacket and into the top of the piston. Some water coming out of the exhuast is normal. It would not be a water pump.
- Q:I was wonder if there is a water pump in the out drive, my boat is overheating we are think it could have something to do with the water pump
- The water pump is located in the outdrive. You should see a screen area on the lower end where the pump is loicated. I would guess the impeller needs to be replaced. You should stop running the engine 'till it is fixed.
- Q:Where can I get a water pump housing for a 1987 Dodge Dakota, A junk yard?
- Besides finding one at a junk yard you could try a Dodge dealer too. Your generation Dakota was made by Dodge until 1996 and if your '87 Dakota has an engine that happens to share a compatible water pump housing design with any '96 model's pump design then you might have some luck. Manufacturers must make replacement parts for their vehicles for 15 years after the model is released - meaning the 1996 Dakota parts should still be available at Dodge dealers. Good luck.
- Q:hooking up a water pump to my tank and need a power supply
- can you be a bit more descriptive have you a pump but no way of powering it if so what type of pump what voltage where is pump
- Q:Ok, if my intake manifold wasnt mess up and it could be my water pump would I still smell a syrup odor and WHY would it be leaking green antifreeze? especially when the antifreeze I use is orange?
- Okay, I take it you've added orange anti-freeze to your cooling system. If the system originally had green in it- you just did something really expensive. The two kinds of anti-freeze don't get along. Mixing the two together then getting them hot makes them into a gel. SO, what you get to do now is a complete system flush(by taking the whole system apart-heater core, radiator, hoses, heater valve, the works) use some sort of flush product, and get a large tub. Then, after you've gotten an amount of it out, reassemble the whole thing, and with the engine cool-put some more flush agent in it. Then, take a garden hose- and fill the system. once it's full open the petcock and continue to use the garden hose to flush the system until the water comes out clear. Now, close up the system and run the car for a bit and check the bottom of the water pump to see if the weep hole is leaking. There is on just below the pump shaft. If that's leaking, the pump is shot. If that's not, then there could be a cracked head, or a bad head gasket. A few things to check for that are- if when the car is running, are there air bubbles coming out of the radiator(with the cap open)? Does it seem to overheat easily? Have you run the engine hot?
- Q:A water pump that consume 2kW of electric power when operating is claimedto take in water from a lake and pump it to a pool whose free surface is 30 m above the free surface of the lake at a rate of 50 L/s. Determine if this claim is reasonable.You have to show the minimum power required is 14.7 kWand i can't get it.
- A liter of water mas a mass of 1Kg. How much work must be done to raise 50 Kg of water through a height of 30 m? You can say: Work done (W) = potential energy gained (mgh), Or you can say that Work done is the weight force (mg) * the distance moved against the force (h) Either way, W = m * g * h where m is the mass; g is the acceleration due to gravity {9.8 m/s?}; h is the height W = 50 * 9.8 * 30 = 14700 J If you need to do that amount of work in one second, that's a rate of working of 14700 J/s A joule/second is a watt. Minimum power required = 14700 W = 14.7 kW
- Q:or how do i remove the water pump?please xplain
- You need to get the large nut lose. It holds the fan/fan clutch to the water pump shaft. After you get that off it's all down hill from there.A large adjustable wrench will work on the nut but you will need to keep pump from turning to loosen it. I think it may be left hand thread. It is not on real tight. The book will help on this one.
- Q:can stress from to much weight cause the engine to get hot and cause your water pump to leak out the weep hole? and what else causes it to leak?
- There is a number of reasons for your water pump to leak. One could be its tear and wear due to years of used. Second is due to successive overheating. Weight cant cause water pump breakdown, as long as it does not overheats. To much pressure in the cooling system cause its breakdown. Hope this might help!
- Q:Water is pumped out of a holding tank at a rate of 6-6e^(-.09t) liters/minute, where t is in minutes since the pump is started. If the holding tank contains 1000 liters of water when the pump is started, how much water does it hold one hour later??Round your answer to one decimal place.
- Let V(t) be the volume of water (in Liters) in the tank after t minutes. We are given that V(0) = 1000, and we wish to find V(60). We are also given the rate of change of the volume: V'(t) = -[6 - 6e^(-0.09t)]. Note that a negative sign needs to be placed because the rate represents water leaving the tank, i.e., being pumped out of the tank. By the Fundamental Theorem of Calculus, Integral (0 to 60) V'(t) dt = V(60) - V(0), so that V(60) = V(0) + Integral (0 to 60) V'(t) dt V(60) = V(0) + Integral (0 to 60) -[6 - 6e^(-0.09t)] dt V(60) = V(0) + Integral (0 to 60) [-6 + 6e^(-0.09t)] dt V(60) = V(0) + [-6t + (6/-0.09)e^(-0.09t)] (Evaluated at t = 60 - Evaluated at t = 0] V(60) = V(0) + [-6(60) + (6/-0.09)e^(-0.09(60))] - [-6(0) + (6/-0.09)e^(-0.09(0))] V(60) = 1000 + [-360 - (200/3)e^(-5.4)] - [0 - (200/3)] V(60) = 1000 - 360 + 200/3[1 - e^(-5.4)] V(60) = 640 + 200/3[1 - e^(-5.4)] V(60) = approx. 706.4 Therefore, approximately 706.4 L of water occupy the holding tank 1 hour after the pump is started.
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Immersible Pump, Solar Pumping System, Popular
- Ref Price:
-
- Loading Port:
- Shekou
- Payment Terms:
- TT or LC
- Min Order Qty:
- 20 unit
- Supply Capability:
- 300000 unit/month
OKorder Service Pledge
OKorder Financial Service
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