Selling Carbon black use N220 n330 n550 n660

Selling Carbon black use N220 n330 n550 n660 System 1

Selling Carbon black use N220 n330 n550 n660 System 2

Selling Carbon black use N220 n330 n550 n660 System 3

Selling Carbon black use N220 n330 n550 n660

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Loading Port:: Qingdao

Payment Terms:: TT OR LC

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Supply Capability:: 20000 m.t./month

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Selling Carbon black use N220 n330 n550 n660 /1333-86-4
1.competitive price
2.high quality
3.wide specifications

Selling Carbon black use N220 n330 n550 n660 /1333-86-4

1.Basic information:

1. Carbon Black N220, N326, N330, N375, N539, N550, N660, N774 also available;

2. For more details(Carbon Black MSDS), please do not hesitate to contact us.

3.We holding the princple of " Profession, Speedy, Sincerity" with your questions and inquiries.

So if you are interested in any product we are supplying or we could supply, your inquiry will always meet our prompt reply!

2.Specification:

Name ,Parameter	Carbon black N220	Carbon black N330	Carbon black N550	Carbon black N660
Loding Absorption Number(g/Kg)	114-128	77-87	39-47	32-40
Absorption Value of DBP (10-5m3/Kg)	109-119	97-107	116-126	85-95
Absorption Value of compressing sample DBP (10-5m3/Kg)	95-105	83-93	83-93	71-79
Adsorptive Specific Surface Area of CATB ( 103m2/Kg)	106-116	77-87	38-46	32-40
Adsorptive Specific Surface Area of Nitrogen (103m2/Kg)	114-124	78-88	38-46	30-40
Tinting Strength %	110-120	98-108	----	----
Heating Loss	2.5%max	2.5%max	1.5%max	1.5%max
Ash Content	0.5%max	0.5%max	0.5%max	0.5%max
Tensile Strength	-0.5mpa min	-0.5mpa min	-0.5mpa min	-0.5mpa min
300% Extending Stress	-1.5±1.0 mpa	-1.0±1.0 mpa	-1.0±1.0 mpa	-2.5±1.0 mpa
45μm Sieve Residue	0.10% max	0.10% max	0.10% max	0.10% max

Q: In the chemical calculation, the quality of the catalyst should not be counted before and after the reaction: Half is not easy to save trouble

Q: Chemical production of iodine and magnesium with water as catalyst!: In the 250mL three bottles were equipped with spherical condenser and constant pressure dropping funnel, in the condensate tube connected to the anhydrous calcium chloride drying tube. The flask was placed with 1.5 g of magnesium chip and a small tablet of iodine, 10 g of bromobenzene and 30 mL of anhydrous ether were mixed in a constant pressure dropping funnel. First 1/4 of the mixture into the flask, a few minutes later see the magnesium surface of the bubble generated, the solution was slightly cloudy, iodine color began to disappear. If no reaction occurs, use a hot water bath. After the start of the reaction, stir, slowly dropping the remaining bromophene ether solution, dropping the rate to keep the solution was slightly boiling state, after adding, in the water bath to continue reflow 0.5h, magnesium tablets full effect.

Q: Could you please explain it, i know they increase reaction rates but how?: A catalyst provides an alternative route for the reaction, (maybe more steps than previously), but each step having a lower activation energy than the original uncatalysed reaction. This means that although there will be the same number of collisions per second (if the reaction is performed at the same temperature as before), a greater fraction of those collisions will result in a reaction - so there will be more reactions per second. In the case of a heterogeneous catalyst - e.g. a solid surface the change is that the first step is a bond to the surface which waekens some of the bonds in the reactants - again making a greater fraction of reactions result in reaction.

Q: Can manganese dioxide do any catalyst for chemical reactions?: the catalyst does not participate in the reaction, such as platinum - rhodium alloy network, nitrogen and hydrogen reaction to produce ammonia. Platinum-rhodium alloy network in the process of providing electrons (or similar effects, the specific is not clear, but does not react itself), before and after the reaction of platinum - rhodium alloy mesh shape has not changed.

Q: explain how a catalyst can affect the rate of reaction but not be in the overall equation.?: Catalysts act to increase the rate of reaction, for example by providing an alternative reaction pathway which lowers the activation energy of the reaction i.e. increasing the likelihood of successful collisions between the reactants. However, they are not used up during the course of the reaction, and at the end you have exactly the same mass of catalyst as you started with, unlike the reactant(s), which will be used up to form product(s). So, the overall equation of the reaction does not include the catalyst because it only needs to show the substances which are used up or formed during the course of the reaction i.e. the reactants and products.

Q: Will the catalyst change in the chemical reaction?: In fact, there are two kinds of catalyst mechanism, one is not a chemical reaction, the reaction did not occur throughout the chemical reaction, the catalyst did not change; one is involved in the reaction process, but the final production of the catalyst, which The class reaction generally occurs in a stepwise chemical reaction.

Q: I was hoping to buy a land rover lr4 or lr2, but with the lr4 having gas mileage in the mid teens, i wanted to know if there is a way to improve it. I dont drive on the highway too much. I'd like to know if there is anything else to improve mileage too. I drive a lot of people around for functions, family, and others and I looked at other suvs but those two looked the best.: Fuel Catalyst

Q: the process of which the heterogeneous catalyst work in vehicles. a step by step instruction in how they work. :): The Reduction Catalyst The reduction catalyst is the first stage of the catalytic converter. It uses platinum and rhodium to help reduce the NOx emissions. When an NO or NO2 molecule contacts the catalyst, the catalyst rips the nitrogen atom out of the molecule and holds on to it, freeing the oxygen in the form of O2. The nitrogen atoms bond with other nitrogen atoms that are also stuck to the catalyst, forming N2. For example: 2NO =N2 + O2 or 2NO2 =N2 + 2O2 The Oxidization Catalyst The oxidation catalyst is the second stage of the catalytic converter. It reduces the unburned hydrocarbons and carbon monoxide by burning (oxidizing) them over a platinum and palladium catalyst. This catalyst aids the reaction of the CO and hydrocarbons with the remaining oxygen in the exhaust gas. For example: 2CO + O2 =2CO2

Q: Just something I've always wondered about...: transition okorder /... for ex-- X (one reactant) + catalyst(transition element) ------X.catalyst(intermediate unstable compound) X.catalyst + Y (other reactant) --------XY(product) + catalyst how the change in oxidation state of transition elements helps the reacton through the formation of intermediates may be seen from reaction in between SO2 and O2 to form SO3 in presence of V2O5 ... V2O5 + SO2 ------V2O4 + SO3 2V2O4 + O2 ------2V2O5 in the above reaction vanadium changes its oxidation state from +5 to +4 and again to +5.. another example is reaction in between iodide and persulphate ions in presence of Fe(III) as catalyst... 2I(-) + S2O8(2-) ---------I2 + 2SO4(2-) (Fe(III) is present as catalyst) the reaction is believed to take place as follows: 2Fe(3+) + 2I(-) ------2Fe(2+) + I2 2Fe(2+) + S2O8(2-) ------2Fe(3+) + 2SO4(2-) (3)in number of cases transition elements provide a suitable large surface area with free valencies on which reactants are absorbed ...as a result concentration of reactants on surface of catalysts increases..hence rate of reaction increases...this is known as adsorption theory.... according to adsorption theory : there are free valencies on surface of solid transition metals because of the incomplete d-subshelll.. so the mechanism of catalysis involve followin five steps: (1) diffusion of reactant molecules towards surface of catalyst... (2) adsorption of reactant molecules on surface of catalyst by forming loose bonds with catalyst due to free valencies... (3)occurence of chemical reactions between reactant and catalyst forming an intermediate.. (4)desorption of product molecules from surface due to its lack of affinity for the catalyst surface thereby making the surface free for fresh adsorption of reactant molecules... (5)diffusion of product molecules away from surface of catalyst...

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